Every problem in the chapter beside the book’s answer, a chapter at a time as you scroll.

Chapter 2: Solving Linear Equations and Inequalities

507 problems · 95 figures

Be Prepared 2.1 §2.1 source ↗

Evaluate x+4 when x=−3.
If you missed this problem, review Example 1.54.
Example 1.54 in the book ↗

Answer

1

Be Prepared 2.2 §2.1 source ↗

Evaluate 15−y when y=−5.
If you missed this problem, review Example 1.56.
Example 1.56 in the book ↗

Answer

20

Be Prepared 2.3 §2.1 source ↗

Simplify 4(4n+1)−15n.
If you missed this problem, review Example 1.138.
Example 1.138 in the book ↗

Answer

n + 4

Be Prepared 2.4 §2.1 source ↗

Translate into algebra “5 less than x.”
If you missed this problem, review Example 1.26.
Example 1.26 in the book ↗

Answer

x − 5

Try It 2.1 §2.1 source ↗

Is y=43 a solution of 9y+2=6y+3?

Answer

no

Try It 2.2 §2.1 source ↗

Is y=75 a solution of 5y+3=10y−4?

Answer

yes

Try It 2.3 §2.1 source ↗

Solve: x+19=−27.

Answer

x = −46

Try It 2.4 §2.1 source ↗

Solve: x+16=−34.

Answer

x = −50

Try It 2.5 §2.1 source ↗

Solve: n−61=−75.

Answer

n = −14

Try It 2.6 §2.1 source ↗

Solve: p−41=−73.

Answer

p = −32

Try It 2.7 §2.1 source ↗

Solve: p−23=56.

Answer

p = 9 6 = 3 2

Try It 2.8 §2.1 source ↗

Solve: q−12=56.

Answer

q = 4 3

Try It 2.9 §2.1 source ↗

Solve: b− 0.47= −2.1.

Answer

b = −1.63

Try It 2.10 §2.1 source ↗

Solve: c− 0.93= −4.6.

Answer

c = −3.67

Try It 2.11 §2.1 source ↗

Solve: 8y− 4− 7y− 7= 4.

Answer

y = 15

Try It 2.12 §2.1 source ↗

Solve: 6z+ 5− 5z− 4= 3.

Answer

z = 2

Try It 2.13 §2.1 source ↗

Solve: 5(p−3)− 4p= −10.

Answer

p = 5

Try It 2.14 §2.1 source ↗

Solve: 4(q+2)− 3q= −8.

Answer

q = −16

Try It 2.15 §2.1 source ↗

Solve: 4(2h−3)− 7h= 6(h−2)− 6(h−1).

Answer

h = 6

Try It 2.16 §2.1 source ↗

Solve: 2(5x+2)− 9x= 3(x−2)− 3(x−4).

Answer

x = 2

Try It 2.17 §2.1 source ↗

Translate and solve: Ten more than x is equal to 41.

Answer

x+ 10= 41; x= 31

Try It 2.18 §2.1 source ↗

Translate and solve: Twelve less than x is equal to 51.

Answer

x− 12= 51; x= 63

Try It 2.19 §2.1 source ↗

Translate and solve: The difference of 4x and 3x is 14.

Answer

4x− 3x= 14; x= 14

Try It 2.20 §2.1 source ↗

Translate and solve: The difference of 7a and 6a is −8.

Answer

7a− 6a= −8; a= −8

Try It 2.21 §2.1 source ↗

Translate into an algebraic equation and solve:

The Pappas family has two cats, Zeus and Athena. Together, they weigh 23 pounds. Zeus weighs 16 pounds. How much does Athena weigh?

Answer

7 pounds

Try It 2.22 §2.1 source ↗

Translate into an algebraic equation and solve:

Sam and Henry are roommates. Together, they have 68 books. Sam has 26 books. How many books does Henry have?

Answer

42 books

Try It 2.23 §2.1 source ↗

Translate into an algebraic equation and solve:

Eddie paid $19,875 for his new car. This was $1,025 less than the sticker price. What was the sticker price of the car?

Answer

$20,900

Try It 2.24 §2.1 source ↗

Translate into an algebraic equation and solve:

The admission price for the movies during the day is $7.75. This is $3.25 less the price at night. How much does the movie cost at night?

Answer

$11.00

2.1-1 §2.1 source ↗

Verify a Solution of an Equation

In the following exercises, determine whether the given value is a solution to the equation.

Is y=53 a solution of
6y+10=12y?

Answer

yes

2.1-3 §2.1 source ↗

Verify a Solution of an Equation

In the following exercises, determine whether the given value is a solution to the equation.

Is u=−12 a solution of
8u−1=6u?

Answer

no

2.1-5 §2.1 source ↗

Solve Equations using the Subtraction and Addition Properties of Equality

In the following exercises, solve each equation using the Subtraction and Addition Properties of Equality.

x + 24 = 35

Answer

x = 11

2.1-7 §2.1 source ↗

Solve Equations using the Subtraction and Addition Properties of Equality

In the following exercises, solve each equation using the Subtraction and Addition Properties of Equality.

y + 45 = −66

Answer

y = −111

2.1-9 §2.1 source ↗

Solve Equations using the Subtraction and Addition Properties of Equality

In the following exercises, solve each equation using the Subtraction and Addition Properties of Equality.

b + 1 4 = 3 4

Answer

b = 1 2

2.1-11 §2.1 source ↗

Solve Equations using the Subtraction and Addition Properties of Equality

In the following exercises, solve each equation using the Subtraction and Addition Properties of Equality.

p + 2.4 = −9.3

Answer

p = −11.7

2.1-13 §2.1 source ↗

Solve Equations using the Subtraction and Addition Properties of Equality

In the following exercises, solve each equation using the Subtraction and Addition Properties of Equality.

a − 45 = 76

Answer

a = 121

2.1-15 §2.1 source ↗

Solve Equations using the Subtraction and Addition Properties of Equality

In the following exercises, solve each equation using the Subtraction and Addition Properties of Equality.

m − 18 = −200

Answer

m = −182

2.1-17 §2.1 source ↗

Solve Equations using the Subtraction and Addition Properties of Equality

In the following exercises, solve each equation using the Subtraction and Addition Properties of Equality.

x − 1 3 = 2

Answer

x = 7 3

2.1-19 §2.1 source ↗

Solve Equations using the Subtraction and Addition Properties of Equality

In the following exercises, solve each equation using the Subtraction and Addition Properties of Equality.

y − 3.8 = 10

Answer

y = 13.8

2.1-21 §2.1 source ↗

Solve Equations using the Subtraction and Addition Properties of Equality

In the following exercises, solve each equation using the Subtraction and Addition Properties of Equality.

x − 165 = −420

Answer

x = −255

2.1-23 §2.1 source ↗

Solve Equations using the Subtraction and Addition Properties of Equality

In the following exercises, solve each equation using the Subtraction and Addition Properties of Equality.

z + 0.52 = −8.5

Answer

z = −9.02

2.1-25 §2.1 source ↗

Solve Equations using the Subtraction and Addition Properties of Equality

In the following exercises, solve each equation using the Subtraction and Addition Properties of Equality.

q + 3 4 = 1 2

Answer

q = − 1 4

2.1-27 §2.1 source ↗

Solve Equations using the Subtraction and Addition Properties of Equality

In the following exercises, solve each equation using the Subtraction and Addition Properties of Equality.

p − 2 5 = 2 3

Answer

p = 16 15

2.1-29 §2.1 source ↗

Solve Equations that Require Simplification

In the following exercises, solve each equation.

c + 31 − 10 = 46

Answer

c = 25

2.1-31 §2.1 source ↗

Solve Equations that Require Simplification

In the following exercises, solve each equation.

9x+ 5− 8x+ 14= 20

Answer

x = 1

2.1-33 §2.1 source ↗

Solve Equations that Require Simplification

In the following exercises, solve each equation.

−6x− 11+ 7x− 5= −16

Answer

x = 0

2.1-35 §2.1 source ↗

Solve Equations that Require Simplification

In the following exercises, solve each equation.

5(y−6)− 4y= −6

Answer

y = 24

2.1-37 §2.1 source ↗

Solve Equations that Require Simplification

In the following exercises, solve each equation.

8(u+1.5)− 7u= 4.9

Answer

u = −7.1

2.1-39 §2.1 source ↗

Solve Equations that Require Simplification

In the following exercises, solve each equation.

6a− 5(a−2)+ 9= −11

Answer

a = −30

2.1-41 §2.1 source ↗

Solve Equations that Require Simplification

In the following exercises, solve each equation.

6(y−2)− 5y= 4(y+3)
− 4 ( y − 1 )

Answer

y = 28

2.1-43 §2.1 source ↗

Solve Equations that Require Simplification

In the following exercises, solve each equation.

3(5n−1)− 14n+ 9
= 10(n−4)− 6n− 4(n+1)

Answer

n = −50

2.1-45 §2.1 source ↗

Solve Equations that Require Simplification

In the following exercises, solve each equation.

−(j+2)+ 2j− 1= 5

Answer

j = 8

2.1-47 §2.1 source ↗

Solve Equations that Require Simplification

In the following exercises, solve each equation.

−( 1 4 a− 3 4 )+ 5 4 a= −2

Answer

a = − 11 4

2.1-49 §2.1 source ↗

Solve Equations that Require Simplification

In the following exercises, solve each equation.

8(4x+5)− 5(6x)− x
= 53− 6(x+1)+ 3(2x+2)

Answer

x = 13

2.1-51 §2.1 source ↗

Translate to an Equation and Solve

In the following exercises, translate to an equation and then solve it.

Nine more than x is equal to 52.

Answer

x + 9 = 52 ; x = 43

2.1-53 §2.1 source ↗

Translate to an Equation and Solve

In the following exercises, translate to an equation and then solve it.

Ten less than m is −14.

Answer

m− 10= −14; m= −4

2.1-55 §2.1 source ↗

Translate to an Equation and Solve

In the following exercises, translate to an equation and then solve it.

The sum of y and −30 is 40.

Answer

y+ (−30)= 40; y= 70

2.1-57 §2.1 source ↗

Translate to an Equation and Solve

In the following exercises, translate to an equation and then solve it.

The difference of 9xand8x is 107.

Answer

9x− 8x= 107; 107

2.1-59 §2.1 source ↗

Translate to an Equation and Solve

In the following exercises, translate to an equation and then solve it.

The difference of n and 16 is 12.

Answer

n − 1 6 = 1 2 ; 2 3

2.1-61 §2.1 source ↗

Translate to an Equation and Solve

In the following exercises, translate to an equation and then solve it.

The sum of −4n and 5n is −82.

Answer

−4n+ 5n= −82; − 82

2.1-63 §2.1 source ↗

Translate and Solve Applications

In the following exercises, translate into an equation and solve.

Distance Avril rode her bike a total of 18 miles, from home to the library and then to the beach. The distance from Avril’s house to the library is 7 miles. What is the distance from the library to the beach?

Answer

11 miles

2.1-65 §2.1 source ↗

Translate and Solve Applications

In the following exercises, translate into an equation and solve.

Age Eva’s daughter is 15 years younger than her son. Eva’s son is 22 years old. How old is her daughter?

Answer

7 years old

2.1-67 §2.1 source ↗

Translate and Solve Applications

In the following exercises, translate into an equation and solve.

Groceries For a family birthday dinner, Celeste bought a turkey that weighed 5 pounds less than the one she bought for Thanksgiving. The birthday turkey weighed 16 pounds. How much did the Thanksgiving turkey weigh?

Answer

21 pounds

2.1-69 §2.1 source ↗

Translate and Solve Applications

In the following exercises, translate into an equation and solve.

Health Connor’s temperature was 0.7 degrees higher this morning than it had been last night. His temperature this morning was 101.2 degrees. What was his temperature last night?

Answer

100.5 degrees

2.1-71 §2.1 source ↗

Translate and Solve Applications

In the following exercises, translate into an equation and solve.

Salary Ron’s paycheck this week was $17.43 less than his paycheck last week. His paycheck this week was $103.76. How much was Ron’s paycheck last week?

Answer

$121.19

2.1-73 §2.1 source ↗

Translate and Solve Applications

In the following exercises, translate into an equation and solve.

Construction Miguel wants to drill a hole for a 58 inch screw. The hole should be 112 inch smaller than the screw. Let d equal the size of the hole he should drill. Solve the equation d+112=58 to see what size the hole should be.

