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Chapter 3: Derivatives

249 problems · 41 figures

Checkpoint 3.1 §3.1 source ↗

Find the slope of the line tangent to the graph of f(x)=x at x=4.

Answer

1 4

Checkpoint 3.2 §3.1 source ↗

For f(x)=x2, use a table to estimate f′(3) using Equation 3.6.

Answer

6

Checkpoint 3.3 §3.1 source ↗

For f(x)= x2+ 3x+ 2, find f′(1).

Answer

f ′ ( 1 ) = 5

Checkpoint 3.4 §3.1 source ↗

A rock is dropped from a height of 64 feet. Its height above ground at time t seconds later is given by s(t)= −16t2+ 64, 0≤t≤2. Find its instantaneous velocity 1 second after it is dropped, using Equation 3.5.

Answer

−32 ft/s

Checkpoint 3.5 §3.1 source ↗

A coffee shop determines that the daily profit on scones obtained by charging s dollars per scone is P(s)= −20s2+ 150s− 10. The coffee shop currently charges $3.25 per scone. Find P′(3.25), the rate of change of profit when the price is $3.25 and decide whether or not the coffee shop should consider raising or lowering its prices on scones.

Answer

P′(3.25)= 20> 0; raise prices

3-1 §3.1 source ↗

For the following exercises, use Equation 3.1 to find the slope of the secant line between the values x1 and x2 for each function y=f(x).

f(x)= 4x+ 7; x 1 = 2, x 2 = 5

Answer

4

3-3 §3.1 source ↗

For the following exercises, use Equation 3.1 to find the slope of the secant line between the values x1 and x2 for each function y=f(x).

f(x)= x 2 + 2x+ 1; x 1 = 3, x 2 = 3.5

Answer

8.5

3-5 §3.1 source ↗

For the following exercises, use Equation 3.1 to find the slope of the secant line between the values x1 and x2 for each function y=f(x).

f(x)= 4 3 x − 1 ; x 1 = 1, x 2 = 3

Answer

− 3 4

3-7 §3.1 source ↗

For the following exercises, use Equation 3.1 to find the slope of the secant line between the values x1 and x2 for each function y=f(x).

f(x)= x ; x 1 = 1, x 2 = 16

Answer

0.2

3-9 §3.1 source ↗

For the following exercises, use Equation 3.1 to find the slope of the secant line between the values x1 and x2 for each function y=f(x).

f(x)= x 1 / 3 + 1; x 1 = 0, x 2 = 8

Answer

0.25

3-11 §3.1 source ↗

For the following functions,

f(x)= 3− 4x, a= 2

Answer

a. −4 b. y=3−4x

3-13 §3.1 source ↗

For the following functions,

f(x)= x 2 + x, a= 1

Answer

a. 3 b. y=3x−1

3-15 §3.1 source ↗

For the following functions,

f ( x ) = 7 x , a = 3

Answer

a. −79 b. y=−79x+143

3-17 §3.1 source ↗

For the following functions,

f(x)= 2− 3 x 2 , a= −2

Answer

a. 12 b. y=12x+14

3-19 §3.1 source ↗

For the following functions,

f(x)= 2 x + 3 , a= −4

Answer

a. −2 b. y=−2x−10

3-21 §3.1 source ↗

For the following functions y=f(x), find f′(a) using Equation 3.5.

f(x)= 5x+ 4, a= −1

Answer

5

3-23 §3.1 source ↗

For the following functions y=f(x), find f′(a) using Equation 3.5.

f(x)= x 2 + 9x, a= 2

Answer

13

3-25 §3.1 source ↗

For the following functions y=f(x), find f′(a) using Equation 3.5.

f ( x ) = x , a = 4

Answer

1 4

3-27 §3.1 source ↗

For the following functions y=f(x), find f′(a) using Equation 3.5.

f ( x ) = 1 x , a = 2

Answer

− 1 4

3-29 §3.1 source ↗

For the following functions y=f(x), find f′(a) using Equation 3.5.

f(x)= 1 x 3 , a= 1

Answer

−3

3-31 §3.1 source ↗

For the following exercises, given the function y=f(x),

[T] f(x)= x2+ 3x+ 4, P(1,8) (Round to 6 decimal places.)

x Slope mPQ x Slope mPQ
1.1 (i) 0.9 (vii)
1.01 (ii) 0.99 (viii)
1.001 (iii) 0.999 (ix)
1.0001 (iv) 0.9999 (x)
1.00001 (v) 0.99999 (xi)
1.000001 (vi) 0.999999 (xii)

Answer

a. (i)5.100000, (ii)5.010000, (iii)5.001000, (iv)5.000100, (v)5.000010, (vi)5.000001, (vii)4.900000, (viii)4.990000, (ix)4.999000, (x)4.999900, (xi)4.999990, (x)4.999999 b. mtan=5 c. y=5x+3

3-33 §3.1 source ↗

For the following exercises, given the function y=f(x),

[T] f(x)= 10e0.5x, P(0,10) (Round to 4 decimal places.)

x Slope mPQ
−0.1 (i)
−0.01 (ii)
−0.001 (iii)
−0.0001 (iv)
−0.00001 (v)
−0.000001 (vi)

Answer

a. (i)4.8771, (ii)4.9875(iii)4.9988, (iv)4.9999, (v)4.9999, (vi)4.9999 b. mtan=5 c. y=5x+10

3-35 §3.1 source ↗

[T] For the following position functions y=s(t), an object is moving along a straight line, where t is in seconds and s is in meters. Find

s ( t ) = 1 3 t + 5

Answer

a. 13; b. (i)0.3– m/s, (ii)0.3– m/s, (iii)0.3– m/s, (iv)0.3– m/s; c. 0.3–=13 m/s

3-37 §3.1 source ↗

[T] For the following position functions y=s(t), an object is moving along a straight line, where t is in seconds and s is in meters. Find

s ( t ) = 2 t 3 + 3

Answer

a. 2(h2+6h+12); b. (i)25.22 m/s, (ii)24.12 m/s, (iii)24.01 m/s, (iv)24 m/s; c. 24 m/s

3-39 §3.1 source ↗

[T] For the following position functions y=s(t), an object is moving along a straight line, where t is in seconds and s is in meters. Find

Use the following graph to evaluate a. f′(1) and b. f′(6).

This graph shows two connected line segments: one going from (1, 0) to (4, 6) and the other going from (4, 6) to (8, 8).

Answer

a. 1.25; b. 0.5

3-41 §3.1 source ↗

For the following exercises, use the limit definition of derivative to show that the derivative does not exist at x=a for each of the given functions.

f(x)= x 1 / 3 , x= 0

Answer

lim x → 0 − x 1 / 3 − 0 x − 0 = lim x → 0 − 1 x 2 / 3 = ∞

3-43 §3.1 source ↗

For the following exercises, use the limit definition of derivative to show that the derivative does not exist at x=a for each of the given functions.

f ( x ) = { 1 , x < 1 x , x ≥ 1 , x = 1

Answer

lim x → 1 − 1 − 1 x − 1 = 0≠1= lim x → 1 + x − 1 x − 1

3-45 §3.1 source ↗

For the following exercises, use the limit definition of derivative to show that the derivative does not exist at x=a for each of the given functions.

[T] The position in feet of a race car along a straight track after t seconds is modeled by the function s(t)= 8t2− 116t3.

a. Find the average velocity of the vehicle over the following time intervals to four decimal places:

i. [4, 4.1]

ii. [4, 4.01]

iii. [4, 4.001]

iv. [4, 4.0001]

b. Use a. to draw a conclusion about the instantaneous velocity of the vehicle at t=4 seconds.

Answer

a. (i)61.7244 ft/s, (ii)61.0725 ft/s (iii)61.0072 ft/s (iv)61.0007 ft/s b. At 4 seconds the race car is traveling at a rate/velocity of 61 ft/s.

3-47 §3.1 source ↗

For the following exercises, use the limit definition of derivative to show that the derivative does not exist at x=a for each of the given functions.

Two vehicles start out traveling side by side along a straight road. Their position functions, shown in the following graph, are given by s=f(t) and s=g(t), where s is measured in feet and t is measured in seconds.

Two functions s = g(t) and s = f(t) are graphed. The first function s = g(t) starts at (0, 0) and arcs upward through roughly (2, 1) to (4, 4). The second function s = f(t) is a straight line passing through (0, 0) and (4, 4).

a. Which vehicle has traveled farther at t=2 seconds?

b. What is the approximate velocity of each vehicle at t=3 seconds?

c. Which vehicle is traveling faster at t=4 seconds?

d. What is true about the positions of the vehicles at t=4 seconds?

Answer

a. The vehicle represented by f(t), because it has traveled 2 feet, whereas g(t) has traveled 1 foot. b. The velocity of f(t) is constant at 1 ft/s, while the velocity of g(t) is approximately 2 ft/s. c. The vehicle represented by g(t), with a velocity of approximately 4 ft/s. d. Both have traveled 4 feet in 4 seconds.

3-49 §3.1 source ↗

For the following exercises, use the limit definition of derivative to show that the derivative does not exist at x=a for each of the given functions.

[T] For the function f(x)= x3− 2x2− 11x+ 12, do the following.

a. Use a graphing calculator to graph f in an appropriate viewing window.

b. Use the ZOOM feature on the calculator to approximate the two values of x=a for which mtan= f′(a)= 0.

Answer

a.

The function starts in the third quadrant, passes through the x axis at x = −3, increases to a maximum around y = 20, decreases and passes through the x axis at x = 1, continues decreasing to a minimum around y = −13, and then increases through the x axis at x = 4, after which it continues increasing.


b. a≈ − 1.361, 2.694

3-51 §3.1 source ↗

For the following exercises, use the limit definition of derivative to show that the derivative does not exist at x=a for each of the given functions.

Suppose that N(x) computes the number of gallons of gas used by a vehicle traveling x miles. Suppose the vehicle gets 30 mpg.

a. Find a mathematical expression for N(x).

b. What is N(100)? Explain the physical meaning.

c. What is N′(100)? Explain the physical meaning.

Answer

a. N(x)=x30 b. ∼3.3 gallons. When the vehicle travels 100 miles, it has used 3.3 gallons of gas. c. 130. The rate of gas consumption in gallons per mile that the vehicle is achieving after having traveled 100 miles.

3-53 §3.1 source ↗

For the following exercises, use the limit definition of derivative to show that the derivative does not exist at x=a for each of the given functions.

[T] For the function f(x)= x2x2+1, do the following.

a. Use a graphing calculator to graph f in an appropriate viewing window.

b. Use the nDeriv function on a graphing calculator to find f′(−4), f′(−2), f′(2), and f′(4).

Answer

a.

The function starts in the second quadrant and gently decreases, touches the origin, and then it increases gently.


b. −0.028, −0.16, 0.16, 0.028

Checkpoint 3.6 §3.2 source ↗

Find the derivative of f(x)=x2.

Answer

f ′ ( x ) = 2 x

Checkpoint 3.7 §3.2 source ↗

Sketch the graph of f(x)=x2−4. On what interval is the graph of f′(x) above the x-axis?

Answer

( 0 , + ∞ )

Checkpoint 3.8 §3.2 source ↗

Find values of a and b that make f(x)={ax+bifx<3x2ifx≥3 both continuous and differentiable at 3.

Answer

a=6 and b=−9

Checkpoint 3.9 §3.2 source ↗

Find f″(x) for f(x)=x2.

Answer

f ″ ( x ) = 2

Checkpoint 3.10 §3.2 source ↗

For s(t)=t3, find a(t).

Answer

a ( t ) = 6 t

3-55 §3.2 source ↗

For the following exercises, use the definition of a derivative to find f′(x).

f ( x ) = 2 − 3 x

Answer

−3

3-57 §3.2 source ↗

For the following exercises, use the definition of a derivative to find f′(x).

f ( x ) = 4 x 2

Answer

8 x

3-59 §3.2 source ↗

For the following exercises, use the definition of a derivative to find f′(x).

f ( x ) = 2 x

Answer

1 2 x

3-61 §3.2 source ↗

For the following exercises, use the definition of a derivative to find f′(x).

f ( x ) = 9 x

Answer

−9 x 2

3-63 §3.2 source ↗

For the following exercises, use the definition of a derivative to find f′(x).

f ( x ) = 1 x

Answer

−1 2 x 3 / 2

3-65 §3.2 source ↗

For the following exercises, use the graph of y=f(x) to sketch the graph of its derivative f′(x).

The function f(x) starts at (−1.5, 20) and decreases to pass through (0, 10), where it appears to have a derivative of 0. Then it further decreases, passing through (1.7, 0) and achieving a minimum at (3, −17), at which point it increases rapidly through (3.8, 0) to (4, 20).

Answer


The function starts in the third quadrant and increases to touch the origin, then decreases to a minimum at (2, −16), before increasing through the x axis at x = 3, after which it continues increasing.

3-67 §3.2 source ↗

For the following exercises, use the graph of y=f(x) to sketch the graph of its derivative f′(x).

The function f(x) starts at (−3, −1) and increases to pass through (−1.5, 0) and achieve a local minimum at (1, 0). Then, it decreases and passes through (1.5, 0) and continues decreasing to (3, −1).

Answer


The function starts at (−3, 0), increases to a maximum at (−1.5, 1), decreases through the origin and to a minimum at (1.5, −1), and then increases to the x axis at x = 3.

3-69 §3.2 source ↗

For the following exercises, the given limit represents the derivative of a function y=f(x) at x=a. Find f(x) and a.

lim h → 0 [ 3 ( 2 + h ) 2 + 2 ] − 14 h

Answer

f(x)= 3 x 2 + 2, a= 2

3-71 §3.2 source ↗

For the following exercises, the given limit represents the derivative of a function y=f(x) at x=a. Find f(x) and a.

lim h → 0 ( 2 + h ) 4 − 16 h

Answer

f ( x ) = x 4 , a = 2

3-73 §3.2 source ↗

For the following exercises, the given limit represents the derivative of a function y=f(x) at x=a. Find f(x) and a.

lim h → 0 e h − 1 h

Answer

f ( x ) = e x , a = 0

3-75 §3.2 source ↗

For the following functions,

f ( x ) = { 3 , x < 1 3 x , x ≥ 1

Answer

a.

The function is linear at y = 3 until it reaches (1, 3), at which point it increases as a line with slope 3.


b. limh→0−f(1+h)−f(1)h= limh→0−3−3h= 0
limh→0+f(1+h)−f(1)h= limh→0+3(1+h)−3(1)h= limh→0+3hh= 3
limh→0−f(1+h)−f(1)h≠limh→0+f(1+h)−f(1)h, so limh→0f(1+h)−f(1)h does not exist.

3-77 §3.2 source ↗

For the following functions,

f ( x ) = { 2 x , x ≤ 1 2 x , x > 1

Answer

a.

The function starts in the third quadrant as a straight line and passes through the origin with slope 2; then at (1, 2) it decreases convexly as 2/x.


b. limh→0−f(1+h)−f(1)h= limh→0−2(1+h)−2h= limh→0−2hh= limh→0−2= 2
limh→0+f(1+h)−f(1)h=limh→0+21+h−21h=limh→0+2−2(1+h)1+hh=limh→0+−2hh(1+h)=limh→0+−21+h=−2
limh→0−f(1+h)−f(1)h≠limh→0+f(1+h)−f(1)h, so limh→0f(1+h)−f(1)h does not exist.

3-79 §3.2 source ↗

For the following graphs,

The function starts at (−3, −1) and increases to and stops at a local maximum at (−1, 3) inclusive. Then it starts again at (−1, 1) before increasing quickly to and stopping at a local maximum (0, 4) inclusive. Then it starts again at (0, 3) and decreases linearly to (1, 1), at which point there is a discontinuity and the value of this function at x = 1 is 2. The function continues from (1, 1) and increases linearly to (2, 3.5) before decreasing linearly to (3, 2).

Answer

a. x=1, b. x=2

3-81 §3.2 source ↗

For the following functions, use f″(x)= limh→0f′(x+h)−f′(x)h to find f″(x).

f ( x ) = 2 − 3 x

Answer

0

3-83 §3.2 source ↗

For the following functions, use f″(x)= limh→0f′(x+h)−f′(x)h to find f″(x).

f ( x ) = x + 1 x

Answer

2 x 3

3-85 §3.2 source ↗

For the following exercises, use a calculator to graph f(x). Determine the function f′(x), then use a calculator to graph f′(x).

[T] f(x)= 3x2+ 2x+ 4.

Answer

f′(x)=6x+2

The function f(x) is graphed as an upward facing parabola with y intercept 4. The function f’(x) is graphed as a straight line with y intercept 2 and slope 6.

3-87 §3.2 source ↗

For the following exercises, use a calculator to graph f(x). Determine the function f′(x), then use a calculator to graph f′(x).

[T] f(x)=12x

Answer

f′(x)= − 1(2x)3/2

The function f(x) is in the first quadrant and has asymptotes at x = 0 and y = 0. The function f’(x) is in the fourth quadrant and has asymptotes at x = 0 and y = 0.

3-89 §3.2 source ↗

For the following exercises, use a calculator to graph f(x). Determine the function f′(x), then use a calculator to graph f′(x).

[T] f(x)=x3+1

Answer

f′(x)=3x2

The function f(x) starts is the graph of the cubic function shifted up by 1. The function f’(x) is the graph of a parabola that is slightly steeper than the normal squared function.

3-91 §3.2 source ↗

For the following exercises, describe what the two expressions represent in terms of each of the given situations. Be sure to include units.

C(x) denotes the total amount of money (in thousands of dollars) spent on concessions by x customers at an amusement park.

Answer

a. Average rate at which customers spent on concessions in thousands per customer. b. Rate (in thousands per customer) at which x customers spent money on concessions in thousands per customer.

3-93 §3.2 source ↗

For the following exercises, describe what the two expressions represent in terms of each of the given situations. Be sure to include units.

g(x) denotes the grade (in percentage points) received on a test, given x hours of studying.

Answer

a. Average grade received on the test with an average study time between two values. b. Rate (in percentage points per hour) at which the grade on the test increased or decreased for a given average study time of x hours.

3-95 §3.2 source ↗

For the following exercises, describe what the two expressions represent in terms of each of the given situations. Be sure to include units.

p(x) denotes atmospheric pressure in Torrs at an altitude of x feet.

Answer

a. Average change of atmospheric pressure between two different altitudes. b. Rate (torr per foot) at which atmospheric pressure is increasing or decreasing at x feet.

3-97 §3.2 source ↗

For the following exercises, describe what the two expressions represent in terms of each of the given situations. Be sure to include units.

Suppose temperature T in degrees Fahrenheit at a height x in feet above the ground is given by y=T(x).

a. Give a physical interpretation, with units, of T′(x).

b. If we know that T′(1000)= −0.1, explain the physical meaning.

Answer

a. The rate (in degrees per foot) at which temperature is increasing or decreasing for a given height x. b. The rate of change of temperature as altitude changes at 1000 feet is −0.1 degrees per foot.

3-99 §3.2 source ↗

For the following exercises, describe what the two expressions represent in terms of each of the given situations. Be sure to include units.

The graph in the following figure models the number of people N(t) who have come down with the flu t weeks after its initial outbreak in a town with a population of 50,000 citizens.

a. Describe what N′(t) represents and how it behaves as t increases.

b. What does the derivative tell us about how this town is affected by the flu outbreak?

The function starts at (0, 3000) and increases quickly to an asymptote at y = 50000.

Answer

a. The rate at which the number of people who have come down with the flu is changing t weeks after the initial outbreak. b. The rate is increasing sharply up to the third week, at which point it slows down and then becomes constant.

3-101 §3.2 source ↗

For the following exercises, use the following table, which shows the height h of the Saturn V rocket for the Apollo 11 mission t seconds after launch.