Answer

d = 13 24 inch

2.1-75 §2.1 source ↗

Translate and Solve Applications

In the following exercises, translate into an equation and solve.

Is −8 a solution to the equation 3x=16−5x? How do you know?

Answer

No. Justifications will vary.

Be Prepared 2.5 §2.2 source ↗

Simplify: −7(1−7).
If you missed this problem, review Example 1.68.
Example 1.68 in the book ↗

Answer

1

Be Prepared 2.6 §2.2 source ↗

Evaluate 9x+2 when x=−3.
If you missed this problem, review Example 1.57.
Example 1.57 in the book ↗

Answer

− 25

Try It 2.25 §2.2 source ↗

Solve: 3y=−41.

Answer

y = −41 3

Try It 2.26 §2.2 source ↗

Solve: 4z=−55.

Answer

z = −55 4

Try It 2.27 §2.2 source ↗

Solve: a−7=−42.

Answer

a = 294

Try It 2.28 §2.2 source ↗

Solve: b−6=−24.

Answer

b = 144

Try It 2.29 §2.2 source ↗

Solve: −k=8.

Answer

k = −8

Try It 2.30 §2.2 source ↗

Solve: −g=3.

Answer

g = −3

Try It 2.31 §2.2 source ↗

Solve: 25n=14.

Answer

n = 35

Try It 2.32 §2.2 source ↗

Solve: 56y=15.

Answer

y = 18

Try It 2.33 §2.2 source ↗

Solve: 925=−45z.

Answer

z = − 9 20

Try It 2.34 §2.2 source ↗

Solve: 56=−83r.

Answer

r = − 5 16

Try It 2.35 §2.2 source ↗

Solve: 18− 27= 15c− 9c− 3c.

Answer

c = −3

Try It 2.36 §2.2 source ↗

Solve:18− 22= 12x− x− 4x.

Answer

x = − 4 7

Try It 2.37 §2.2 source ↗

Solve: −4(q−2)− 8= 24.

Answer

q = −6

Try It 2.38 §2.2 source ↗

Solve: −6(r−2)− 12= 30.

Answer

r = −5

Try It 2.39 §2.2 source ↗

Translate and solve: The number 132 is the product of −12 and y.

Answer

132= −12y; y= −11

Try It 2.40 §2.2 source ↗

Translate and solve: The number 117 is the product of −13 and z.

Answer

117= −13z; z= −9

Try It 2.41 §2.2 source ↗

Translate and solve: n divided by 7 is equal to −21.

Answer

n 7 = −21; n= −147

Try It 2.42 §2.2 source ↗

Translate and solve: n divided by 8 is equal to −56.

Answer

n 8 = −56; n= −448

Try It 2.43 §2.2 source ↗

Translate and solve: The quotient of q and −8 is 72.

Answer

q −8 = 72; q= −576

Try It 2.44 §2.2 source ↗

Translate and solve: The quotient of p and −9 is 81.

Answer

p −9 = 81; p= −729

Try It 2.45 §2.2 source ↗

Translate and solve: Two-fifths of f is 16.

Answer

2 5 f = 16 ; f = 40

Try It 2.46 §2.2 source ↗

Translate and solve: Three-fourths of f is 21.

Answer

3 4 f = 21 ; f = 28

Try It 2.47 §2.2 source ↗

Translate and solve: The sum of five-eighths and x is one-fourth.

Answer

5 8 + x= 1 4 ; x= − 3 8

Try It 2.48 §2.2 source ↗

Translate and solve: The sum of three-fourths and x is five-sixths.

Answer

3 4 + x= 5 6 ; x= 1 12

Try It 2.49 §2.2 source ↗

Translate and solve:

Arianna bought a 24-pack of water bottles for $9.36. What was the cost of one water bottle?

Answer

$0.39

Try It 2.50 §2.2 source ↗

Translate and solve:

At JB’s Bowling Alley, 6 people can play on one lane for $34.98. What is the cost for each person?

Answer

$5.83

Try It 2.51 §2.2 source ↗

Translate and solve:

The annual property tax on the Mehta’s house is $1,800, calculated as 151,000 of the assessed value of the house. What is the assessed value of the Mehta’s house?

Answer

$120,000

Try It 2.52 §2.2 source ↗

Translate and solve:

Stella planted 14 flats of flowers in 23 of her garden. How many flats of flowers would she need to fill the whole garden?

Answer

21 flats

2.2-77 §2.2 source ↗

Solve Equations Using the Division and Multiplication Properties of Equality

In the following exercises, solve each equation using the Division and Multiplication Properties of Equality and check the solution.

8 x = 56

Answer

x = 7

2.2-79 §2.2 source ↗

Solve Equations Using the Division and Multiplication Properties of Equality

In the following exercises, solve each equation using the Division and Multiplication Properties of Equality and check the solution.

−5 c = 55

Answer

c = −11

2.2-81 §2.2 source ↗

Solve Equations Using the Division and Multiplication Properties of Equality

In the following exercises, solve each equation using the Division and Multiplication Properties of Equality and check the solution.

−809 = 15 y

Answer

y = − 809 15

2.2-83 §2.2 source ↗

Solve Equations Using the Division and Multiplication Properties of Equality

In the following exercises, solve each equation using the Division and Multiplication Properties of Equality and check the solution.

−37 p = −541

Answer

p = 541 37

2.2-85 §2.2 source ↗

Solve Equations Using the Division and Multiplication Properties of Equality

In the following exercises, solve each equation using the Division and Multiplication Properties of Equality and check the solution.

0.25 z = 3.25

Answer

z = 13

2.2-87 §2.2 source ↗

Solve Equations Using the Division and Multiplication Properties of Equality

In the following exercises, solve each equation using the Division and Multiplication Properties of Equality and check the solution.

−13 x = 0

Answer

x = 0

2.2-89 §2.2 source ↗

Solve Equations Using the Division and Multiplication Properties of Equality

In the following exercises, solve each equation using the Division and Multiplication Properties of Equality and check the solution.

x 4 = 35

Answer

x = 140

2.2-91 §2.2 source ↗

Solve Equations Using the Division and Multiplication Properties of Equality

In the following exercises, solve each equation using the Division and Multiplication Properties of Equality and check the solution.

−20 = q −5

Answer

q = 100

2.2-93 §2.2 source ↗

Solve Equations Using the Division and Multiplication Properties of Equality

In the following exercises, solve each equation using the Division and Multiplication Properties of Equality and check the solution.

y 9 = −16

Answer

y = −144

2.2-95 §2.2 source ↗

Solve Equations Using the Division and Multiplication Properties of Equality

In the following exercises, solve each equation using the Division and Multiplication Properties of Equality and check the solution.

m −12 = 45

Answer

m = −540

2.2-97 §2.2 source ↗

Solve Equations Using the Division and Multiplication Properties of Equality

In the following exercises, solve each equation using the Division and Multiplication Properties of Equality and check the solution.

− y = 6

Answer

y = −6

2.2-99 §2.2 source ↗

Solve Equations Using the Division and Multiplication Properties of Equality

In the following exercises, solve each equation using the Division and Multiplication Properties of Equality and check the solution.

− v = −72

Answer

v = 72

2.2-101 §2.2 source ↗

Solve Equations Using the Division and Multiplication Properties of Equality

In the following exercises, solve each equation using the Division and Multiplication Properties of Equality and check the solution.

2 3 y = 48

Answer

y = 72

2.2-103 §2.2 source ↗

Solve Equations Using the Division and Multiplication Properties of Equality

In the following exercises, solve each equation using the Division and Multiplication Properties of Equality and check the solution.

− 5 8 w = 40

Answer

w = −64

2.2-105 §2.2 source ↗

Solve Equations Using the Division and Multiplication Properties of Equality

In the following exercises, solve each equation using the Division and Multiplication Properties of Equality and check the solution.

− 2 5 = 1 10 a

Answer

a = −4

2.2-107 §2.2 source ↗

Solve Equations Using the Division and Multiplication Properties of Equality

In the following exercises, solve each equation using the Division and Multiplication Properties of Equality and check the solution.

− 7 10 x = − 14 3

Answer

x = 20 3

2.2-109 §2.2 source ↗

Solve Equations Using the Division and Multiplication Properties of Equality

In the following exercises, solve each equation using the Division and Multiplication Properties of Equality and check the solution.

7 12 = − 3 4 p

Answer

p = − 7 9

2.2-111 §2.2 source ↗

Solve Equations Using the Division and Multiplication Properties of Equality

In the following exercises, solve each equation using the Division and Multiplication Properties of Equality and check the solution.

− 5 18 = − 10 9 u

Answer

u = 1 4

2.2-113 §2.2 source ↗

Solve Equations That Require Simplification

In the following exercises, solve each equation requiring simplification.

100− 16= 4p− 10p− p

Answer

p = −12

2.2-115 §2.2 source ↗

Solve Equations That Require Simplification

In the following exercises, solve each equation requiring simplification.

7 8 n − 3 4 n = 9 + 2

Answer

n = 88

2.2-117 §2.2 source ↗

Solve Equations That Require Simplification

In the following exercises, solve each equation requiring simplification.

0.25d+ 0.10d= 6− 0.75

Answer

d = 15

2.2-119 §2.2 source ↗

Solve Equations That Require Simplification

In the following exercises, solve each equation requiring simplification.

−10(q−4)− 57= 93

Answer

q = −11

2.2-121 §2.2 source ↗

Solve Equations That Require Simplification

In the following exercises, solve each equation requiring simplification.

−10(x+4)− 19= 85

Answer

x = − 72 5

2.2-123 §2.2 source ↗

Mixed Practice

In the following exercises, solve each equation.

9 10 x = 90

Answer

x = 100

2.2-125 §2.2 source ↗

Mixed Practice

In the following exercises, solve each equation.

y + 46 = 55

Answer

y = 9

2.2-127 §2.2 source ↗

Mixed Practice

In the following exercises, solve each equation.

w −2 = 99

Answer

w = −198

2.2-129 §2.2 source ↗

Mixed Practice

In the following exercises, solve each equation.

27 = 6 a

Answer

a = 9 2

2.2-131 §2.2 source ↗

Mixed Practice

In the following exercises, solve each equation.

− x = 2

Answer

x = −2

2.2-133 §2.2 source ↗

Mixed Practice

In the following exercises, solve each equation.

m − 41 = −14

Answer

m = 27

2.2-135 §2.2 source ↗

Mixed Practice

In the following exercises, solve each equation.

63.90 = 0.03 p

Answer

p = 2130

2.2-137 §2.2 source ↗

Mixed Practice

In the following exercises, solve each equation.

84 = −12 z

Answer

z = −7

2.2-139 §2.2 source ↗

Mixed Practice

In the following exercises, solve each equation.

c− 0.3c= 35.70

Answer

c = 51

2.2-141 §2.2 source ↗

Mixed Practice

In the following exercises, solve each equation.

− x = −8

Answer

x = 8

2.2-143 §2.2 source ↗

Translate to an Equation and Solve

In the following exercises, translate to an equation and then solve.

133 is the product of −19 and n.

Answer

133= −19n; n= −7

2.2-145 §2.2 source ↗

Translate to an Equation and Solve

In the following exercises, translate to an equation and then solve.

−152 is the product of 8 and q.

Answer

−152= 8q; q= −19

2.2-147 §2.2 source ↗

Translate to an Equation and Solve

In the following exercises, translate to an equation and then solve.

r divided by 12 is equal to −48.

Answer

r 12 = −48; r= −576

2.2-149 §2.2 source ↗

Translate to an Equation and Solve

In the following exercises, translate to an equation and then solve.

j divided by −20 is equal to −80.

Answer

j −20 = −80; j= 1,600

2.2-151 §2.2 source ↗

Translate to an Equation and Solve

In the following exercises, translate to an equation and then solve.

The quotient of b and −6 is 18.

Answer

b −6 = 18; b= −108

2.2-153 §2.2 source ↗

Translate to an Equation and Solve

In the following exercises, translate to an equation and then solve.

The quotient k and 22 is −66.

Answer

k 22 = −66; k= −1,452

2.2-155 §2.2 source ↗

Translate to an Equation and Solve

In the following exercises, translate to an equation and then solve.

Three-tenths of x is 15.

Answer

3 10 x= 15; x= 50

2.2-157 §2.2 source ↗

Translate to an Equation and Solve

In the following exercises, translate to an equation and then solve.

Five-halves of v is 50.

Answer

5 2 v = 50 ; v = 20

2.2-159 §2.2 source ↗

Translate to an Equation and Solve

In the following exercises, translate to an equation and then solve.

The sum of two-fifths and f is one-half.

Answer

2 5 + f= 1 2 ; f= 1 10

2.2-161 §2.2 source ↗

Translate to an Equation and Solve

In the following exercises, translate to an equation and then solve.

The difference of q and one-eighth is three-fourths.

Answer

q− 1 8 = 3 4 ; q= 7 8

2.2-163 §2.2 source ↗

Translate and Solve Applications

In the following exercises, translate into an equation and solve.

Balloons Ramona bought 18 balloons for a party. She wants to make 3 equal bunches. How many balloons did she use in each bunch?

Answer

6 balloons

2.2-165 §2.2 source ↗

Translate and Solve Applications

In the following exercises, translate into an equation and solve.

Shopping Serena paid $12.96 for a pack of 12 pairs of sport socks. What was the price of pair of sport socks?

Answer

$1.08

2.2-167 §2.2 source ↗

Translate and Solve Applications

In the following exercises, translate into an equation and solve.

MPG John’s SUV gets 18 miles per gallon (mpg). This is half as many mpg as his wife’s hybrid car. How many miles per gallon does the hybrid car get?

Answer

36 mpg

2.2-169 §2.2 source ↗

Translate and Solve Applications

In the following exercises, translate into an equation and solve.

Real estate Bea earned $11,700 commission for selling a house, calculated as 6100 of the selling price. What was the selling price of the house?

Answer

$195,000

2.2-171 §2.2 source ↗

Translate and Solve Applications

In the following exercises, translate into an equation and solve.

Stamps Travis bought $9.45 worth of 49-cent stamps and 21-cent stamps. The number of 21-cent stamps was 5 less than the number of 49-cent stamps. Solve the equation 0.49s+ 0.21​(s−5)​​= 9.45 for s, to find the number of 49-cent stamps Travis bought.

Answer

15 49-cent stamps

2.2-173 §2.2 source ↗

Translate and Solve Applications

In the following exercises, translate into an equation and solve.

Emiliano thinks x=40 is the solution to the equation 12x=80. Explain why he is wrong.

Answer

Answers will vary.

Be Prepared 2.7 §2.3 source ↗

Simplify: 4y−9+9.
If you missed this problem, review Example 1.129.
Example 1.129 in the book ↗

Answer

4 y

Try It 2.53 §2.3 source ↗

Solve: 3x+4=−8.

Answer

x = −4

Try It 2.54 §2.3 source ↗

Solve: 5a+3=−37.

Answer

a = −8

Try It 2.55 §2.3 source ↗

Solve: 5y−9=16.

Answer

y = 5

Try It 2.56 §2.3 source ↗

Solve: 3m−8=19.

Answer

m = 9

Try It 2.57 §2.3 source ↗

Solve: 6n=5n−10.

Answer

n = −10

Try It 2.58 §2.3 source ↗

Solve: −6c=−7c−1.

Answer

c = −1

Try It 2.59 §2.3 source ↗

Solve: 3p−14=5p.

Answer

p = −7

Try It 2.60 §2.3 source ↗

Solve: 8m+9=5m.

Answer

m = −3

Try It 2.61 §2.3 source ↗

Solve: 12j=−4j+32.

Answer

j = 2

Try It 2.62 §2.3 source ↗

Solve: 8h=−4h+12.

Answer

h = 1

Try It 2.63 §2.3 source ↗

Solve: 12x+8=6x+2.

Answer

x = −1

Try It 2.64 §2.3 source ↗

Solve: 9y+4=7y+12.

Answer

y = 4

Try It 2.65 §2.3 source ↗

Solve: 8q−5=−4q+7.

Answer

q = 1

Try It 2.66 §2.3 source ↗

Solve: 7n−3=n+3.

Answer

n = 1

Try It 2.67 §2.3 source ↗

Solve: 2a−2=6a+18.

Answer

a = −5

Try It 2.68 §2.3 source ↗

Solve: 4k−1=7k+17.

Answer

k = −6

Try It 2.69 §2.3 source ↗

Solve: 78x− 12= − 18x− 2.

Answer

x = 10

Try It 2.70 §2.3 source ↗

Solve: 76y+ 11= 16y+ 8.

Answer

y = −3

Try It 2.71 §2.3 source ↗

Solve: 2.8x+ 12= −1.4x− 9.

Answer

x = −5

Try It 2.72 §2.3 source ↗

Solve: 3.6y+ 8= 1.2y− 4.

Answer

y = −5

2.3-175 §2.3 source ↗

Solve Equations with Constants on Both Sides

In the following exercises, solve the following equations with constants on both sides.

12 x − 8 = 64

Answer

x = 6

2.3-177 §2.3 source ↗

Solve Equations with Constants on Both Sides

In the following exercises, solve the following equations with constants on both sides.

15 y + 7 = 97

Answer

y = 6

2.3-179 §2.3 source ↗

Solve Equations with Constants on Both Sides

In the following exercises, solve the following equations with constants on both sides.

3 m + 9 = −15

Answer

m = −8

2.3-181 §2.3 source ↗

Solve Equations with Constants on Both Sides

In the following exercises, solve the following equations with constants on both sides.

−77 = 9 b − 5

Answer

b = −8

2.3-183 §2.3 source ↗

Solve Equations with Constants on Both Sides

In the following exercises, solve the following equations with constants on both sides.

60 = −21 x − 24

Answer

x = −4

2.3-185 §2.3 source ↗

Solve Equations with Constants on Both Sides

In the following exercises, solve the following equations with constants on both sides.

−14 q − 2 = 16

Answer

q = − 9 7

2.3-187 §2.3 source ↗

Solve Equations with Variables on Both Sides

In the following exercises, solve the following equations with variables on both sides.

21 k = 20 k − 11

Answer

k = −11

2.3-189 §2.3 source ↗

Solve Equations with Variables on Both Sides

In the following exercises, solve the following equations with variables on both sides.

8 x + 27 = 11 x

Answer

x = 9

2.3-191 §2.3 source ↗

Solve Equations with Variables on Both Sides

In the following exercises, solve the following equations with variables on both sides.

b = −4 b − 15

Answer

b = −3

2.3-193 §2.3 source ↗

Solve Equations with Variables on Both Sides

In the following exercises, solve the following equations with variables on both sides.

5 z = 39 − 8 z

Answer

z = 3

2.3-195 §2.3 source ↗

Solve Equations with Variables on Both Sides

In the following exercises, solve the following equations with variables on both sides.

4 x + 3 4 = 3 x

Answer

x = − 3 4

2.3-197 §2.3 source ↗

Solve Equations with Variables on Both Sides

In the following exercises, solve the following equations with variables on both sides.

−11 r − 8 = −7 r

Answer

r = −2

2.3-199 §2.3 source ↗

Solve Equations with Variables and Constants on Both Sides

In the following exercises, solve the following equations with variables and constants on both sides.

6 x − 17 = 5 x + 2

Answer

x = 19

2.3-201 §2.3 source ↗

Solve Equations with Variables and Constants on Both Sides

In the following exercises, solve the following equations with variables and constants on both sides.

21+ 18f= 19f+ 14

Answer

f = 7

2.3-203 §2.3 source ↗

Solve Equations with Variables and Constants on Both Sides

In the following exercises, solve the following equations with variables and constants on both sides.

12 q − 5 = 9 q − 20

Answer

q = −5

2.3-205 §2.3 source ↗

Solve Equations with Variables and Constants on Both Sides

In the following exercises, solve the following equations with variables and constants on both sides.

8 c + 7 = −3 c − 37

Answer

c = −4

2.3-207 §2.3 source ↗

Solve Equations with Variables and Constants on Both Sides

In the following exercises, solve the following equations with variables and constants on both sides.

7x− 17= −8x+ 13

Answer

x = 2

2.3-209 §2.3 source ↗

Solve Equations with Variables and Constants on Both Sides

In the following exercises, solve the following equations with variables and constants on both sides.

9 p + 14 = 6 + 4 p

Answer

p = − 8 5

2.3-211 §2.3 source ↗

Solve Equations with Variables and Constants on Both Sides

In the following exercises, solve the following equations with variables and constants on both sides.

3 y − 4 = 12 − y

Answer

y = 4

2.3-213 §2.3 source ↗

Solve Equations with Variables and Constants on Both Sides

In the following exercises, solve the following equations with variables and constants on both sides.

7 4 m− 7= 3 4 m− 13

Answer

m = −6

2.3-215 §2.3 source ↗

Solve Equations with Variables and Constants on Both Sides

In the following exercises, solve the following equations with variables and constants on both sides.

11− 1 5 a= 4 5 a+ 4

Answer

a = 7

2.3-217 §2.3 source ↗

Solve Equations with Variables and Constants on Both Sides

In the following exercises, solve the following equations with variables and constants on both sides.

5 4 a+ 15= 3 4 a− 5

Answer

a = −40

2.3-219 §2.3 source ↗

Solve Equations with Variables and Constants on Both Sides

In the following exercises, solve the following equations with variables and constants on both sides.

3 5 p + 2 = 4 5 p − 1

Answer

p = 15

2.3-221 §2.3 source ↗

Solve Equations with Variables and Constants on Both Sides

In the following exercises, solve the following equations with variables and constants on both sides.

13z+ 6.45= 8z+ 23.75

Answer

z = 3.46

2.3-223 §2.3 source ↗

Solve Equations with Variables and Constants on Both Sides

In the following exercises, solve the following equations with variables and constants on both sides.

2.7w− 80= 1.2w+ 10

Answer

w = 60

2.3-225 §2.3 source ↗

Solve Equations with Variables and Constants on Both Sides

In the following exercises, solve the following equations with variables and constants on both sides.

6.6x− 18.9= 3.4x+ 54.7

Answer

x = 23

2.3-227 §2.3 source ↗

Solve Equations with Variables and Constants on Both Sides

In the following exercises, solve the following equations with variables and constants on both sides.

Making a fence Jovani has 150 feet of fencing to make a rectangular garden in his backyard. He wants the length to be 15 feet more than the width. Find the width, w, by solving the equation 150= 2w+ 30+ 2w.

Answer

30 feet

2.3-229 §2.3 source ↗

Solve Equations with Variables and Constants on Both Sides

In the following exercises, solve the following equations with variables and constants on both sides.

Solve the equation 10x+ 14= −2x+ 38 explaining all the steps of your solution as in the examples in this section.

Answer

x=2 Justifications will vary.

2.3-231 §2.3 source ↗

Solve Equations with Variables and Constants on Both Sides

In the following exercises, solve the following equations with variables and constants on both sides.

Is x=−2 a solution to the equation 5−2x=−4x+1 ? How do you know?

Answer

Yes. Justifications will vary.

Be Prepared 2.8 §2.4 source ↗

Simplify: −(a−4).
If you missed this problem, review Example 1.137.
Example 1.137 in the book ↗

Answer

− a + 4

Be Prepared 2.9 §2.4 source ↗

Multiply: 32(12x+20).
If you missed this problem, review Example 1.133.
Example 1.133 in the book ↗

Answer

18 x + 30

Be Prepared 2.10 §2.4 source ↗

Simplify: 5−2(n+1).
If you missed this problem, review Example 1.138.
Example 1.138 in the book ↗

Answer

3 − 2 n

Be Prepared 2.11 §2.4 source ↗

Multiply: 3(7y+9).
If you missed this problem, review Example 1.132.
Example 1.132 in the book ↗

Answer

21 y + 27

Be Prepared 2.12 §2.4 source ↗

Multiply: (2.5)(6.4).
If you missed this problem, review Example 1.97.
Example 1.97 in the book ↗

Answer

16

Try It 2.73 §2.4 source ↗

Solve: 5(x+3)=35.

Answer

x = 4

Try It 2.74 §2.4 source ↗

Solve: 6(y−4)=−18.

Answer

y = 1

Try It 2.75 §2.4 source ↗

Solve: −(y+8)=−2.

Answer

y = −6

Try It 2.76 §2.4 source ↗

Solve: −(z+4)=−12.

Answer

z = 8

Try It 2.77 §2.4 source ↗

Solve: 2(m−4)+3=−1.

Answer

m = 2

Try It 2.78 §2.4 source ↗

Solve: 7(n−3)− 8= −15.

Answer

n = 2

Try It 2.79 §2.4 source ↗

Solve: 13(6u+3)= 7− u.

Answer

u = 2

Try It 2.80 §2.4 source ↗

Solve: 23(9x−12)= 8+ 2x.