Time (seconds) Height (meters)
0 0
1 2
2 4
3 13
4 25
5 32

[T] Construct a table of values for h′(t) and graph both h(t) and h′(t) on the same graph. (Hint: for interior points, estimate both the left limit and right limit and average them. An interior point of an interval I is an element of I which is not an endpoint of I.)

Answer

Time (seconds) h′(t)(m/s)
0 2
1 2
2 5.5
3 10.5
4 9.5
5 7

3-103 §3.2 source ↗

For the following exercises, use the following table, which shows the height h of the Saturn V rocket for the Apollo 11 mission t seconds after launch.

Time (seconds) Height (meters)
0 0
1 2
2 4
3 13
4 25
5 32

[T] The best quadratic fit to the data is given by G(t)= 1.429t2+ 0.0857t− 0.1429, where G is the height of the rocket (in meters) and t is the time elapsed since takeoff. From this equation, determine G′(t). Graph G(t) with the given data and, on a separate coordinate plane, graph G′(t).

Answer

G′(t)= 2.858t+ 0.0857

This graph has the points (0, 0), (1, 2), (2, 4), (3, 13), (4, 25), and (5, 32). There is a quadratic line fit to the points with y intercept near 0.


This graph has a straight line with y intercept near 0 and slope slightly less than 3.

3-105 §3.2 source ↗

For the following exercises, use the following table, which shows the height h of the Saturn V rocket for the Apollo 11 mission t seconds after launch.

Time (seconds) Height (meters)
0 0
1 2
2 4
3 13
4 25
5 32

Using the best linear, quadratic, and cubic fits to the data, determine what H″(t), G″(t)andF″(t) are. What are the physical meanings of H″(t), G″(t)andF″(t), and what are their units?

Answer

H″(t)= 0, G″(t)= 2.858andf″(t)= 1.222t+ 5.912 represent the acceleration of the rocket, with units of meters per second squared (m/s2).

Checkpoint 3.11 §3.3 source ↗

Find the derivative of g(x)=−3.

Answer

0

Checkpoint 3.12 §3.3 source ↗

Find ddx(x4).

Answer

4 x 3

Checkpoint 3.13 §3.3 source ↗

Find the derivative of f(x)=x7.

Answer

f ′ ( x ) = 7 x 6

Checkpoint 3.14 §3.3 source ↗

Find the derivative of f(x)= 2x3− 6x2+ 3.

Answer

f ′ (x)= 6 x 2 − 12x.

Checkpoint 3.15 §3.3 source ↗

Find an equation of the line tangent to the graph of f(x)=3x2−11 at x=2. Use the point-slope form.

Answer

y = 12 x − 23

Checkpoint 3.16 §3.3 source ↗

Use the product rule to obtain the derivative of j(x)= 2x5(4x2+x).

Answer

j ′ (x)= 10 x 4 (4 x 2 +x)+ (8x+1)(2 x 5 )= 56 x 6 + 12 x 5 .

Checkpoint 3.17 §3.3 source ↗

Find the derivative of h(x)= 3x+14x−3.

Answer

k ′ (x)= − 13 ( 4 x − 3 ) 2 .

Checkpoint 3.18 §3.3 source ↗

Find the derivative of g(x)=1x7 using the extended power rule.

Answer

g ′ (x)= −7 x −8 .

Checkpoint 3.19 §3.3 source ↗

Find ddx(3f(x)−2g(x)).

Answer

3 f ′ (x)− 2 g ′ (x).

Checkpoint 3.20 §3.3 source ↗

Find the values of x for which the graph of f(x)= 4x2− 3x+ 2 has a tangent line parallel to the line y=2x+3.

Answer

5 8

3-107 §3.3 source ↗

For the following exercises, find f′(x) for each function.

f(x)= 5 x 3 − x+ 1

Answer

f ′ (x)= 15 x 2 − 1

3-109 §3.3 source ↗

For the following exercises, find f′(x) for each function.

f(x)= 8 x 4 + 9 x 2 − 1

Answer

f ′ (x)= 32 x 3 + 18x

3-111 §3.3 source ↗

For the following exercises, find f′(x) for each function.

f(x)= 3x(18 x 4 + 13 x + 1 )

Answer

f ′ (x)= 270 x 4 + 39 ( x + 1 ) 2

3-113 §3.3 source ↗

For the following exercises, find f′(x) for each function.

f(x)= x 2 ( 2 x 2 + 5 x 3 )

Answer

f ′ ( x ) = −5 x 2

3-115 §3.3 source ↗

For the following exercises, find f′(x) for each function.

f(x)= 4 x 3 − 2 x + 1 x 2

Answer

f ′ (x)= 4 x 4 + 2 x 2 − 2 x x 4

3-117 §3.3 source ↗

For the following exercises, find f′(x) for each function.

f(x)= x + 9 x 2 − 7 x + 1

Answer

f ′ (x)= − x 2 − 18 x + 64 ( x 2 − 7 x + 1 ) 2

3-119 §3.3 source ↗

For the following exercises, find an equation of the tangent line T(x) to the graph of the given function at the indicated point. Use a graphing calculator to graph the function and the tangent line.

[T] y=2x2+1 at (1,3)

Answer


The graph y is a slightly curving line with y intercept at 1. The line T(x) is straight with y intercept 3 and slope 1/2.


T(x)=–4x+7

3-121 §3.3 source ↗

For the following exercises, find an equation of the tangent line T(x) to the graph of the given function at the indicated point. Use a graphing calculator to graph the function and the tangent line.

[T] y=2x−3x2 at (1,−1)

Answer


The graph y is a two crescents with the crescent in the third quadrant sloping gently from (−3, −1) to (−1, −5) and the other crescent sloping more sharply from (0.8, −5) to (3, 0.2). The straight line T(x) is drawn through (0, −5) with slope 4.


T(x)=4x−5

3-123 §3.3 source ↗

For the following exercises, assume that f(x) and g(x) are both differentiable functions for all x. Find the derivative of each of the functions h(x).

h ( x ) = x 3 f ( x )

Answer

h ′ (x)= 3 x 2 f(x)+ x 3 f ′ (x)

3-125 §3.3 source ↗

For the following exercises, assume that f(x) and g(x) are both differentiable functions for all x. Find the derivative of each of the functions h(x).

h(x)= 3 f ( x ) g ( x ) + 2

Answer

h ′ (x)= 3 f ′ ( x ) ( g ( x ) + 2 ) − 3 f ( x ) g ′ ( x ) ( g ( x ) + 2 ) 2

3-127 §3.3 source ↗

For the following exercises, assume that f(x) and g(x) are both differentiable functions with values as given in the following table. Use the following table to calculate the following derivatives.

x 1 2 3 4
f(x) 3 5 −2 0
g(x) 2 3 −4 6
f′(x) −1 7 8 −3
g′(x) 4 1 2 9

Find h′(2) if h(x)= f(x)g(x).

Answer

16 9

3-129 §3.3 source ↗

For the following exercises, assume that f(x) and g(x) are both differentiable functions with values as given in the following table. Use the following table to calculate the following derivatives.

x 1 2 3 4
f(x) 3 5 −2 0
g(x) 2 3 −4 6
f′(x) −1 7 8 −3
g′(x) 4 1 2 9

Find h′(4) if h(x)= 1x+ g(x)f(x).

Answer

Undefined

3-131 §3.3 source ↗

For the following exercises, use the following figure to find the indicated derivatives, if they exist.

Two functions are graphed: f(x) and g(x). The function f(x) starts at (−1, 5) and decreases linearly to (3, 1) at which point it increases linearly to (5, 3). The function g(x) starts at the origin, increases linearly to (2.5, 2.5), and then remains constant at y = 2.5.

Let h(x)= f(x)g(x). Find

a. h′(1),

b. h′(3), and

c. h′(4).

Answer

a. 2, b. does not exist, c. 2.5

3-133 §3.3 source ↗

For the following exercises,

[T] f(x)= 2x3+ 3x− x2, a= 2

Answer

a. 23, b. y=23x−28

The graph is a slightly deformed cubic function passing through the origin. The tangent line is drawn through (0, −28) with slope 23.

3-135 §3.3 source ↗

For the following exercises,

[T] f(x)= x2− x12+ 3x+ 2, a= 0

Answer

a. 3, b. y=3x+2

The graph starts in the third quadrant, increases quickly and passes through the x axis near −0.9, then increases at a lower rate, passes through (0, 2), increases to (1, 5), and then decreases quickly and passes through the x axis near 1.2.

3-137 §3.3 source ↗

For the following exercises,

Find an equation of the tangent line to the graph of f(x)= 2x3+ 4x2− 5x− 3 at x=−1.

Answer

y = −7 x − 3

3-139 §3.3 source ↗

For the following exercises,

Find an equation of the tangent line to the graph of f(x)= (3x−x2)(3−x−x2) at x=1.

Answer

y = −5 x + 7

3-141 §3.3 source ↗

For the following exercises,

Find an equation of the line passing through the point P(3,3) and tangent to the graph of f(x)=6x−1.

Answer

y = − 3 2 x + 15 2

3-143 §3.3 source ↗

For the following exercises,

Find a quadratic polynomial such that f(1)= 5, f′(1)= 3 and f″(1)=−6.

Answer

y = −3 x 2 + 9 x − 1

3-145 §3.3 source ↗

For the following exercises,

[T] A herring swimming along a straight line has traveled s(t)=t2t2+2 feet in t seconds.

Determine the velocity of the herring when it has traveled 3 seconds.

Answer

12121 or 0.0992 ft/s

3-147 §3.3 source ↗

For the following exercises,

[T] The concentration of antibiotic in the bloodstream t hours after being injected is given by the function C(t)= 2t2+tt3+50, where C is measured in milligrams per liter of blood.

a. Find the rate of change of C(t).

b. Determine the rate of change for t=8,12,24, and 36.

c. Briefly describe what seems to be occurring as the number of hours increases.

Answer

a. −2t4−2t3+200t+50(t3+50)2 b. −0.02395 mg/L-hr, −0.01344 mg/L-hr, −0.003566 mg/L-hr, −0.001579 mg/L-hr c. The rate at which the concentration of drug in the bloodstream decreases is slowing to 0 as time increases.