Answer

x = 4

Try It 2.81 §2.4 source ↗

Solve: 12− 3(4j+3)= −17.

Answer

j = 5 3

Try It 2.82 §2.4 source ↗

Solve: −6− 8(k−2)= −10.

Answer

k = 5 2

Try It 2.83 §2.4 source ↗

Solve: 6(p−3)− 7= 5(4p+3)− 12.

Answer

p = −2

Try It 2.84 §2.4 source ↗

Solve: 8(q+1)− 5= 3(2q−4)− 1.

Answer

q = −8

Try It 2.85 §2.4 source ↗

Solve: 6[4−2(7y−1)]= 8(13−8y).

Answer

y = − 17 5

Try It 2.86 §2.4 source ↗

Solve: 12[1−5(4z−1)]= 3(24+11z).

Answer

z = 0

Try It 2.87 §2.4 source ↗

Solve: 0.55(100n+8)= 0.6(85n+14).

Answer

n = 1

Try It 2.88 §2.4 source ↗

Solve: 0.15(40m−120)= 0.5(60m+12).

Answer

m = −1

Try It 2.89 §2.4 source ↗

Classify the equation as a conditional equation, an identity, or a contradiction and then state the solution:

4+ 9(3x−7)= −42x− 13+ 23(3x−2)

Answer

identity; all real numbers

Try It 2.90 §2.4 source ↗

Classify the equation as a conditional equation, an identity, or a contradiction and then state the solution:

8(1−3x)+ 15(2x+7)= 2(x+50)+ 4(x+3)+ 1

Answer

identity; all real numbers

Try It 2.91 §2.4 source ↗

Classify the equation as a conditional equation, an identity, or a contradiction and then state the solution: 11(q+3)− 5= 19

Answer

conditional equation; q=–911

Try It 2.92 §2.4 source ↗

Classify the equation as a conditional equation, an identity, or a contradiction and then state the solution: 6+ 14(k−8)= 95

Answer

conditional equation; k=20114

Try It 2.93 §2.4 source ↗

Classify the equation as a conditional equation, an identity, or a contradiction and then state the solution:

12c+ 5(5+3c)= 3(9c−4)

Answer

contradiction; no solution

Try It 2.94 §2.4 source ↗

Classify the equation as a conditional equation, an identity, or a contradiction and then state the solution:

4(7d+18)= 13(3d−2)− 11d

Answer

contradiction; no solution

2.4-233 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

21 ( y − 5 ) = −42

Answer

y = 3

2.4-235 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

−16(3n+4)= 32

Answer

n = −2

2.4-237 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

5 ( 8 + 6 p ) = 0

Answer

p = − 4 3

2.4-239 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

− ( t − 19 ) = 28

Answer

t = −9

2.4-241 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

8(9b−4)− 12= 100

Answer

b = 2

2.4-243 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

21+ 2(m−4)= 25

Answer

m = 6

2.4-245 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

−6+ 6(5−k)= 15

Answer

k = 3 2

2.4-247 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

8(6t−5)− 35= −27

Answer

t = 1

2.4-249 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

−2(11−7x)+ 54= 4

Answer

x = −2

2.4-251 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

3 5 (10x−5)= 27

Answer

x = 5

2.4-253 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

1 4 (20d+12)= d+ 7

Answer

d = 1

2.4-255 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

15− (3r+8)= 28

Answer

r = −7

2.4-257 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

−3 − ( m − 1 ) = 13

Answer

m = −15

2.4-259 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

18− 2(y−3)= 32

Answer

y = −4

2.4-261 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

35− 5(2w+8)= −10

Answer

w = 1 2

2.4-263 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

−2(a−6)= 4(a−3)

Answer

a = 4

2.4-265 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

5(8−r)= −2(2r−16)

Answer

r = 8

2.4-267 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

9(2m−3)− 8= 4m+ 7

Answer

m = 3

2.4-269 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

−15+ 4(2−5y)= −7(y−4)+ 4

Answer

y = −3

2.4-271 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

5(x−4)− 4x= 14

Answer

x = 34

2.4-273 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

−12+ 8(x−5)= −4+ 3(5x−2)

Answer

x = −6

2.4-275 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

7(2n−5)= 8(4n−1)− 9

Answer

n = −1

2.4-277 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

3(a−2)− (a+6)= 4(a−1)

Answer

a = −4

2.4-279 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

−(7m+4)− (2m−5)
= 14 − ( 5 m − 3 )

Answer

m = −4

2.4-281 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

5 [ 9 − 2 ( 6 d − 1 ) ]
= 11(4−10d)− 139

Answer

d = −3

2.4-283 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

3 [ −14 + 2 ( 15 k − 6 ) ]
= 8 ( 3 − 5 k ) − 24

Answer

k = 3 5

2.4-285 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

10 [ 5 ( n + 1 ) + 4 ( n − 1 ) ]
= 11[7(5+n)−(25−3n)]

Answer

n = −5

2.4-287 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

4(2.5v−0.6)= 7.6

Answer

v = 1

2.4-289 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

0.2(p−6)= 0.4(p+14)

Answer

p = −34

2.4-291 §2.4 source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

0.5(16m+34)= −15

Answer

m = −4

2.4-293 §2.4 source ↗

Classify Equations

In the following exercises, classify each equation as a conditional equation, an identity, or a contradiction and then state the solution.

15y+ 32= 2(10y−7)− 5y+ 46

Answer

identity; all real numbers

2.4-295 §2.4 source ↗

Classify Equations

In the following exercises, classify each equation as a conditional equation, an identity, or a contradiction and then state the solution.

9(a−4)+ 3(2a+5)= 7(3a−4)− 6a+ 7

Answer

identity; all real numbers

2.4-297 §2.4 source ↗

Classify Equations

In the following exercises, classify each equation as a conditional equation, an identity, or a contradiction and then state the solution.

24(3d−4)+ 100= 52

Answer

conditional equation; d=23

2.4-299 §2.4 source ↗

Classify Equations

In the following exercises, classify each equation as a conditional equation, an identity, or a contradiction and then state the solution.

30(2n−1)= 5(10n+8)

Answer

conditional equation; n=7

2.4-301 §2.4 source ↗

Classify Equations

In the following exercises, classify each equation as a conditional equation, an identity, or a contradiction and then state the solution.

18u− 51= 9(4u+5)− 6(3u−10)

Answer

contradiction; no solution

2.4-303 §2.4 source ↗

Classify Equations

In the following exercises, classify each equation as a conditional equation, an identity, or a contradiction and then state the solution.

5(p+4)+ 8(2p−1)= 9(3p−5)− 6(p−2)

Answer

contradiction; no solution

2.4-305 §2.4 source ↗

Classify Equations

In the following exercises, classify each equation as a conditional equation, an identity, or a contradiction and then state the solution.

9(4k−7)= 11(3k+1)+ 4

Answer

conditional equation; k=26

2.4-307 §2.4 source ↗

Classify Equations

In the following exercises, classify each equation as a conditional equation, an identity, or a contradiction and then state the solution.

60(2x−1)= 15(8x+5)

Answer

contradiction; no solution

2.4-309 §2.4 source ↗

Classify Equations

In the following exercises, classify each equation as a conditional equation, an identity, or a contradiction and then state the solution.

36(4m+5)= 12(12m+15)

Answer

identity; all real numbers

2.4-311 §2.4 source ↗

Classify Equations

In the following exercises, classify each equation as a conditional equation, an identity, or a contradiction and then state the solution.

11(8c+5)− 8c= 2(40c+25)+ 5

Answer

identity; all real numbers

2.4-313 §2.4 source ↗

Classify Equations

In the following exercises, classify each equation as a conditional equation, an identity, or a contradiction and then state the solution.

Coins Rhonda has $1.90 in nickels and dimes. The number of dimes is one less than twice the number of nickels. Find the number of nickels, n, by solving the equation 0.05n+ 0.10(2n−1)= 1.90.

Answer

8 nickels

2.4-315 §2.4 source ↗

Classify Equations

In the following exercises, classify each equation as a conditional equation, an identity, or a contradiction and then state the solution.

Explain why you should simplify both sides of an equation as much as possible before collecting the variable terms to one side and the constant terms to the other side.

Answer

Answers will vary.

2.4-317 §2.4 source ↗

Classify Equations

In the following exercises, classify each equation as a conditional equation, an identity, or a contradiction and then state the solution.

Solve the equation 14(8x+20)= 3x− 4 explaining all the steps of your solution as in the examples in this section.

Answer

Answers will vary.

Be Prepared 2.13 §2.5 source ↗

Multiply: 8·38.
If you missed this problem, review Example 1.69.
Example 1.69 in the book ↗

Answer

3

Be Prepared 2.14 §2.5 source ↗

Find the LCD of 56 and 14.
If you missed this problem, review Example 1.82.
Example 1.82 in the book ↗

Answer

12

Be Prepared 2.15 §2.5 source ↗

Multiply 4.78 by 100.
If you missed this problem, review Example 1.98.
Example 1.98 in the book ↗

Answer

478

Try It 2.95 §2.5 source ↗

Solve: 14x+12=58.

Answer

x = 1 2

Try It 2.96 §2.5 source ↗

Solve: 18x+12=14.

Answer

x = −2

Try It 2.97 §2.5 source ↗

Solve: 7= 12x+ 34x− 23x.

Answer

x = 12

Try It 2.98 §2.5 source ↗

Solve: −1= 12u+ 14u− 23u.

Answer

u = −12

Try It 2.99 §2.5 source ↗

Solve: x+13=16x−12.

Answer

x = −1

Try It 2.100 §2.5 source ↗

Solve: c+34=12c−14.

Answer

c = −2

Try It 2.101 §2.5 source ↗

Solve: −11= 12(6p+2).

Answer

p = −4

Try It 2.102 §2.5 source ↗

Solve: 8=13(9q+6).

Answer

q = 2

Try It 2.103 §2.5 source ↗

Solve: 15(n+3)= 14(n+2).

Answer

n = 2

Try It 2.104 §2.5 source ↗

Solve: 12(m−3)= 14(m−7).

Answer

m = −1

Try It 2.105 §2.5 source ↗

Solve: 4y−73=y6.

Answer

y = 2

Try It 2.106 §2.5 source ↗

Solve: −2z−54=z8.

Answer

z = −2

Try It 2.107 §2.5 source ↗

Solve: b10+2=b4+5.

Answer

b = −20

Try It 2.108 §2.5 source ↗

Solve: c6+3=c3+4.

Answer

c = −6

Try It 2.109 §2.5 source ↗

Solve: 3r+56+ 1= 4r+33.

Answer

r = 1

Try It 2.110 §2.5 source ↗

Solve: 2s+32+ 1= 3s+24.

Answer

s = −8

Try It 2.111 §2.5 source ↗

Solve: 0.14h+ 0.12= 0.35h− 2.4.

Answer

h = 12

Try It 2.112 §2.5 source ↗

Solve: 0.65k− 0.1= 0.4k− 0.35.

Answer

k = −1

Try It 2.113 §2.5 source ↗

Solve: 0.25n+ 0.05(n+5)= 2.95.

Answer

n = 9

Try It 2.114 §2.5 source ↗

Solve: 0.10d+ 0.05(d−5)= 2.15.

Answer

d = 16

2.5-319 §2.5 source ↗

Solve Equations with Fraction Coefficients

In the following exercises, solve each equation with fraction coefficients.

3 4 x − 1 2 = 1 4

Answer

x = 1

2.5-321 §2.5 source ↗

Solve Equations with Fraction Coefficients

In the following exercises, solve each equation with fraction coefficients.

5 6 y − 1 3 = − 7 6

Answer

y = −1

2.5-323 §2.5 source ↗

Solve Equations with Fraction Coefficients

In the following exercises, solve each equation with fraction coefficients.

5 8 b + 1 2 = − 3 4

Answer

b = −2

2.5-325 §2.5 source ↗

Solve Equations with Fraction Coefficients

In the following exercises, solve each equation with fraction coefficients.

2= 3 5 x− 1 3 x+ 2 5 x

Answer

x = 3

2.5-327 §2.5 source ↗

Solve Equations with Fraction Coefficients

In the following exercises, solve each equation with fraction coefficients.

5 6 n− 1 4 n− 1 2 n= −2

Answer

n = −24

2.5-329 §2.5 source ↗

Solve Equations with Fraction Coefficients

In the following exercises, solve each equation with fraction coefficients.

x + 3 4 = 1 2 x − 5 4

Answer

x = −4

2.5-331 §2.5 source ↗

Solve Equations with Fraction Coefficients

In the following exercises, solve each equation with fraction coefficients.

3 2 z + 1 3 = z − 2 3

Answer

z = −2

2.5-333 §2.5 source ↗

Solve Equations with Fraction Coefficients

In the following exercises, solve each equation with fraction coefficients.

1 2 a− 1 4 = 1 6 a+ 1 12

Answer

a = 1

2.5-335 §2.5 source ↗

Solve Equations with Fraction Coefficients

In the following exercises, solve each equation with fraction coefficients.

1 3 x+ 2 5 = 1 5 x− 2 5

Answer

x = −6

2.5-337 §2.5 source ↗

Solve Equations with Fraction Coefficients

In the following exercises, solve each equation with fraction coefficients.

1= 1 5 (15x−10)

Answer

x = 1

2.5-339 §2.5 source ↗

Solve Equations with Fraction Coefficients

In the following exercises, solve each equation with fraction coefficients.

1 5 (q+3)= 1 2 (q−3)

Answer

q = 7

2.5-341 §2.5 source ↗

Solve Equations with Fraction Coefficients

In the following exercises, solve each equation with fraction coefficients.

1 3 ( x + 5 ) = 5 6

Answer

x = − 5 2

2.5-343 §2.5 source ↗

Solve Equations with Fraction Coefficients

In the following exercises, solve each equation with fraction coefficients.

4 m + 2 6 = m 3

Answer

m = −1

2.5-345 §2.5 source ↗

Solve Equations with Fraction Coefficients

In the following exercises, solve each equation with fraction coefficients.

3 p + 6 3 = p 2

Answer

p = −4

2.5-347 §2.5 source ↗

Solve Equations with Fraction Coefficients

In the following exercises, solve each equation with fraction coefficients.

v 10 + 1 = v 4 − 2

Answer

v = 20

2.5-349 §2.5 source ↗

Solve Equations with Fraction Coefficients

In the following exercises, solve each equation with fraction coefficients.

d 6 + 3 = d 8 + 2

Answer

d = −24

2.5-351 §2.5 source ↗

Solve Equations with Fraction Coefficients

In the following exercises, solve each equation with fraction coefficients.

10 y − 2 3 + 3= 10 y + 1 9

Answer

y = −1

2.5-353 §2.5 source ↗

Solve Equations with Fraction Coefficients

In the following exercises, solve each equation with fraction coefficients.

3 v − 6 2 + 5= 11 v − 4 5

Answer

v = 4

2.5-355 §2.5 source ↗

Solve Equations with Decimal Coefficients

In the following exercises, solve each equation with decimal coefficients.

0.4 y − 4 = 2

Answer

y = 15

2.5-357 §2.5 source ↗

Solve Equations with Decimal Coefficients

In the following exercises, solve each equation with decimal coefficients.

2.1 k + 3 = 7.2

Answer

k = 2

2.5-359 §2.5 source ↗

Solve Equations with Decimal Coefficients

In the following exercises, solve each equation with decimal coefficients.

0.7x+ 0.4= 0.6x+ 2.4

Answer

x = 20

2.5-361 §2.5 source ↗

Solve Equations with Decimal Coefficients

In the following exercises, solve each equation with decimal coefficients.

0.48x+ 1.56= 0.58x− 0.64

Answer

x = 22

2.5-363 §2.5 source ↗

Solve Equations with Decimal Coefficients

In the following exercises, solve each equation with decimal coefficients.

1.2x− 0.91= 0.8x+ 2.29

Answer

x = 8

2.5-365 §2.5 source ↗

Solve Equations with Decimal Coefficients

In the following exercises, solve each equation with decimal coefficients.

0.05n+ 0.10(n+7)= 3.55

Answer

n = 19

2.5-367 §2.5 source ↗

Solve Equations with Decimal Coefficients

In the following exercises, solve each equation with decimal coefficients.

0.10d+ 0.25(d+7)= 5.25

Answer

d = 10

2.5-369 §2.5 source ↗

Solve Equations with Decimal Coefficients

In the following exercises, solve each equation with decimal coefficients.

0.05(q−8)+ 0.25q= 4.10

Answer

q = 15

2.5-371 §2.5 source ↗

Solve Equations with Decimal Coefficients

In the following exercises, solve each equation with decimal coefficients.

Stamps Paula bought $22.82 worth of 49-cent stamps and 21-cent stamps. The number of 21-cent stamps was 8 less than the number of 49-cent stamps. Solve the equation 0.49s+ 0.21(s−8)= 22.82 for s, to find the number of 49-cent stamps Paula bought.

Answer

s = 35

2.5-373 §2.5 source ↗

Solve Equations with Decimal Coefficients

In the following exercises, solve each equation with decimal coefficients.

If an equation has several fractions, how does multiplying both sides by the LCD make it easier to solve?

Answer

Answers will vary.

2.5-375 §2.5 source ↗

Solve Equations with Decimal Coefficients

In the following exercises, solve each equation with decimal coefficients.

In the equation 0.35x+ 2.1= 3.85 what is the LCD? How do you know?

Answer

100. Justifications will vary.

Be Prepared 2.16 §2.6 source ↗

Solve: 15t=120.
If you missed this problem, review Example 2.13.
Example 2.13 in the book ↗

Answer

8

Be Prepared 2.17 §2.6 source ↗

Solve: 6x+24=96.
If you missed this problem, review Example 2.27.
Example 2.27 in the book ↗

Answer

12

Try It 2.115 §2.6 source ↗

Lindsay drove for 512 hours at 60 miles per hour. How much distance did she travel?

Answer

330 miles

Try It 2.116 §2.6 source ↗

Trinh walked for 213 hours at 3 miles per hour. How far did she walk?

Answer

7 miles

Try It 2.117 §2.6 source ↗

Lee wants to drive from Phoenix to his brother’s apartment in San Francisco, a distance of 770 miles. If he drives at a steady rate of 70 miles per hour, how many hours will the trip take?

Answer

11 hours

Try It 2.118 §2.6 source ↗

Yesenia is 168 miles from Chicago. If she needs to be in Chicago in 3 hours, at what rate does she need to drive?

Answer

56 mph

Try It 2.119 §2.6 source ↗

Solve the formula d=rt for r:

ⓐ when d=180andt=4 ⓑ in general

Answer

ⓐ r=45 ⓑ r=dt

Try It 2.120 §2.6 source ↗

Solve the formula d=rt for r:

ⓐ when d= 780andt= 12 ⓑ in general

Answer

ⓐ r=65 ⓑ r=dt

Try It 2.121 §2.6 source ↗

Use the formula A=12bh to solve for h:

ⓐ when A=170 and b=17 ⓑ in general

Answer

ⓐ h=20 ⓑ h=2Ab

Try It 2.122 §2.6 source ↗

Use the formula A=12bh to solve for b:

ⓐ when A=62 and h=31 ⓑ in general

Answer

ⓐ b=4 ⓑ b=2Ah

Try It 2.123 §2.6 source ↗

Use the formula I=Prt to find the principal, P:

ⓐ when I= $2,160, r= 6%, t= 3years ⓑ in general

Answer

ⓐ $12,000 ⓑ P=Irt

Try It 2.124 §2.6 source ↗

Use the formula I=Prt to find the principal,P:

ⓐ when I= $5,400, r= 12%, t= 5years ⓑ in general

Answer

ⓐ $9,000 ⓑ P=Irt

Try It 2.125 §2.6 source ↗

Solve the formula 3x+4y=10 for y:

ⓐ when x=143 ⓑ in general

Answer

ⓐ y=−1 ⓑ y=10−3x4

Try It 2.126 §2.6 source ↗

Solve the formula 5x+2y=18 for y:

ⓐ when x=4 ⓑ in general

Answer

ⓐ y=−1 ⓑ y=18−5x2

Try It 2.127 §2.6 source ↗

Solve the formula P=a+b+c for b.

Answer

b = P − a − c

Try It 2.128 §2.6 source ↗

Solve the formula P=a+b+c for c.

Answer

c = P − a − b

Try It 2.129 §2.6 source ↗

Solve the formula 4x+7y=9 for y.

Answer

y = 9 − 4 x 7

Try It 2.130 §2.6 source ↗

Solve the formula 5x+8y=1 for y.

Answer

y = 1 − 5 x 8

2.6-377 §2.6 source ↗

Use the Distance, Rate, and Time Formula

In the following exercises, solve.

Socorro drove for 456 hours at 60 miles per hour. How much distance did she travel?

Answer

290 miles

2.6-379 §2.6 source ↗

Use the Distance, Rate, and Time Formula

In the following exercises, solve.

Francie rode her bike for 212 hours at 12 miles per hour. How far did she ride?

Answer

30 miles

2.6-381 §2.6 source ↗

Use the Distance, Rate, and Time Formula

In the following exercises, solve.

Megan is taking the bus from New York City to Montreal. The distance is 380 miles and the bus travels at a steady rate of 76 miles per hour. How long will the bus ride be?

Answer

5 hours

2.6-383 §2.6 source ↗

Use the Distance, Rate, and Time Formula

In the following exercises, solve.

Kareem wants to ride his bike from St. Louis to Champaign, Illinois. The distance is 180 miles. If he rides at a steady rate of 16 miles per hour, how many hours will the trip take?

Answer

11.25 hours

2.6-385 §2.6 source ↗

Use the Distance, Rate, and Time Formula

In the following exercises, solve.

Alejandra is driving to Cincinnati, 450 miles away. If she wants to be there in 6 hours, at what rate does she need to drive?

Answer

75 mph

2.6-387 §2.6 source ↗

Use the Distance, Rate, and Time Formula

In the following exercises, solve.

Philip got a ride with a friend from Denver to Las Vegas, a distance of 750 miles. If the trip took 10 hours, how fast was the friend driving?

Answer

75 mph

2.6-389 §2.6 source ↗

Solve a Formula for a Specific Variable

In the following exercises, use the formula d=rt.

Solve for t ⓐ when d= 240andr= 60 ⓑ in general

Answer

ⓐ t=4 ⓑ t=dr

2.6-391 §2.6 source ↗

Solve a Formula for a Specific Variable

In the following exercises, use the formula d=rt.

Solve for t
ⓐ when d= 175andr= 50
ⓑ in general

Answer

ⓐ t=3.5 ⓑ t=dr

2.6-393 §2.6 source ↗

Solve a Formula for a Specific Variable

In the following exercises, use the formula d=rt.

Solve for rⓐ when d=420andt=6ⓑ in general

Answer

ⓐ r=70 ⓑ r=dt

2.6-395 §2.6 source ↗

Solve a Formula for a Specific Variable

In the following exercises, use the formula d=rt.

Solve for rⓐ when d= 180andt= 4.5ⓑ in general

Answer

ⓐ r=40 ⓑ r=dt

2.6-397 §2.6 source ↗

In the following exercises, use the formula A=12bh.

Solve for h
ⓐ when A= 176andb= 22ⓑ in general

Answer

ⓐ h=16 ⓑ h=2Ab

2.6-399 §2.6 source ↗

In the following exercises, use the formula A=12bh.

Solve for bⓐ when A=65andh=13ⓑ in general

Answer

ⓐ b=10 ⓑ b=2Ah

2.6-401 §2.6 source ↗

In the following exercises, use the formula I = Prt.

Solve for the principal, P for
ⓐ I= $3,950, r= 6%,t=5yearsⓑ in general

Answer

ⓐ P= $13, 166.67 ⓑ P=Irt

2.6-403 §2.6 source ↗

In the following exercises, use the formula I = Prt.

Solve for the time, t for
ⓐ I= $624, P= $6,000,r=5.2%ⓑ in general

Answer

ⓐ t=2 years ⓑ t=IPr

2.6-405 §2.6 source ↗

In the following exercises, solve.

Solve the formula 5x+2y=10 for yⓐ when x=4ⓑ in general

Answer

ⓐ y=−5 ⓑ y=10−5x2

2.6-407 §2.6 source ↗

In the following exercises, solve.

Solve the formula 4x+y=5 for yⓐ when x=−3ⓑ in general

Answer

ⓐ y=17 ⓑ y=5−4x

2.6-409 §2.6 source ↗

In the following exercises, solve.

Solve a+b=90 for a.

Answer

a = 90 − b

2.6-411 §2.6 source ↗

In the following exercises, solve.

Solve 180=a+b+c for c.