3-149 §3.3 source ↗

For the following exercises,

[T] According to Newton’s law of universal gravitation, the force F between two bodies of constant mass m1 and m2 is given by the formula F=Gm1m2d2, where G is the gravitational constant and d is the distance between the bodies.

a. Suppose that G,m1,andm2 are constants. Find the rate of change of force F with respect to distance d.

b. Find the rate of change of force F with gravitational constant G= 6.67×10−11 Nm2/kg2, on two bodies 10 meters apart, each with a mass of 1000 kilograms.

Answer

a. F′(d)= −2Gm1m2d3 b. −1.33×10−7 N/m

Checkpoint 3.21 §3.4 source ↗

Given f(10)=−5 and f′(10)=6, estimate f(10.1).

Answer

−4.4

Checkpoint 3.22 §3.4 source ↗

A particle moves along a coordinate axis. Its position at time t is given by s(t)= t2− 5t+ 1. Is the particle moving from right to left or from left to right at time t=3?

Answer

left to right

Checkpoint 3.23 §3.4 source ↗

The current population of a mosquito colony is known to be 3,000; that is, P(0)=3,000. If P′(0)=100, estimate the size of the population in 3 days, where t is measured in days.

Answer

3,300

Checkpoint 3.24 §3.4 source ↗

Suppose that the profit obtained from the sale of x fish-fry dinners is given by P(x)= −0.03x2+ 8x− 50. Use the marginal profit function to estimate the profit from the sale of the 101st fish-fry dinner.

Answer

$2

3-151 §3.4 source ↗

For the following exercises, the given functions represent the position of a particle traveling along a horizontal line; t≥0.

s(t)= 2 t 3 − 15 t 2 + 36t− 10

Answer

a. v(t)= 6t2− 30t+ 36, a(t)= 12t− 30; b. speeds up (2,2.5)∪(3,∞), slows down (0,2)∪(2.5,3)

3-153 §3.4 source ↗

For the following exercises, the given functions represent the position of a particle traveling along a horizontal line; t≥0.

A model rocket is fired vertically upward from the ground. The distance s in feet that the rocket travels from the ground after t seconds is given by s(t)= −16t2+ 560t.

a. Find the velocity of the rocket 3 seconds after being fired.

b. Find the acceleration of the rocket 3 seconds after being fired.

Answer

a. 464ft/s2 b. −32ft/s2

3-155 §3.4 source ↗

For the following exercises, the given functions represent the position of a particle traveling along a horizontal line; t≥0.

The position function s(t)= t2− 3t− 4 represents the position of the back of a car backing out of a driveway and then driving in a straight line, where s is in feet and t is in seconds. In this case, s(t)=0 represents the time at which the back of the car is at the garage door, so s(0)=−4 is the starting position of the car, 4 feet inside the garage.

a. Determine the velocity of the car when s(t)=0.

b. Determine the velocity of the car when s(t)=14.

Answer

a. 5 ft/s b. 9 ft/s

3-157 §3.4 source ↗

For the following exercises, the given functions represent the position of a particle traveling along a horizontal line; t≥0.

A potato is launched vertically upward with an initial velocity of 100 ft/s from a potato gun at the top of an 85-foot-tall building. The position of the potato relative to the ground after t seconds is given by s(t)= −16t2+ 100t+ 85.

a. Find the velocity of the potato after 0.5s and 5.75s.

b. Find the speed of the potato at 0.5 s and 5.75 s.

c. Determine when the potato reaches its maximum height.

d. Find the acceleration of the potato at 0.5 s and 1.5 s.

e. Determine how long the potato is in the air.

f. Determine the velocity of the potato upon hitting the ground.

Answer

a. 84 ft/s, −84 ft/s b. 84 ft/s c. 258s d. −32ft/s2 in both cases e. 18(25+965)s f. −4965ft/s

3-159 §3.4 source ↗

For the following exercises, the given functions represent the position of a particle traveling along a horizontal line; t≥0.

The following graph shows the position y=s(t) of an object moving along a straight line.

On the Cartesian coordinate plane, a function is graphed that is part of a parabola from the origin to (2, 2) with maximum at (1.5, 2.25). Then the function is constant until (5, 2), at which points becomes a parabola again, decreasing to a minimum at (6, 1) and then increasing to (7, 2).

a. Use the graph of the position function to determine the time intervals when the velocity is positive, negative, or zero.

b. Sketch the graph of the velocity function.

c. Use the graph of the velocity function to determine the time intervals when the acceleration is positive, negative, or zero.

d. Determine the time intervals when the object is speeding up or slowing down.

Answer

a. Velocity is positive on (0,1.5)∪(6,7), negative on (1.5,2)∪(5,6), and zero on (2,5). b.

The graph is a straight line from (0, 2) to (2, −1), then is discontinuous with a straight line from (2, 0) to (5, 0), and then is discontinuous with a straight line from (5, −4) to (7, 4).


c. Acceleration is positive on (5,7), negative on (0,2), and zero on (2,5). d. The object is speeding up on (6,7)∪(1.5,2) and slowing down on (0,1.5)∪(5,6).

3-161 §3.4 source ↗

For the following exercises, the given functions represent the position of a particle traveling along a horizontal line; t≥0.

The price p (in dollars) and the demand x for a certain digital clock radio is given by the price–demand function p= 10− 0.001x.

a. Find the revenue function R(x).

b. Find the marginal revenue function.

c. Find the marginal revenue at x=2000 and 5000.

Answer

a. R(x)= 10x− 0.001x2 b. R′(x)= 10− 0.002x c. $6 per item, $0 per item

3-163 §3.4 source ↗

For the following exercises, the given functions represent the position of a particle traveling along a horizontal line; t≥0.

[T] In general, the profit function is the difference between the revenue and cost functions: P(x)= R(x)− C(x).

Suppose the price-demand and cost functions for the production of cordless drills is given respectively by p=143−0.03x and C(x)= 75,000+ 65x, where x is the number of cordless drills that are sold at a price of p dollars per drill and C(x) is the cost of producing x cordless drills.

a. Find the marginal cost function.

b. Find the revenue and marginal revenue functions.

c. Find R′(1000) and R′(4000). Interpret the results.

d. Find the profit and marginal profit functions.

e. Find P′(1000) and P′(4000). Interpret the results.

Answer

a. C′(x)=65 b. R(x)= 143x− 0.03x2, R′(x)= 143− 0.06x c. 83,−97. At a production level of 1000 cordless drills, revenue is increasing at a rate of $83 per drill; at a production level of 4000 cordless drills, revenue is decreasing at a rate of $97 per drill. d. P(x)= −0.03x2+ 78x− 75000, P′(x)= −0.06x+ 78 e. 18,−162. At a production level of 1000 cordless drills, profit is increasing at a rate of $18 per drill; at a production level of 4000 cordless drills, profit is decreasing at a rate of $162 per drill.

3-165 §3.4 source ↗

For the following exercises, the given functions represent the position of a particle traveling along a horizontal line; t≥0.

[T] A culture of bacteria grows in number according to the function N(t)= 3000(1+4tt2+100), where t is measured in hours.

a. Find the rate of change of the number of bacteria.

b. Find N′(0), N′(10), N′(20), and N′(30).

c. Interpret the results in (b).

d. Find N″(0), N″(10), N″(20), and N″(30). Interpret what the answers imply about the bacteria population growth.

Answer

a. N′(t)= 3000(−4t2+400(t2+100)2) b. 120, 0, −14.4, −9.6 c. The bacteria population increases from time 0 to 10 hours; afterwards, the bacteria population decreases. d. 0, −6, 0.384, 0.432. The rate at which the bacteria is increasing is decreasing during the first 10 hours. Afterwards, the bacteria population is decreasing at a decreasing rate.

3-167 §3.4 source ↗

The following questions concern the population (in millions) of London by decade in the 19th century, which is listed in the following table.

[T]

a. Using a calculator or a computer program, find the best-fit linear function to measure the population.

b. Find the derivative of the equation in a. and explain its physical meaning.

c. Find the second derivative of the equation and explain its physical meaning.

Table 3.4 Population of London in the book ↗
Years since 1800 Population (millions)
1 0.8795
11 1.040
21 1.264
31 1.516
41 1.661
51 2.000
61 2.634
71 3.272
81 3.911
91 4.422
Source: http://en.wikipedia.org/wiki/Demographics_of_London.

Answer

a. P(t)= 0.03983+ 0.4280 b. P′(t)= 0.03983. The population is increasing. c. P″(t)=0. The rate at which the population is increasing is constant.

3-169 §3.4 source ↗

For the following exercises, consider an astronaut on a large planet in another galaxy. To learn more about the composition of this planet, the astronaut drops an electronic sensor into a deep trench. The sensor transmits its vertical position every second in relation to the astronaut’s position. The summary of the falling sensor data is displayed in the following table.

Time after dropping (s) Position (m)
0 0
1 −1
2 −2
3 −5
4 −7
5 −14

[T]

a. Using a calculator or computer program, find the best-fit quadratic curve to the data.

b. Find the derivative of the position function and explain its physical meaning.

c. Find the second derivative of the position function and explain its physical meaning.

Answer

a. p(t)= −0.6071x2+ 0.4357x− 0.3571 b. p′(t)= −1.214x+ 0.4357. This is the velocity of the sensor. c. p″(t)= −1.214. This is the acceleration of the sensor; it is a constant acceleration downward.

3-171 §3.4 source ↗

The following problems deal with the Holling type I, II, and III equations. These equations describe the ecological event of growth of a predator population given the amount of prey available for consumption.

[T] The Holling type I equation is described by f(x)=ax, where x is the amount of prey available and a>0 is the rate at which the predator meets the prey for consumption.

a. Graph the Holling type I equation, given a=0.5.

b. Determine the first derivative of the Holling type I equation and explain physically what the derivative implies.

c. Determine the second derivative of the Holling type I equation and explain physically what the derivative implies.

d. Using the interpretations from b. and c. explain why the Holling type I equation may not be realistic.