Answer

c = 180 − a − b

2.6-413 §2.6 source ↗

In the following exercises, solve.

Solve the formula 9x+y=13 for y.

Answer

y = 13 − 9 x

2.6-415 §2.6 source ↗

In the following exercises, solve.

Solve the formula −5x+y=−1 for y.

Answer

y = −1 + 5 x

2.6-417 §2.6 source ↗

In the following exercises, solve.

Solve the formula 3x+2y=11 for y.

Answer

y = 11 − 3 x 2

2.6-419 §2.6 source ↗

In the following exercises, solve.

Solve the formula x−y=−3 for y.

Answer

y = 3 + x

2.6-421 §2.6 source ↗

In the following exercises, solve.

Solve the formula P=2L+2W for W.

Answer

W = P − 2 L 2

2.6-423 §2.6 source ↗

In the following exercises, solve.

Solve the formula C=πd for π.

Answer

π = C d

2.6-425 §2.6 source ↗

In the following exercises, solve.

Solve the formula V=LWH for H.

Answer

H = V L W

2.6-427 §2.6 source ↗

In the following exercises, solve.

Converting temperature Yon was visiting the United States and he saw that the temperature in Seattle one day was 50o Fahrenheit. Solve for C in the formula F=95C+32 to find the Celsius temperature.

Answer

10°C

2.6-429 §2.6 source ↗

In the following exercises, solve.

Solve the equation 5x−2y=10 for xⓐ when y=10ⓑ in general
ⓒ Which solution is easier for you, ⓐ or ⓑ ? Why?

Answer

Answers will vary.

Be Prepared 2.18 §2.7 source ↗

Translate from algebra to English: 15>x.
If you missed this problem, review Example 1.12.
Example 1.12 in the book ↗

Answer

15 is greater than x.

Be Prepared 2.19 §2.7 source ↗

Solve: n−9=−42.
If you missed this problem, review Example 2.3.
Example 2.3 in the book ↗

Answer

n = − 33

Be Prepared 2.20 §2.7 source ↗

Solve: −5p=−23.
If you missed this problem, review Example 2.13.
Example 2.13 in the book ↗

Answer

p = 23 5

Be Prepared 2.21 §2.7 source ↗

Solve: 3a− 12= 7a− 20.
If you missed this problem, review Example 2.34.
Example 2.34 in the book ↗

Answer

a = 2

Try It 2.131 §2.7 source ↗

Graph on the number line: ⓐ x≤−1 ⓑ x>2 ⓒ x<3

Answer

ⓐ
This figure is a number line ranging from negative 5 to 5 with tick marks for each integer. The inequality x is less than or equal to negative 1 is graphed on the number line, with an open bracket at x equals negative 1, and a dark line extending to the left of the bracket.

ⓑ
This figure is a number line ranging from negative 5 to 5 with tick marks for each integer. The inequality x is greater than 2 is graphed on the number line, with an open parenthesis at x equals 2, and a dark line extending to the right of the parenthesis.

ⓒ
This figure is a number line ranging from negative 5 to 5 with tick marks for each integer. The inequality x is less than 3 is graphed on the number line, with an open parenthesis at x equals 3, and a dark line extending to the left of the parenthesis.

Try It 2.132 §2.7 source ↗

Graph on the number line: ⓐ x>−2 ⓑ x<−3 ⓒ x≥−1

Answer

ⓐ
This figure is a number line ranging from negative 5 to 5 with tick marks for each integer. The inequality x is greater than negative 2 is graphed on the number line, with an open parenthesis at x equals negative 2, and a dark line extending to the right of the parenthesis.

ⓑ
This figure is a number line ranging from negative 5 to 5 with tick marks for each integer. The inequality x is less than negative 3 is graphed on the number line, with an open parenthesis at x equals negative 3, and a dark line extending to the left of the parenthesis.

ⓒ
This figure is a number line ranging from negative 5 to 5 with tick marks for each integer. The inequality x is greater than or equal to negative 1 is graphed on the number line, with an open bracket at x equals negative 1, and a dark line extending to the right of the bracket.

Try It 2.133 §2.7 source ↗

Graph on the number line and write in interval notation:

ⓐ x>2 ⓑ x≤−1.5 ⓒ x≥34

Answer

ⓐ
This figure is a number line ranging from negative 5 to 5 with tick marks for each integer. The inequality x is greater than 2 is graphed on the number line, with an open parenthesis at x equals 2, and a dark line extending to the right of the parenthesis. The inequality is also written in interval notation as parenthesis, 2 comma infinity, parenthesis.

ⓑ
This figure is a number line ranging from negative 5 to 5 with tick marks for each integer. The inequality x is less than or equal to negative 1.5 is graphed on the number line, with an open bracket at x equals negative 1.5, and a dark line extending to the left of the bracket. The inequality is also written in interval notation as parenthesis, negative infinity comma negative 1.5, bracket.

ⓒ
This figure is a number line ranging from negative 5 to 5 with tick marks for each integer. The inequality x is greater than or equal to 3/4 is graphed on the number line, with an open bracket at x equals 3/4, and a dark line extending to the right of the bracket. The inequality is also written in interval notation as bracket, 3/4 comma infinity, parenthesis.

Try It 2.134 §2.7 source ↗

Graph on the number line and write in interval notation:

ⓐ x≤−4 ⓑ x≥0.5 ⓒ x<−23

Answer

ⓐ
This figure is a number line ranging from negative 5 to 5 with tick marks for each integer. The inequality x is less than or equal to negative 4 is graphed on the number line, with an open bracket at x equals negative 4, and a dark line extending to the left of the bracket. The inequality is also written in interval notation as parenthesis, negative infinity comma negative 4, bracket.

ⓑ
This figure is a number line ranging from negative 5 to 5 with tick marks for each integer. The inequality x is greater than or equal to 0.5 is graphed on the number line, with an open bracket at x equals 0.5, and a dark line extending to the right of the bracket. The inequality is also written in interval notation as bracket, o.5 comma infinity, parenthesis.

ⓒ
This figure is a number line ranging from negative 5 to 5 with tick marks for each integer. The inequality x is less than negative 2/3 is graphed on the number line, with an open parenthesis at x equals negative 2/3, and a dark line extending to the left of the parenthesis. The inequality is also written in interval notation as parenthesis, negative infinity comma negative 2/3, parenthesis.

Try It 2.135 §2.7 source ↗

Solve the inequality, graph the solution on the number line, and write the solution in interval notation.

p−34≥16

Answer

This figure shows the inequality p is greater than or equal to 11/12. Below this inequality is the inequality graphed on a number line ranging from 0 to 4, with tick marks at each integer. There is a bracket at p equals 11/12, and a dark line extends to the right from 11/12. Below the number line is the solution written in interval notation: bracket, 11/12 comma infinity, parenthesis.

Try It 2.136 §2.7 source ↗

Solve the inequality, graph the solution on the number line, and write the solution in interval notation.

r−13≤712

Answer

This figure shows the inequality r is less than or equal to 11/12. Below this inequality is the inequality graphed on a number line ranging from 0 to 4, with tick marks at each integer. There is a bracket at r equals 11/12, and a dark line extends to the left from 11/12. Below the number line is the solution written in interval notation: parenthesis, negative infinity comma 11/12, bracket.

Try It 2.137 §2.7 source ↗

Solve the inequality, graph the solution on the number line, and write the solution in interval notation.

c-8>0

Answer

c>8

This figure is a number line ranging from 6 to 10 with tick marks for each integer. The inequality c is greater than 8 is graphed on the number line, with an open parenthesis at c equals 8, and a dark line extending to the right of the parenthesis.

Try It 2.138 §2.7 source ↗

Solve the inequality, graph the solution on the number line, and write the solution in interval notation.

12d≤​60

Answer

(-∞,5]

This figure is a number line ranging from 3 to 7 with tick marks for each integer. The inequality d is less than or equal to 5 is graphed on the number line, with an open bracket at d equals 5, and a dark line extending to the left of the bracket. The inequality is also written in interval notation as parenthesis, negative infinity comma 5, bracket.

Try It 2.139 §2.7 source ↗

Solve each inequality, graph the solution on the number line, and write the solution in interval notation.

−8q<32

Answer

q > −4

This figure is a number line ranging from negative 6 to negative 3 with tick marks for each integer. The inequality q is greater than negative 4 is graphed on the number line, with an open parenthesis at q equals negative 4, and a dark line extending to the right of the parenthesis. The inequality is also written in interval notation as parenthesis, negative 4 comma infinity, parenthesis.

Try It 2.140 §2.7 source ↗

Solve each inequality, graph the solution on the number line, and write the solution in interval notation.

−7r≤​−70

Answer

This figure is a number line ranging from 9 to 13 with tick marks for each integer. The inequality r is greater than or equal to 10 is graphed on the number line, with an open bracket at r equals 10, and a dark line extending to the right of the bracket. The inequality is also written in interval notation as bracket, 10 comma infinity, parenthesis.

Try It 2.141 §2.7 source ↗

Solve the inequality, graph the solution on the number line, and write the solution in interval notation.

24≤38m

Answer

This figure shows the inequality m is greater than or equal to 64. Below this inequality is a number line ranging from 63 to 67 with tick marks for each integer. The inequality m is greater than or equal to 64 is graphed on the number line, with an open bracket at m equals 64, and a dark line extending to the right of the bracket. The inequality is also written in interval notation as bracket, 64 comma infinity, parenthesis.

Try It 2.142 §2.7 source ↗

Solve the inequality, graph the solution on the number line, and write the solution in interval notation.

−24<43n

Answer

This figure shows the inequality n is greater than negative 18. Below this inequality is a number line ranging from negative 20 to negative 16 with tick marks for each integer. The inequality n is greater than negative 18 is graphed on the number line, with an open parenthesis at n equals negative 18, and a dark line extending to the right of the parenthesis. The inequality is also written in interval notation as parenthesis, negative 18 comma infinity, parenthesis.

Try It 2.143 §2.7 source ↗

Solve the inequality, graph the solution on the number line, and write the solution in interval notation.

k−12≤15

Answer

This figure shows the inequality k is greater than or equal to negative 180. Below this inequality is a number line ranging from negative 181 to negative 177 with tick marks for each integer. The inequality k is greater than or equal to negative 180 is graphed on the number line, with an open bracket at n equals negative 180, and a dark line extending to the right of the bracket. The inequality is also written in interval notation as bracket, negative 180 comma infinity, parenthesis.

Try It 2.144 §2.7 source ↗

Solve the inequality, graph the solution on the number line, and write the solution in interval notation.

u−4≥−16

Answer

This figure shows the inequality u is less than or equal to 64. Below this inequality is a number line ranging from 62 to 66 with tick marks for each integer. The inequality u is less than or equal to 64 is graphed on the number line, with an open bracket at u equals 64, and a dark line extending to the left of the bracket. The inequality is also written in interval notation as parenthesis, negative infinity comma 64, bracket.

Try It 2.145 §2.7 source ↗

Solve the inequality 3q ≥ 7q − 23, graph the solution on the number line, and write the solution in interval notation.

Answer

This figure shows the inequality q is less than or equal to 23/4. Below this inequality is a number line ranging from 4 to 8 with tick marks for each integer. The inequality q is less than or equal to 23/4 is graphed on the number line, with an open bracket at q equals 23/4 (written in), and a dark line extending to the left of the bracket. The inequality is also written in interval notation as parenthesis, negative infinity comma 23/4, bracket.

Try It 2.146 §2.7 source ↗

Solve the inequality 6x< 10x+ 19, graph the solution on the number line, and write the solution in interval notation.

Answer

This figure shows the inequality x is greater than negative 19/4. Below this inequality is a number line ranging from negative 7 to negative 3, with tick marks for each integer. The inequality x is greater than negative 19/4 is graphed on the number line, with an open parenthesis at x equals negative 19/4 (written in), and a dark line extending to the right of the parenthesis. The inequality is also written in interval notation as parenthesis, negative 19/4 comma infinity, parenthesis.

Try It 2.147 §2.7 source ↗

Solve the inequality 9y+ 2(y+6)> 5y− 24, graph the solution on the number line, and write the solution in interval notation.

Answer

This figure shows the inequality y is greater than negative 6. Below this inequality is a number line ranging from negative 7 to negative 3 with tick marks for each integer. The inequality y is greater than negative 6 is graphed on the number line, with an open parenthesis at y equals negative 6, and a dark line extending to the right of the parenthesis. The inequality is also written in interval notation as parenthesis, negative 6 comma infinity, parenthesis.

Try It 2.148 §2.7 source ↗

Solve the inequality 6u+ 8(u−1)> 10u+ 32, graph the solution on the number line, and write the solution in interval notation.

Answer

This figure shows the inequality u is greater than 10. Below this inequality is a number line ranging from 9 to 13 with tick marks for each integer. The inequality u is greater than 10 is graphed on the number line, with an open parenthesis at u equals 10, and a dark line extending to the right of the parenthesis. The inequality is also written in interval notation as parenthesis, 10 comma infinity, parenthesis.

Try It 2.149 §2.7 source ↗

Solve the inequality 4b− 3(3−b)> 5(b−6)+ 2b, graph the solution on the number line, and write the solution in interval notation.

Answer

This figure shows an inequality that is an identity. Below this inequality is a number line ranging from negative 2 to 2 with tick marks for each integer. The identity is graphed on the number line, with a dark line extending in both directions. The inequality is also written in interval notation as parenthesis, negative infinity comma infinity, parenthesis.

Try It 2.150 §2.7 source ↗

Solve the inequality 9h− 7(2−h)< 8(h+11)+ 8h, graph the solution on the number line, and write the solution in interval notation.

Answer

This figure shows an inequality that is an identity. Below this inequality is a number line ranging from negative 2 to 2 with tick marks for each integer. The identity is graphed on the number line, with a dark line extending in both directions. The inequality is also written in interval notation as parenthesis, negative infinity comma infinity, parenthesis.

Try It 2.151 §2.7 source ↗

Solve the inequality 14x− 112x> 16x+ 78, graph the solution on the number line, and write the solution in interval notation.

Answer

This figure shows an inequality that is a contradiction. Below this is a number line ranging from negative 2 to 2 with tick marks for each integer. No inequality is graphed on the number line. Below the number line is the statement: “No solution.”

Try It 2.152 §2.7 source ↗

Solve the inequality 25z− 13z< 115z​+ 35, graph the solution on the number line, and write the solution in interval notation.

Answer

This figure shows an inequality that is a contradiction. Below this is a number line ranging from negative 2 to 2 with tick marks for each integer. No inequality is graphed on the number line. Below the number line is the statement: “No solution.”

Try It 2.153 §2.7 source ↗

Translate and solve. Then write the solution in interval notation and graph on the number line.

Twenty times y is at most 100

Answer

This figure shows the inequality 20y is less than or equal to 100, and then its solution: y is less than or equal to 5. Below this inequality is a number line ranging from 4 to 8 with tick marks for each integer. The inequality y is less than or equal to 5 is graphed on the number line, with an open bracket at y equals 5, and a dark line extending to the left of the bracket. The inequality is also written in interval notation as parenthesis, negative infinity comma 5, bracket.

Try It 2.154 §2.7 source ↗

Translate and solve. Then write the solution in interval notation and graph on the number line.

Nine times z is no less than 135

Answer

This figure shows the inequality 9z is greater than or equal to 135, and then its solution: z is greater than or equal to 15. Below this inequality is a number line ranging from 14 to 18 with tick marks for each integer. The inequality z is greater than or equal to 15 is graphed on the number line, with an open bracket at z equals 15, and a dark line extending to the right of the bracket. The inequality is also written in interval notation as bracket, 15 comma infinity, parenthesis.

Try It 2.155 §2.7 source ↗

Translate and solve. Then write the solution in interval notation and graph on the number line.

Nineteen less than p is no less than 47

Answer

This figure shows the inequality p minus 19 is greater than or equal to 47, and then its solution: p is greater than or equal to 66. Below this inequality is a number line ranging from 65 to 69 with tick marks for each integer. The inequality p is greater than or equal to 66 is graphed on the number line, with an open bracket at p equals 66, and a dark line extending to the right of the bracket. The inequality is also written in interval notation as bracket, 66 comma infinity, parenthesis.

Try It 2.156 §2.7 source ↗

Translate and solve. Then write the solution in interval notation and graph on the number line.

Four more than a is at most 15.

Answer

This figure shows the inequality a plus 4 is less than or equal to 15, and then its solution: a is less than or equal to 11. Below this inequality is a number line ranging from 10 to 14 with tick marks for each integer. The inequality a is less than or equal to 11 is graphed on the number line, with an open bracket at a equals 11, and a dark line extending to the left of the bracket. The inequality is also written in interval notation as parenthesis, negative infinity 11, bracket.

2.7-431 §2.7 source ↗

Graph Inequalities on the Number Line

In the following exercises, graph each inequality on the number line.

ⓐ x>1ⓑ x<−2
ⓒ x≥−3

Answer

ⓐ
This figure is a number line ranging from negative 5 to 5 with tick marks for each integer. The inequality x is greater than 1 is graphed on the number line, with an open parenthesis at x equals 1, and a dark line extending to the right of the parenthesis.

ⓑ
This figure is a number line ranging from negative 5 to 5 with tick marks for each integer. The inequality x is less than negative 2 is graphed on the number line, with an open parenthesis at x equals negative 2, and a dark line extending to the left of the parenthesis.

ⓒ
This figure is a number line ranging from negative 5 to 5 with tick marks for each integer. The inequality x is greater than or equal to negative 3 is graphed on the number line, with an open bracket at x equals negative 3, and a dark line extending to the right of the bracket.

2.7-433 §2.7 source ↗

Graph Inequalities on the Number Line

In the following exercises, graph each inequality on the number line.


ⓐ x≤0ⓑ x>−4ⓒ x≥−1

Answer

ⓐ
This figure is a number line ranging from negative 5 to 5 with tick marks for each integer. The inequality x is less than or equal to 0 is graphed on the number line, with an open bracket at x equals 0, and a dark line extending to the left of the bracket.

ⓑ
This figure is a number line ranging from negative 5 to 5 with tick marks for each integer. The inequality x is greater than negative 4 is graphed on the number line, with an open parenthesis at x equals negative 4, and a dark line extending to the right of the parenthesis.

ⓒ
This figure is a number line ranging from negative 5 to 5 with tick marks for each integer. The inequality x is greater than or equal to negative 1 is graphed on the number line, with an open bracket at x equals negative 1, and a dark line extending to the right of the bracket.

2.7-435 §2.7 source ↗

In the following exercises, graph each inequality on the number line and write in interval notation.


ⓐ x>3ⓑ x≤−0.5ⓒ x≥13

Answer

ⓐ
This figure is a number line ranging from negative 5 to 5 with tick marks for each integer. The inequality x is greater than 3 is graphed on the number line, with an open parenthesis at x equals 3, and a dark line extending to the right of the parenthsis. Below the number line is the solution written in interval notation: parenthesis, 3 comma infinity, parenthesis.

ⓑ
This figure is a number line ranging from negative 5 to 5 with tick marks for each integer. The inequality x is less than or equal to negative 0.5 is graphed on the number line, with an open bracket at x equals negative 0.5, and a dark line extending to the left of the bracket. Below the number line is the solution written in interval notation: parenthesis, negative infinity comma negative 0.5, bracket.

ⓒ
This figure is a number line ranging from negative 5 to 5 with tick marks for each integer. The inequality x is greater than or equal to 1/3 is graphed on the number line, with an open bracket at x equals 1/3 (written in), and a dark line extending to the right of the bracket. Below the number line is the solution written in interval notation: bracket, 1/3 comma infinity, parenthesis.

2.7-437 §2.7 source ↗

In the following exercises, graph each inequality on the number line and write in interval notation.


ⓐ x≤5ⓑ x≥−1.5ⓒ x<−73

Answer

ⓐ
This figure is a number line with tick marks. The inequality x is less than or equal to 5 is graphed on the number line, with an open bracket at x equals 5, and a dark line extending to the left of the bracket. Below the number line is the solution written in interval notation: parenthesis, negative infinity comma 5, bracket.

ⓑ
This figure is a number line ranging from negative 5 to 5 with tick marks for each integer. The inequality x is greater than or equal to negative 1.5 is graphed on the number line, with an open bracket at x equals negative 1.5, and a dark line extending to the right of the bracket. Below the number line is the solution written in interval notation: bracket, negative 1.5 comma infinity, parenthesis.

ⓒ
This figure is a number line ranging from negative 5 to 5 with tick marks for each integer. The inequality x is less than negative 7/3 is graphed on the number line, with an open parenthesis at x equals negative 7/3 (written in), and a dark line extending to the left of the parenthsis. Below the number line is the solution written in interval notation: parenthesis, negative infinity comma negative 7/3, parenthesis.

2.7-439 §2.7 source ↗

Solve Inequalities using the Subtraction and Addition Properties of Inequality

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

m − 45 ≤ 62

Answer

At the top of this figure is the solution to the inequality: m is less than or equal to 107. Below this is a number line ranging from 105 to 109 with tick marks for each integer. The inequality x is less than or equal to 107 is graphed on the number line, with an open bracket at x equals 107, and a dark line extending to the left of the bracket. Below the number line is the solution written in interval notation: parenthesis, negative infinity comma 107, bracket.

2.7-441 §2.7 source ↗

Solve Inequalities using the Subtraction and Addition Properties of Inequality

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

v + 12 > 3

Answer

At the top of this figure is the solution to the inequality: v is greater than negative 9. Below this is a number line ranging from negative 11 to negative 7 with tick marks for each integer. The inequality x is greater than negative 9 is graphed on the number line, with an open parenthesis at x equals negative 9, and a dark line extending to the right of the parenthesis. Below the number line is the solution written in interval notation: parenthesis, negative 9 comma infinity, parenthesis.

2.7-443 §2.7 source ↗

Solve Inequalities using the Subtraction and Addition Properties of Inequality

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

b + 7 8 ≥ 1 6

Answer

At the top of this figure is the solution to the inequality: b is greater than or equal to negative 17/24. Below this is a number line ranging from negative 2 to 2 with tick marks for each integer. The inequality b is greater than or equal to negative 17/24 is graphed on the number line, with an open bracket at b equals negative 17/24 (written in), and a dark line extending to the right of the bracket. Below the number line is the solution written in interval notation: bracket, negative 17/24 comma infinity, parenthesis.

2.7-445 §2.7 source ↗

Solve Inequalities using the Subtraction and Addition Properties of Inequality

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

g− 11 12 < − 5 18

Answer

At the top of this figure is the solution to the inequality: g is less than 23/26. Below this is a number line ranging from negative 2 to 2 with tick marks for each integer. The inequality g is less than 23/26 is graphed on the number line, with an open parenthesis at g equals 23/26 (written in), and a dark line extending to the left of the parenthesis. Below the number line is the solution written in interval notation: parenthesis, negative infinity comma 23/26, parenthesis.

2.7-447 §2.7 source ↗

Solve Inequalities using the Division and Multiplication Properties of Inequality

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

6 y < 48

Answer

At the top of this figure is the solution to the inequality: y is less than 8. Below this is a number line ranging from 6 to 10 with tick marks for each integer. The inequality y is less than 8 is graphed on the number line, with an open parenthesis at y equals 8, and a dark line extending to the left of the parenthesis. Below the number line is the solution written in interval notation: parenthesis, negative infinity comma 8, parenthesis.

2.7-449 §2.7 source ↗

Solve Inequalities using the Division and Multiplication Properties of Inequality

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

9 s ≥ 81

Answer

At the top of this figure is the solution to the inequality: s is greater than or equal to 9. Below this is a number line ranging from 7 to 11 with tick marks for each integer. The inequality s is greater than or equal to 9 is graphed on the number line, with an open bracket at s equals 9, and a dark line extending to the right of the bracket. Below the number line is the solution written in interval notation: bracket, 9 comma infinity, parenthesis.

2.7-451 §2.7 source ↗

Solve Inequalities using the Division and Multiplication Properties of Inequality

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

−8 v ≤ 96

Answer

At the top of this figure is the solution to the inequality: v is greater than or equal to negative 12. Below this is a number line ranging from negative 14 to negative 10 with tick marks for each integer. The inequality v is greater than or equal to negative 12 is graphed on the number line, with an open bracket at v equals negative 12, and a dark line extending to the right of the bracket. Below the number line is the solution written in interval notation: bracket, negative 12 comma infinity, parenthesis.

2.7-453 §2.7 source ↗

Solve Inequalities using the Division and Multiplication Properties of Inequality

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

−7 d > 105

Answer

At the top of this figure is the solution to the inequality: d is less than negative 15. Below this is a number line ranging from negative 17 to negative 13 with tick marks for each integer. The inequality d is less than negative 15 is graphed on the number line, with an open parenthesis at d equals negative 15, and a dark line extending to the left of the parenthesis. Below the number line is the solution written in interval notation: parenthesis, negative infinity comma negative 15, parenthesis.