Answer

a.

The graph is a straight line drawn through the origin with slope 1/2.


b. f′(x)=a. The more increase in prey, the more growth for predators. c. f″(x)=0. As the amount of prey increases, the rate at which the predator population growth increases is constant. d. This equation assumes that if there is more prey, the predator is able to increase consumption linearly. This assumption is unphysical because we would expect there to be some saturation point at which there is too much prey for the predator to consume adequately.

3-173 §3.4 source ↗

The following problems deal with the Holling type I, II, and III equations. These equations describe the ecological event of growth of a predator population given the amount of prey available for consumption.

[T] The Holling type III equation is described by f(x)= ax2n2+x2, where x is the amount of prey available and a>0 is the maximum consumption rate of the predator.

a. Graph the Holling type III equation given a=0.5 and n=5. What are the differences between the Holling type II and III equations?

b. Take the first derivative of the Holling type III equation and interpret the physical meaning of the derivative.

c. Find and interpret the meaning of the second derivative (it may help to graph the second derivative).

d. What additional ecological phenomena does the Holling type III function describe compared with the Holling type II function?

Answer

a.

The graph increases from the origin quickly at first and then slowly to (10, 0.4).


b. f′(x)= 2axn2(n2+x2)2. When the amount of prey increases, the predator growth increases. c. f″(x)= 2an2(n2−3x2)(n2+x2)3. When the amount of prey is extremely small, the rate at which predator growth is increasing is increasing, but when the amount of prey reaches above a certain threshold, the rate at which predator growth is increasing begins to decrease. d. At lower levels of prey, the prey is more easily able to avoid detection by the predator, so fewer prey individuals are consumed, resulting in less predator growth.

Checkpoint 3.25 §3.5 source ↗

Find the derivative of f(x)= sinxcosx.

Answer

f ′ (x)= cos 2 x− sin 2 x

Checkpoint 3.26 §3.5 source ↗

Find the derivative of f(x)=xcosx.

Answer

cos x + x sin x cos 2 x

Checkpoint 3.27 §3.5 source ↗

A particle moves along a coordinate axis. Its position at time t is given by s(t)= 3t+ 2cost for 0≤t≤2π. At what times is the particle at rest?

Answer

t = π 3 , t = 2 π 3

Checkpoint 3.28 §3.5 source ↗

Find the derivative of f(x)=cotx.

Answer

f ′ (x)= − csc 2 x

Checkpoint 3.29 §3.5 source ↗

Find the derivative of f(x)= 2tanx− 3cotx.

Answer

f ′ (x)= 2 sec 2 x+ 3 csc 2 x

Checkpoint 3.30 §3.5 source ↗

Find the slope of the line tangent to the graph of f(x)=tanx at x=π6.

Answer

4 3

Checkpoint 3.31 §3.5 source ↗

For y=cosx, find d4ydx4.

Answer

cos x

Checkpoint 3.32 §3.5 source ↗

For y=sinx, find d59dx59(sinx).

Answer

− cos x

Checkpoint 3.33 §3.5 source ↗

A block attached to a spring is moving vertically. Its position at time t is given by s(t)=2sint. Find v(5π6) and a(5π6). Compare these values and decide whether the block is speeding up or slowing down.

Answer

v(5π6)= −3< 0 and a(5π6)= −1< 0. The block is speeding up.

3-175 §3.5 source ↗

For the following exercises, find dydx for the given functions.

y = x 2 − sec x + 1

Answer

d y d x = 2x− secxtanx

3-177 §3.5 source ↗

For the following exercises, find dydx for the given functions.

y = x 2 cot x

Answer

d y d x = 2xcotx− x 2 csc 2 x

3-179 §3.5 source ↗

For the following exercises, find dydx for the given functions.

y = sec x x

Answer

d y d x = x sec x tan x − sec x x 2

3-181 §3.5 source ↗

For the following exercises, find dydx for the given functions.

y= (x+cosx)(1−sinx)

Answer

d y d x = (1−sinx)(1−sinx)− cosx(x+cosx)

3-183 §3.5 source ↗

For the following exercises, find dydx for the given functions.

y= 1 − cot x 1 + cot x

Answer

d y d x = 2 csc 2 x ( 1 + cot x ) 2

3-185 §3.5 source ↗

For the following exercises, find an equation of the tangent line to each of the given functions at the indicated values of x. Then use a calculator to graph both the function and the tangent line to ensure the equation for the tangent line is correct.

[T] f(x)= −sinx, x= 0

Answer

y=−x

The graph shows negative sin(x) and the straight line T(x) with slope −1 and y intercept 0.

3-187 §3.5 source ↗

For the following exercises, find an equation of the tangent line to each of the given functions at the indicated values of x. Then use a calculator to graph both the function and the tangent line to ensure the equation for the tangent line is correct.

[T] f(x)= 1+ cosx, x= 3π2

Answer

y=x+2−3π2

The graph shows the cosine function shifted up one and has the straight line T(x) with slope 1 and y intercept (2 – 3π)/2.

3-189 §3.5 source ↗

For the following exercises, find an equation of the tangent line to each of the given functions at the indicated values of x. Then use a calculator to graph both the function and the tangent line to ensure the equation for the tangent line is correct.

[T] f(x)= x2− tanx, x= 0

Answer

y=−x

The graph shows the function as starting at (−1, 3), decreasing to the origin, continuing to slowly decrease to about (1, −0.5), at which point it decreases very quickly.

3-191 §3.5 source ↗

For the following exercises, find d2ydx2 for the given functions.

y= xsinx− cosx

Answer

3 cos x − x sin x

3-193 §3.5 source ↗

For the following exercises, find d2ydx2 for the given functions.

y = x − 1 2 sin x

Answer

1 2 sin x

3-195 §3.5 source ↗

For the following exercises, find d2ydx2 for the given functions.

y = 2 csc x

Answer

2 csc x ( csc 2 x + cot 2 x )

3-197 §3.5 source ↗

For the following exercises, find d2ydx2 for the given functions.

Find all x values on the graph of f(x)= −3sinxcosx where the tangent line is horizontal.

Answer

( 2 n + 1 ) π 4 , wherenis an integer

3-199 §3.5 source ↗

For the following exercises, find d2ydx2 for the given functions.

Let f(x)=cotx. Determine the points on the graph of f for 0< x< 2π where the tangent line(s) is (are) parallel to the line y=−2x.

Answer

( π 4 , 1),  ( 3 π 4 , −1),  ( 5 π 4 , 1),  ( 7 π 4 , -1)

3-201 §3.5 source ↗

For the following exercises, find d2ydx2 for the given functions.

Let the position of a swinging pendulum in simple harmonic motion be given by s(t)= acost+ bsint where a and b are constants, t measures time in seconds, and s measures position in centimeters. If the position is 0 cm and the velocity is 3 cm/s when t=0, find the values of a and b.

Answer

a = 0 , b = 3

3-203 §3.5 source ↗

For the following exercises, find d2ydx2 for the given functions.

The number of hamburgers sold at a fast-food restaurant in Pasadena, California, is given by y=10+5sinx where y is the number of hamburgers sold and x represents the number of hours after the restaurant opened at 11 a.m. until 11 p.m., when the store closes. Find y′ and determine the intervals where the number of burgers being sold is increasing.

Answer

y′=5cos(x), increasing on (0,π2), (3π2,5π2), and (7π2,12)

3-209 §3.5 source ↗

For the following exercises, find the requested higher-order derivative for the given functions.

d3ydx3 of y=3cosx

Answer

3 sin x

3-211 §3.5 source ↗

For the following exercises, find the requested higher-order derivative for the given functions.

d4ydx4 of y=5cosx

Answer

5 cos x

3-213 §3.5 source ↗

For the following exercises, find the requested higher-order derivative for the given functions.

d3ydx3 of y=x10−secx

Answer

720 x 7 − 5tan(x) sec 3 (x)− tan 3 (x)sec(x)

Checkpoint 3.34 §3.6 source ↗

Find the derivative of h(x)= (2x3+2x−1)4.

Answer

h ′ (x)= 4 ( 2 x 3 + 2 x − 1 ) 3 (6 x 2 +2)= 8(3 x 2 +1) ( 2 x 3 + 2 x − 1 ) 3

Checkpoint 3.35 §3.6 source ↗

Find an equation of the line tangent to the graph of f(x)= (x2−2)3 at x=−2.

Answer

y = −48 x − 88

Checkpoint 3.36 §3.6 source ↗

Find the derivative of h(x)= sin(7x+2).

Answer

h ′ (x)= 7cos(7x+2)

Checkpoint 3.37 §3.6 source ↗

Find the derivative of h(x)= x(2x+3)3.

Answer

h ′ (x)= 3 − 4 x ( 2 x + 3 ) 4

Checkpoint 3.38 §3.6 source ↗

Find the derivative of h(x)= sin6(x3).

Answer

h ′ (x)= 18 x 2 sin 5 ( x 3 )cos( x 3 )

Checkpoint 3.39 §3.6 source ↗

A particle moves along a coordinate axis. Its position at time t is given by s(t)= sin(4t). Find its acceleration at time t.

Answer

a(t)= −16sin(4t)

Checkpoint 3.40 §3.6 source ↗

Given h(x)= f(g(x)). If g(2)= −3, g′(2)= 4, and f′(−3)=7, find h′(2).

Answer

28

Checkpoint 3.41 §3.6 source ↗

Use Leibniz’s notation to find the derivative of y=cos(x3). Make sure that the final answer is expressed entirely in terms of the variable x.

Answer

d y d x = −3 x 2 sin( x 3 )

3-215 §3.6 source ↗

For the following exercises, given y=f(u) and u=g(x), find dydx by using Leibniz’s notation for the chain rule: dydx= dydududx.

y= 6 u 3 , u= 7x− 4

Answer

18 u 2 ·7= 18 ( 7 x − 4 ) 2 ·7

3-217 §3.6 source ↗

For the following exercises, given y=f(u) and u=g(x), find dydx by using Leibniz’s notation for the chain rule: dydx= dydududx.

y= cosu, u= − x 8

Answer

−sinu· −1 8 = −sin( − x 8 )· −1 8

3-219 §3.6 source ↗

For the following exercises, given y=f(u) and u=g(x), find dydx by using Leibniz’s notation for the chain rule: dydx= dydududx.

y= 4 u + 3 , u= x 2 − 6x

Answer

8 x − 24 2 4 u + 3 = 4 x − 12 4 x 2 − 24 x + 3

3-221 §3.6 source ↗

For each of the following exercises,

y = ( 3 x 2 + 1 ) 3

Answer

a. u=3x2+1; b. 18x(3x2+1)2

3-223 §3.6 source ↗

For each of the following exercises,

y = ( x 7 + 7 x ) 7

Answer

a. f(u)= u7, u= x7+ 7x; b. 7(x7+7x)6·(17−7x2)

3-225 §3.6 source ↗

For each of the following exercises,

y = csc ( π x + 1 )

Answer

a. f(u)= cscu, u= πx+ 1; b. −πcsc(πx+1)·cot(πx+1)

3-227 §3.6 source ↗

For each of the following exercises,

y= −6 ( sin   x ) - 3

Answer

a. f(u)= −6u−3, u= sinx, b. 18(sin)−4x·cosx

3-229 §3.6 source ↗

For the following exercises, find dydx for each function.

y = ( 5 − 2 x ) −2

Answer

4 ( 5 − 2 x ) 3

3-231 §3.6 source ↗

For the following exercises, find dydx for each function.

y= ( 2 x 3 − x 2 + 6 x + 1 ) 3

Answer

6 ( 2 x 3 − x 2 + 6 x + 1 ) 2 ( 3 x 2 − x + 3 )

3-233 §3.6 source ↗

For the following exercises, find dydx for each function.

y= ( tan x + sin x ) −3

Answer

−3 ( tan x + sin x ) −4 · ( sec 2 x + cos x )

3-235 §3.6 source ↗

For the following exercises, find dydx for each function.

y= sin(cos7x)

Answer

−7 cos ( cos 7 x ) · sin 7 x

3-237 §3.6 source ↗

For the following exercises, find dydx for each function.

y= cot 3 (4x+1)

Answer

−12 cot 2 ( 4 x + 1 ) · csc 2 ( 4 x + 1 )

3-239 §3.6 source ↗

For the following exercises, find dydx for each function.

Let y= (f(x)+5x2)4 and suppose that f(−1)=−4 and dydx=3 when x=−1. Find f′(−1)

Answer

10 3 4

3-241 §3.6 source ↗

For the following exercises, find dydx for each function.

[T] Find an equation of the tangent line to y=−sin(x2) at the origin. Use a calculator to graph the function and the tangent line together.

Answer

y = −1 2 x

3-243 §3.6 source ↗

For the following exercises, find dydx for each function.

Find the x-coordinates at which the tangent line to y=(x−6x)8 is horizontal.

Answer

x = ± 6

3-245 §3.6 source ↗

For the following exercises, use the information in the following table to find h′(a) at the given value for a.

x f(x) f′(x) g(x) g′(x)
0 2 5 0 2
1 1 −2 3 0
2 4 4 1 −1
3 3 −3 2 3

h(x)= f(g(x)); a= 0

Answer

10

3-247 §3.6 source ↗

For the following exercises, use the information in the following table to find h′(a) at the given value for a.

x f(x) f′(x) g(x) g′(x)
0 2 5 0 2
1 1 −2 3 0
2 4 4 1 −1
3 3 −3 2 3

h(x)= ( x 4 + g ( x ) ) −2 ; a= 1

Answer

− 1 8

3-249 §3.6 source ↗

For the following exercises, use the information in the following table to find h′(a) at the given value for a.

x f(x) f′(x) g(x) g′(x)
0 2 5 0 2
1 1 −2 3 0
2 4 4 1 −1
3 3 −3 2 3

h(x)= f(x+f(x)); a= 1

Answer

−4

3-251 §3.6 source ↗

For the following exercises, use the information in the following table to find h′(a) at the given value for a.

x f(x) f′(x) g(x) g′(x)
0 2 5 0 2
1 1 −2 3 0
2 4 4 1 −1
3 3 −3 2 3

h(x)= g(2+f( x 2 )); a= 1

Answer

−12

3-253 §3.6 source ↗

For the following exercises, use the information in the following table to find h′(a) at the given value for a.

x f(x) f′(x) g(x) g′(x)
0 2 5 0 2
1 1 −2 3 0
2 4 4 1 −1
3 3 −3 2 3

[T] The position function of a freight train is given by s(t)= 100(t+1)−2, with s in meters and t in seconds. At time t=6 s, find the train’s

a. velocity and

b. acceleration.

c. Using a. and b. is the train speeding up or slowing down?

Answer

a. −200343 m/s, b. 6002401 m/s2, c. The train is slowing down since velocity and acceleration have opposite signs.

3-255 §3.6 source ↗

For the following exercises, use the information in the following table to find h′(a) at the given value for a.

x f(x) f′(x) g(x) g′(x)
0 2 5 0 2
1 1 −2 3 0
2 4 4 1 −1
3 3 −3 2 3

[T] The total cost to produce x boxes of Thin Mint Girl Scout cookies is C dollars, where C= 0.0001x3− 0.02x2+ 3x+ 300. In t weeks production is estimated to be x=1600+100t boxes.

a. Find the marginal cost C′(x).

b. Use Leibniz’s notation for the chain rule, dCdt= dCdx·dxdt, to find the rate with respect to time t that the cost is changing.

c. Use b. to determine how fast costs are increasing when t=2 weeks. Include units with the answer.

Answer

a. C′(x)= 0.0003x2− 0.04x+ 3 b. dCdt= 100·(0.0003x2−0.04x+3) c. Approximately $90,300 per week

3-257 §3.6 source ↗

For the following exercises, use the information in the following table to find h′(a) at the given value for a.

x f(x) f′(x) g(x) g′(x)
0 2 5 0 2
1 1 −2 3 0
2 4 4 1 −1
3 3 −3 2 3

[T] The formula for the volume of a sphere is S=43πr3, where r (in feet) is the radius of the sphere. Suppose a spherical snowball is melting in the sun.

a. Suppose r= 1(t+1)2− 112 where t is time in minutes. Use the chain rule dSdt= dSdr·drdt to find the rate at which the snowball is melting.

b. Use a. to find the rate at which the volume is changing at t=1 min.

Answer

a. dSdt= − 8πr2(t+1)3 b. The volume is decreasing at a rate of −π36 ft3/min.

3-259 §3.6 source ↗

For the following exercises, use the information in the following table to find h′(a) at the given value for a.

x f(x) f′(x) g(x) g′(x)
0 2 5 0 2
1 1 −2 3 0
2 4 4 1 −1
3 3 −3 2 3

[T] The depth (in feet) of water at a dock changes with the rise and fall of tides. The depth is modeled by the function D(t)= 5sin(π6t−7π6)+ 8, where t is the number of hours after midnight. Find the rate at which the depth is changing at 6 a.m.

Answer

~2.3 ft/hr

Checkpoint 3.42 §3.7 source ↗

Use the inverse function theorem to find the derivative of g(x)=1x+2. Compare the result obtained by differentiating g(x) directly.

Answer

g ′ (x)= − 1 ( x + 2 ) 2

Checkpoint 3.43 §3.7 source ↗

Find the derivative of g(x)=x5 by applying the inverse function theorem.

Answer

g(x)= 1 5 x − 4 / 5

Checkpoint 3.44 §3.7 source ↗

Find the derivative of s(t)=2t+1.

Answer

s ′ (t)= ( 2 t + 1 ) − 1 / 2

Checkpoint 3.45 §3.7 source ↗

Use the inverse function theorem to find the derivative of g(x)= tan−1x.

Answer

g ′ ( x ) = 1 1 + x 2

Checkpoint 3.46 §3.7 source ↗

Find the derivative of h(x)= cos−1(3x−1).

Answer

h ′ (x)= −3 6 x − 9 x 2

Checkpoint 3.47 §3.7 source ↗

Find an equation of the line tangent to the graph of f(x)=sin−1x at x=0.

Answer

y = x

3-261 §3.7 source ↗

For the following exercises, use the graph of y=f(x) to

A curved line starting at (−2, 0) and passing through (−1, 1) and (2, 2).

Answer

a.

A curved line starting at (−3, 0) and passing through (−2, 1) and (1, 2). There is another curved line that is symmetric with this about the line x = y. That is, it starts at (0, −3) and passes through (1, −2) and (2, 1).


b. (f−1)′(1)~2

3-263 §3.7 source ↗

For the following exercises, use the graph of y=f(x) to

A quarter circle starting at (0, 4) and ending at (4, 0).

Answer

a.

A quarter circle starting at (0, 4) and ending at (4, 0).


b. y'=-x16-x2y'1=-116-1=-115

3-265 §3.7 source ↗

For the following exercises, use the functions y=f(x) to find

f(x)= 2 x 3 − 3, x= 1

Answer

a. 6, b. x= f−1(y)= (y+32)1/3, c. 16

3-267 §3.7 source ↗

For the following exercises, use the functions y=f(x) to find

f(x)= sinx, x= 0

Answer

a. 1, b. x= f−1(y)= sin−1y, c. 1

3-269 §3.7 source ↗

For each of the following functions, find (f−1)′(a).

f(x)= x 3 + 2x+ 3, a= 0

Answer

1 5

3-271 §3.7 source ↗

For each of the following functions, find (f−1)′(a).

f(x)= x− 2 x , x< 0, a= 1

Answer

1 3

3-273 §3.7 source ↗

For each of the following functions, find (f−1)′(a).

f(x)= tanx+ 3 x 2 , a= 0;  0 <  x <  π/2

Answer

1

3-275 §3.7 source ↗

For each of the given functions y=f(x),

f(x)= x − 4 , P(2,8)

Answer

a. 4, b. y=4x

3-277 §3.7 source ↗

For each of the given functions y=f(x),

f(x)= − x 3 − x+ 2, P(−8,2)

Answer

a. −113, b. y= − 113x+ 1813

3-279 §3.7 source ↗

For the following exercises, find dydx for the given function.

y = sin −1 ( x 2 )

Answer

2 x 1 − x 4

3-281 §3.7 source ↗

For the following exercises, find dydx for the given function.

y = sec −1 ( 1 x )

Answer

−1 1 − x 2

3-283 §3.7 source ↗

For the following exercises, find dydx for the given function.

y= ( 1 + tan −1 x ) 3

Answer

3 ( 1 + tan −1 x ) 2 1 + x 2

3-285 §3.7 source ↗

For the following exercises, find dydx for the given function.

y = 1 tan −1 ( x )

Answer

−1 ( 1 + x 2 ) ( tan −1 x ) 2

3-287 §3.7 source ↗

For the following exercises, find dydx for the given function.

y = cot −1 4 − x 2

Answer

x ( 5 − x 2 ) 4 − x 2

3-289 §3.7 source ↗

For the following exercises, use the given values to find (f−1)′(a).

f(π)= 0, f′(π)= −1, a= 0

Answer

−1

3-291 §3.7 source ↗

For the following exercises, use the given values to find (f−1)′(a).

f( 1 3 )= −8, f′( 1 3 )= 2, a= −8

Answer

1 2

3-293 §3.7 source ↗

For the following exercises, use the given values to find (f−1)′(a).

f(1)= −3, f′(1)= 10, a= −3

Answer

1 10

3-295 §3.7 source ↗

For the following exercises, use the given values to find (f−1)′(a).

[T] The position of a moving hockey puck after t seconds is s(t)=tan−1t where s is in meters.

a. Find the velocity of the hockey puck at any time t.

b. Find the acceleration of the puck at any time t.

c. Evaluate a. and b. for t=2,4, and 6 seconds.

d. What conclusion can be drawn from the results in c.?

Answer

a. v(t)=11+t2 b. a(t)= −2t(1+t2)2 c. (a)0.2, 0.06, 0.03; (b)− 0.16, −0.028, −0.0088 d. The hockey puck is decelerating/slowing down at 2, 4, and 6 seconds.

3-297 §3.7 source ↗

For the following exercises, use the given values to find (f−1)′(a).

[T] A pole stands 75 feet tall. An angle θ is formed when wires of various lengths of x feet are attached from the ground to the top of the pole, as shown in the following figure. Find the rate of change of the angle dθdx when a wire of length 90 feet is attached.

A flagpole is shown with height 75 ft. A triangle is made with the flagpole height as the opposite side from the angle θ. The hypotenuse has length x.

Answer

−0.0168 radians per foot

3-299 §3.7 source ↗

For the following exercises, use the given values to find (f−1)′(a).

[T] A local movie theater with a 30-foot-high screen that is 10 feet above a person’s eye level when seated has a viewing angle θ (in radians) given by θ= cot−1x40− cot−1x10,

where x is the distance in feet away from the movie screen that the person is sitting, as shown in the following figure.

A person is shown with a right triangle coming from their eye (the right angle being on the opposite side from the eye), with height 10 and base x. There is a line drawn from the eye to the top of the screen, which makes an angle θ with the triangle’s hypotenuse. The screen has a height of 30.

a. Find dθdx.

b. Evaluate dθdx for x=5,10,15, and 20.

c. Interpret the results in b..

d. Evaluate dθdx for x=25,30,35, and 40

e. Interpret the results in d. At what distance x should the person sit to maximize his or her viewing angle?

Answer

a. dθdx= 10100+x2− 401600+x2 b. 18325, 9340, 424745, 0 c. As a person moves farther away from the screen, the viewing angle is increasing, which implies that as he or she moves farther away, his or her screen vision is widening. d. − 5412905, − 3500, − 19829945, − 91360 e. As the person moves beyond 20 feet from the screen, the viewing angle is decreasing. The optimal distance the person should stand for maximizing the viewing angle is 20 feet.

Checkpoint 3.48 §3.8 source ↗

Find dydx for y defined implicitly by the equation 4x5+ tany= y2+ 5x.

Answer

d y d x = 5 − 20 x 4 sec 2 y − 2 y

Checkpoint 3.49 §3.8 source ↗

Find an equation of the line tangent to the hyperbola x2−y2=16 at the point (5,3).

Answer

y = 5 3 x − 16 3

3-301 §3.8 source ↗

For the following exercises, use implicit differentiation to find dydx.

6 x 2 + 3 y 2 = 12

Answer

d y d x = −2 x y

3-303 §3.8 source ↗

For the following exercises, use implicit differentiation to find dydx.

3 x 3 + 9x y 2 = 5 x 3

Answer

d y d x = x 3 y − y 2 x

3-305 §3.8 source ↗

For the following exercises, use implicit differentiation to find dydx.

y x + 4 = x y + 8

Answer

d y d x = y − y 2 x + 4 x + 4 − x

3-307 §3.8 source ↗

For the following exercises, use implicit differentiation to find dydx.

ysin(xy)= y 2 –2

Answer

d y d x = y 2 cos ( x y ) 2 y − sin ( x y ) − x y cos ( x y )

3-309 §3.8 source ↗

For the following exercises, use implicit differentiation to find dydx.

x 3 y + x y 3 = −8

Answer

d y d x = −3 x 2 y − y 3 x 3 + 3 x y 2

3-311 §3.8 source ↗

For the following exercises, find an equation of the tangent line to the graph of the given equation at the indicated point. Use a calculator or computer software to graph the function and the tangent line.

[T] x2y2+ 5xy= 14, (2,1)

Answer


The graph has a crescent in each of the four quadrants. There is a straight line marked T(x) with slope −1/2 and y intercept 2.


y=−12x+2

3-313 §3.8 source ↗

For the following exercises, find an equation of the tangent line to the graph of the given equation at the indicated point. Use a calculator or computer software to graph the function and the tangent line.

[T] xy2+ sin(πy)− 2x2= 10, (2,−3)

Answer


The graph has two curves, one in the first quadrant and one in the fourth quadrant. They are symmetric about the x axis. The curve in the first quadrant goes from (0.3, 5) to (1.5, 3.5) to (5, 4). There is a straight line marked T(x) with slope 1/(π + 12) and y intercept −(3π + 38)/(π + 12).


y= 1π+12x− 3π+38π+12

3-315 §3.8 source ↗

For the following exercises, find an equation of the tangent line to the graph of the given equation at the indicated point. Use a calculator or computer software to graph the function and the tangent line.

[T] xy+ sin(x)= 1, (π2,0)

Answer


The graph starts in the third quadrant near (−5, 0), remains near 0 until x = −4, at which point it decreases until it reaches near (0, −5). There is an asymptote at x = 0. The graph begins again near (0, 5) decreases to (1, 0) and then increases a little bit before decreasing to be near (5, 0). There is a straight line marked T(x) that coincides with y = 0.


y=0

3-317 §3.8 source ↗

For the following exercises, find an equation of the tangent line to the graph of the given equation at the indicated point. Use a calculator or computer software to graph the function and the tangent line.

For the equation x2+ 2xy− 3y2= 0,

a. Find an equation of the normal to the tangent line at the point (1,1).

b. At what other point does the normal line in a. intersect the graph of the equation?

Answer

a. y=−x+2 b. (3,−1)

3-319 §3.8 source ↗

For the following exercises, find an equation of the tangent line to the graph of the given equation at the indicated point. Use a calculator or computer software to graph the function and the tangent line.

For the equation x2+xy+y2=7,

a. Find the x-intercept(s).

b. Find the slope of the tangent line(s) at the x-intercept(s).

c. What does the value(s) in b. indicate about the tangent line(s)?

Answer

a. (±7,0) b. −2 c. They are parallel since the slope is the same at both intercepts.

3-321 §3.8 source ↗

For the following exercises, find an equation of the tangent line to the graph of the given equation at the indicated point. Use a calculator or computer software to graph the function and the tangent line.

Find an equation of the tangent line to the graph of the equation tan−1(x+y)= x2+ π4 at the point (0,1).

Answer

y = − x + 1

3-323 §3.8 source ↗

For the following exercises, find an equation of the tangent line to the graph of the given equation at the indicated point. Use a calculator or computer software to graph the function and the tangent line.

[T] The number of cell phones produced when x dollars is spent on labor and y dollars is spent on capital invested by a manufacturer can be modeled by the equation 60x3/4y1/4= 3240.

a. Find dydx and evaluate at the point (81,16).

b. Interpret the result of a.

Answer

a. −0.5926 b. When $81 is spent on labor and $16 is spent on capital, the amount spent on capital is decreasing by $0.5926 per $1 spent on labor.

3-325 §3.8 source ↗

For the following exercises, find an equation of the tangent line to the graph of the given equation at the indicated point. Use a calculator or computer software to graph the function and the tangent line.

The volume of a right circular cone of radius x and height y is given by V=13πx2y. Suppose that the volume of the cone is a constant. Find dydx when x=4 and y=16.

Answer

−8

3-327 §3.8 source ↗

For the following exercises, consider a closed rectangular box with a square base with side x and height y.

If the surface area of the rectangular box is 78 square feet, find dydx when x=3 feet and y=5 feet.

Answer

−2.67

3-329 §3.8 source ↗

For the following exercises, use implicit differentiation to determine y′. Does the answer agree with the formulas we have previously determined?

x = cos y

Answer

y ′ = − 1 1 − x 2

Checkpoint 3.50 §3.9 source ↗

Find the derivative of h(x)=xe2x.

Answer

h ′ (x)= e 2 x + 2x e 2 x

Checkpoint 3.51 §3.9 source ↗

If A(t)= 1000e0.3t describes the mosquito population after t days, as in the preceding example, what is the rate of change of A(t) after 4 days?

Answer

996

Checkpoint 3.52 §3.9 source ↗

Differentiate: f(x)= ln(3x+2)5.

Answer

f ′ (x)= 15 3 x + 2

Checkpoint 3.53 §3.9 source ↗

Find the slope for the line tangent to y=3x at x=2.

Answer

9 ln ( 3 )

Checkpoint 3.54 §3.9 source ↗

Use logarithmic differentiation to find the derivative of y=xx.

Answer

d y d x = x x (1+lnx)

Checkpoint 3.55 §3.9 source ↗

Find the derivative of y=(tanx)π.

Answer

y ′ = π ( tan x ) π − 1 sec 2 x

3-331 §3.9 source ↗

For the following exercises, find f′(x) for each function.

f ( x ) = x 2 e x

Answer

2 x e x + x 2 e x

3-333 §3.9 source ↗

For the following exercises, find f′(x) for each function.

f ( x ) = e x 3 ln x

Answer

e x 3 ln x ( 3 x 2 ln x + x 2 )

3-335 §3.9 source ↗

For the following exercises, find f′(x) for each function.

f(x)= e x − e − x e x + e − x

Answer

4 ( e x + e − x ) 2

3-337 §3.9 source ↗

For the following exercises, find f′(x) for each function.

f(x)= 2 4 x + 4 x 2

Answer

2 4 x + 2 ·ln2+ 8x

3-339 §3.9 source ↗

For the following exercises, find f′(x) for each function.

f ( x ) = x π · π x

Answer

π x π − 1 · π x + x π · π x lnπ

3-341 §3.9 source ↗

For the following exercises, find f′(x) for each function.

f ( x ) = ln 5 x − 7

Answer

5 2 ( 5 x − 7 )

3-343 §3.9 source ↗

For the following exercises, find f′(x) for each function.

f(x)= log(secx)

Answer

tan x ln 10

3-345 §3.9 source ↗

For the following exercises, find f′(x) for each function.

f(x)= 2 x · log 3 7 x 2 − 4

Answer

2 x ·ln2· log 3 7 x 2 − 4 + 2 x · 2 x ln 7 ln 3

3-347 §3.9 source ↗

For the following exercises, use logarithmic differentiation to find dydx.

y = ( sin 2 x ) 4 x

Answer

( sin 2 x ) 4 x [ 4 · ln ( sin 2 x ) + 8 x · cot 2 x ]

3-349 §3.9 source ↗

For the following exercises, use logarithmic differentiation to find dydx.

y = x log 2 x

Answer

x log 2 x · 2 ln x x ln 2

3-351 §3.9 source ↗

For the following exercises, use logarithmic differentiation to find dydx.

y = x cot x

Answer

x cot x · [ − csc 2 x · ln x + cot x x ]

3-353 §3.9 source ↗

For the following exercises, use logarithmic differentiation to find dydx.

y= x −1 / 2 ( x 2 + 3 ) 2 / 3 ( 3 x − 4 ) 4

Answer

x −1 / 2 ( x 2 + 3 ) 2 / 3 ( 3 x − 4 ) 4 · [ −1 2 x + 4 x 3 ( x 2 + 3 ) + 12 3 x − 4 ]

3-355 §3.9 source ↗

For the following exercises, use logarithmic differentiation to find dydx.

[T] Find an equation of the line that is normal to the graph of f(x)=x·5x at the point where x=1. Graph both the function and the normal line.

Answer


The function starts at (−3, 0), decreases slightly and then increases through the origin and increases to (1.25, 10). There is a straight line marked T(x) with slope −1/(5 + 5 ln 5) and y intercept 5 + 1/(5 + 5 ln 5).


y= −15+5ln5x+ (5+15+5ln5)

3-357 §3.9 source ↗

For the following exercises, use logarithmic differentiation to find dydx.

Consider the function y=x1/x for x>0.

a. Determine the points on the graph where the tangent line is horizontal.

b. Determine the points on the graph where y′>0 and those where y′<0.

Answer

a. x=e~2.718 b. y' >  0 on (0, e);  y' <  0 on (e, ∞)

3-359 §3.9 source ↗

For the following exercises, use logarithmic differentiation to find dydx.

[T] The population of Toledo, Ohio, in 2000 was approximately 500,000. Assume the population is increasing at a rate of 5% per year.

a. Write the exponential function that relates the total population as a function of t.

b. Use a. to determine the rate at which the population is increasing in t years.

c. Use b. to determine the rate at which the population is increasing in 10 years.

Answer

a. P= 500,000(1.05)t individuals b. P′(t)= 24395·(1.05)t individuals per year c. 39,737 individuals per year

3-361 §3.9 source ↗

For the following exercises, use logarithmic differentiation to find dydx.

[T] The number of cases of influenza in New York City from the beginning of 1960 to the beginning of 1964 is modeled by the function

N(t)= 5.3e0.093t2−0.87t, (0≤t≤4), where N(t) gives the number of cases (in thousands) and t is measured in years, with t=0 corresponding to the beginning of 1960.

a. Show work that evaluates N(0) and N(4). Briefly describe what these values indicate about the disease in New York City.

b. Show work that evaluates N′(0) and N′(3). Briefly describe what these values indicate about the disease in New York City.

Answer

a. At the beginning of 1960 there were 5.3 thousand cases of the disease in New York City. At the beginning of 1964 there were approximately 723 cases of the disease in the United States. b. At the beginning of 1960 the number of cases of the disease was decreasing at rate of −4.611 thousand per year; at the beginning of 1963, the number of cases of the disease was decreasing at a rate of −0.2808 thousand per year.

3-363 §3.9 source ↗

For the following exercises, use the population of New York City from 1790 to 1860, given in the following table.

[T] Using a computer program or a calculator, fit a growth curve to the data of the form p=abt.

Table 3.8 New York City Population Over Time in the book ↗
Years since 1790 Population
0 33,131
10 60,515
20 96,373
30 123,706
40 202,300
50 312,710
60 515,547
70 813,669
Source: http://en.wikipedia.org/wiki/Largest_cities_in_the_United_States
_by_population_by_decade.

Answer

p= 35741 ( 1.045 ) t

3-365 §3.9 source ↗

For the following exercises, use the population of New York City from 1790 to 1860, given in the following table.

[T] Using the exponential best fit for the data, write a table containing the second derivatives evaluated at each year.

Table 3.8 New York City Population Over Time in the book ↗
Years since 1790 Population
0 33,131
10 60,515
20 96,373
30 123,706
40 202,300
50 312,710
60 515,547
70 813,669
Source: http://en.wikipedia.org/wiki/Largest_cities_in_the_United_States
_by_population_by_decade.

Answer

Years since 1790 P″
0 69.25
10 107.5
20 167.0
30 259.4
40 402.8
50 625.5
60 971.4
70 1508.5

3-367 §3.R source ↗

True or False? Justify the answer with a proof or a counterexample.

Every function has a derivative.

Answer

False.

3-369 §3.R source ↗

True or False? Justify the answer with a proof or a counterexample.

A continuous function has a derivative.

Answer

False

3-371 §3.R source ↗

Use the limit definition of the derivative to exactly evaluate the derivative.

f ( x ) = x + 4

Answer

1 2 x + 4

3-373 §3.R source ↗

Find the derivatives of the following functions.

f(x)= 3 x 3 − 4 x 2

Answer

9 x 2 + 8 x 3

3-375 §3.R source ↗

Find the derivatives of the following functions.

f ( x ) = e sin x

Answer

e sin x cos x

3-377 §3.R source ↗

Find the derivatives of the following functions.

f(x)= x 2 cosx+ xtan(x)

Answer

x sec 2 (x)+ 2xcos(x)+ tan(x)− x 2 sin(x)

3-379 §3.R source ↗

Find the derivatives of the following functions.

f(x)= x 4 sin −1 (x)

Answer

1 4 ( x 1 − x 2 + sin −1 ( x ) )

3-381 §3.R source ↗

Find the following derivatives of various orders.

First derivative of y= xln(x)cosx

Answer

cosx·(lnx+1)− xln(x)sinx

3-383 §3.R source ↗

Find the following derivatives of various orders.

Second derivative of y= 4x+ x2sin(x)

Answer

4 x ( ln 4 ) 2 + 2sinx+ 4xcosx− x 2 sinx

3-385 §3.R source ↗

Find an equation of the tangent line to the following equations at the specified point.

y=x+ex−1x at x=1

Answer

T = ( 2 + e ) x − 2

3-387 §3.R source ↗

Draw the derivative for the following graphs.

The function decreases linearly from (−1, 4) to the origin, at which point it increases as x2, passing through (1, 1) and (2, 4).

Answer


The function is the straight line y = −4 until x = 0, at which point it becomes a straight line starting at the origin with slope 2. There is no value assigned for this function at x = 0.

3-389 §3.R source ↗

The following questions concern the water level in Ocean City, New Jersey, in January, which can be approximated by w(t)= 1.9+ 2.9cos(π6t), where t is measured in hours after midnight, and the height is measured in feet.

Find w′(3). What is the physical meaning of this value?

Answer

w′(3)= − 2.9π6. At 3 a.m. the tide is decreasing at a rate of 1.518 ft/hr.

3-391 §3.R source ↗

The following questions consider the wind speeds of Hurricane Katrina, which affected New Orleans, Louisiana, in August 2005. The data are displayed in a table.

Estimate the derivative of the wind speed at hour 83. What is the physical meaning?

Table 3.9 Wind Speeds of Hurricane Katrina in the book ↗
Hours after Midnight, August 26 Wind Speed (mph)
1 45
5 75
11 100
29 115
49 145
58 175
73 155
81 125
85 95
107 35
Source: http://news.nationalgeographic.com/news/2005/09/0914_050914_katrina_timeline.html.

Answer

−7.5. The wind speed is decreasing at a rate of 7.5 mph/hr

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Problems and answers are adapted from Calculus Volume 1 by Gilbert Strang and Edwin “Jed” Herman, OpenStax, and are used under the CC BY-NC-SA 4.0 licence. Access for free at https://openstax.org/books/calculus-volume-1/pages/1-introduction. Illustrations: Copyright Rice University, OpenStax, under CC BY-NC-SA 4.0 license. This adaptation is released under the same licence, is non-commercial, and is neither affiliated with nor endorsed by OpenStax or Rice University.