2.7-455 §2.7 source ↗

Solve Inequalities using the Division and Multiplication Properties of Inequality

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

40 < 5 8 k

Answer

At the top of this figure is the solution to the inequality: k is greater than 64. Below this is a number line ranging from 62 to 66 with tick marks for each integer. The inequality k is greater than 64 is graphed on the number line, with an open parenthesis at k equals 64, and a dark line extending to the right of the parenthesis. Below the number line is the solution written in interval notation: parenthesis, negative infinity comma 64, parenthesis.

2.7-457 §2.7 source ↗

Solve Inequalities using the Division and Multiplication Properties of Inequality

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

9 4 g ≤ 36

Answer

At the top of this figure is the solution to the inequality: g is less than or equal to 16. Below this is a number line ranging from 14 to 18 with tick marks for each integer. The inequality g is less than or equal to 16 is graphed on the number line, with an open bracket at g equals 16, and a dark line extending to the left of the bracket. Below the number line is the solution written in interval notation: parenthesis, negative infinity comma 16, bracket.

2.7-459 §2.7 source ↗

Solve Inequalities using the Division and Multiplication Properties of Inequality

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

b −10 ≥ 30

Answer

At the top of this figure is the solution to the inequality: b is less than or equal to negative 300. Below this is a number line ranging from negative 302 to negative 298 with tick marks for each integer. The inequality b is less than or equal to negative 300 is graphed on the number line, with an open bracket at b equals negative 300, and a dark line extending to the left of the bracket. Below the number line is the solution written in interval notation: parenthesis, negative infinity comma negative 300, bracket.

2.7-461 §2.7 source ↗

Solve Inequalities using the Division and Multiplication Properties of Inequality

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

−18 > q −6

Answer

At the top of this figure is the solution to the inequality: q is greater than 108. Below this is a number line ranging from 106 to 110 with tick marks for each integer. The inequality q is greater than 108 is graphed on the number line, with an open parenthesis at q equals 108, and a dark line extending to the right of the parenthesis. Below the number line is the solution written in interval notation: parenthesis, 108 comma infinity, parenthesis.

2.7-463 §2.7 source ↗

Solve Inequalities using the Division and Multiplication Properties of Inequality

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

7 s < − 28

Answer

At the top of this figure is the solution to the inequality: s is less than negative 4. Below this is a number line ranging from negative 6 to negative 2 with tick marks for each integer. The inequality s is less than negative 4 is graphed on the number line, with an open parenthesis at s equals negative 4, and a dark line extending to the left of the parenthesis. Below the number line is the solution written in interval notation: parenthesis, negative infinity comma negative 4, parenthesis.

2.7-465 §2.7 source ↗

Solve Inequalities using the Division and Multiplication Properties of Inequality

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

3 5 x ≤ − 45

Answer

At the top of this figure is the solution to the inequality: x is less than or equal to negative 75. Below this is a number line ranging from negative 77 to negative 73 with tick marks for each integer. The inequality x is less than or equal to negative 75 is graphed on the number line, with an open bracket at x equals negative 75, and a dark line extending to the left of the bracket. Below the number line is the solution written in interval notation: parenthesis, negative infinity comma negative 75, bracket.

2.7-467 §2.7 source ↗

Solve Inequalities That Require Simplification

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

5 u ≤ 8 u − 21

Answer

At the top of this figure is the solution to the inequality: au is greater than or equal to 7. Below this is a number line ranging from 5 to 9 with tick marks for each integer. The inequality u is greater than or equal to 7 is graphed on the number line, with an open bracket at u equals 7, and a dark line extending to the right of the bracket. Below the number line is the solution written in interval notation: bracket, 7 comma infinity, parenthesis.

2.7-469 §2.7 source ↗

Solve Inequalities That Require Simplification

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

9p> 14p− 18

Answer

At the top of this figure is the solution to the inequality: p is less than 18/5. Below this is a number line ranging from 2 to 6 with tick marks for each integer. The inequality p is less than 18/5 is graphed on the number line, with an open parenthesis at p equals 18/5 (written in), and a dark line extending to the left of the parenthesis. Below the number line is the solution written in interval notation: parenthesis, negative infinity comma 18/5, parenthesis.

2.7-471 §2.7 source ↗

Solve Inequalities That Require Simplification

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

9y+ 5(y+3)< 4y− 35

Answer

At the top of this figure is the solution to the inequality: y is less than negative 5. Below this is a number line ranging from negative 6 to negative 2 with tick marks for each integer. The inequality y is less than negative 5 is graphed on the number line, with an open parenthesis at y equals negative 5, and a dark line extending to the left of the parenthesis. Below the number line is the solution written in interval notation: parenthesis, negative infinity comma negative 5, parenthesis.

2.7-473 §2.7 source ↗

Solve Inequalities That Require Simplification

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

4k− (k−2)≥7k− 26

Answer

At the top of this figure is the solution to the inequality: x is less than or equal to 7. Below this is a number line ranging from 5 to 9 with tick marks for each integer. The inequality x is less than or equal to 7 is graphed on the number line, with an open bracket at x equals 7, and a dark line extending to the left of the bracket. Below the number line is the solution written in interval notation: parenthesis, negative infinity comma 7, bracket.

2.7-475 §2.7 source ↗

Solve Inequalities That Require Simplification

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

6n− 12(3−n)≤9(n−4)+ 9n

Answer

At the top of this figure is the solution to the inequality: the inequality is an identity. Below this is a number line ranging from negative 2 to 2 with tick marks for each integer. The identity is graphed on the number line, with a dark line extending in both directions. Below the number line is the solution written in interval notation: parenthesis, negative infinity comma infinity, parenthesis.

2.7-477 §2.7 source ↗

Solve Inequalities That Require Simplification

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

9u+ 5(2u−5)≥12(u−1)+ 7u

Answer

At the top of this figure is the result of the inequality: the inequality is a contradiction. Below this is a number line ranging from negative 2 to 2 with tick marks for each integer. Because this is a contradiction, no inequality is graphed on the number line. Below the number line is the statement: “No solution”.

2.7-479 §2.7 source ↗

Solve Inequalities That Require Simplification

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

5 6 a− 1 4 a> 7 12 a+ 2 3

Answer

At the top of this figure is the result of the inequality: the inequality is a contradiction. Below this is a number line ranging from negative 2 to 2 with tick marks for each integer. Because this is a contradiction, no inequality is graphed on the number line. Below the number line is the statement: “No solution”.

2.7-481 §2.7 source ↗

Solve Inequalities That Require Simplification

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

12v+ 3(4v−1)≤19(v−2)+ 5v

Answer

At the top of this figure is the result of the inequality: the inequality is a contradiction. Below this is a number line ranging from negative 2 to 2 with tick marks for each integer. Because this is a contradiction, no inequality is graphed on the number line. Below the number line is the statement: “No solution”.

2.7-483 §2.7 source ↗

Mixed practice

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

35 k ≥ −77

Answer

At the top of this figure is the solution to the inequality: k is greater than or equal to negative 11/5. Below this is a number line ranging from negative 4 to 0 with tick marks for each integer. The inequality k is greater than or equal to negative 11/5 is graphed on the number line, with an open bracket at k equals negative 11/5 (written in), and a dark line extending to the right of the bracket. Below the number line is the solution written in interval notation: bracket, negative 11/5 comma infinity, parenthesis.

2.7-485 §2.7 source ↗

Mixed practice

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

18q− 4(10−3q)< 5(6q−8)

Answer

At the top of this figure is the result of the inequality: the inequality is a contradiction. Below this is a number line ranging from negative 2 to 2 with tick marks for each integer. Because this is a contradiction, no inequality is graphed on the number line. Below the number line is the statement: “No solution”.

2.7-487 §2.7 source ↗

Mixed practice

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

− 21 8 y ≤ − 15 28

Answer

At the top of this figure is the solution to the inequality: y is greater than or equal to 10/49. Below this is a number line ranging from negative 1 to 3 with tick marks for each integer. The inequality y is greater than or equal to 10/49 is graphed on the number line, with an open bracket at y equals 10/49 (written in), and a dark line extending to the right of the bracket. Below the number line is the solution written in interval notation: bracket, 10/49 comma infinity, parenthesis.

2.7-489 §2.7 source ↗

Mixed practice

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

d + 29 > − 61

Answer

At the top of this figure is the solution to the inequality: d is greater than negative 90. Below this is a number line ranging from negative 92 to negative 88 with tick marks for each integer. The inequality d is greater than negative 90 is graphed on the number line, with an open parenthesis at d equals negative 90, and a dark line extending to the right of the parenthesis. Below the number line is the solution written in interval notation: parenthesis, negative 90 comma infinity, parenthesis.

2.7-491 §2.7 source ↗

Mixed practice

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

n 13 ≤ − 6

Answer

At the top of this figure is the solution to the inequality: n is less than or equal to negative 78. Below this is a number line ranging from negative 80 to negative 76 with tick marks for each integer. The inequality n is less than or equal to negative 78 is graphed on the number line, with an open bracket at n equals negative 78, and a dark line extending to the left of the bracket. Below the number line is the solution written in interval notation: parenthesis, negative infinity comma negative 78, bracket.

2.7-493 §2.7 source ↗

Translate to an Inequality and Solve

In the following exercises, translate and solve .Then write the solution in interval notation and graph on the number line.

Ninety times c is less than 450.

Answer

At the top of this figure is the the inequality 90c is less than 450. Below this is the solution to the inequality: c is less than 5. Below the solution is the solution written in interval notation: parenthesis, negative infinity comma 5, parenthesis. Below the interval notation is a number line ranging from 3 to 7 with tick marks for each integer. The inequality c is less than 5 is graphed on the number line, with an open parenthesis at c equals 5, and a dark line extending to the left of the parenthesis.

2.7-495 §2.7 source ↗

Translate to an Inequality and Solve

In the following exercises, translate and solve .Then write the solution in interval notation and graph on the number line.

Ten times y is at most −110.

Answer

At the top of this figure is the the inequality 10y is less than or equal to negative 110. Below this is the solution to the inequality: y is less than or equal to negative 11. Below the solution is the solution written in interval notation: parenthesis, negative infinity comma negative 11, bracket. Below the interval notation is a number line ranging from negative 13 to negative 9 with tick marks for each integer. The inequality y is less than or equal to negative 11 is graphed on the number line, with an open bracket at y equals negative 11, and a dark line extending to the left of the bracket.

2.7-497 §2.7 source ↗

Translate to an Inequality and Solve

In the following exercises, translate and solve .Then write the solution in interval notation and graph on the number line.

Six more than k exceeds 25.

Answer

At the top of this figure is the the inequality k plus 6 is greater than 25. Below this is the solution to the inequality: k is greater than 19. Below the the solution written in interval notation: parenthesis, 19 comma infinity, parenthesis. Below the interval notation is a number line ranging from 17 to 21 with tick marks for each integer. The inequality k is greater than 19 is graphed on the number line, with an open parenthesis at k equals 19, and a dark line extending to the right of the parenthesis.

2.7-499 §2.7 source ↗

Translate to an Inequality and Solve

In the following exercises, translate and solve .Then write the solution in interval notation and graph on the number line.

Twelve less than x is no less than 21.

Answer

At the top of this figure is the the inequality x minus 12 is greater than or equal to 21. Below this is the solution to the inequality: x is greater than or equal to 33. Below the solution is the solution written in interval notation: bracket, 33 comma infinity, parenthesis. Below the interval notation is a number line ranging from 32 to 36 with tick marks for each integer. The inequality x is greater than or equal to 33 is graphed on the number line, with an open bracket at x equals 33, and a dark line extending to the right of the bracket.

2.7-501 §2.7 source ↗

Translate to an Inequality and Solve

In the following exercises, translate and solve .Then write the solution in interval notation and graph on the number line.

Negative two times s is lower than 56.

Answer

At the top of this figure is the the inequality negative 2s is less than 56. Below this is the solution to the inequality: s is greater than negative 28. Below the solution is the solution written in interval notation: parenthesis, negative 28 comma infinity, parenthesis. Below the interval notation is a number line ranging from negative 30 to negative 26 with tick marks for each integer. The inequality s is greater than negative 28 is graphed on the number line, with an open parenthesis at s equals negative 28, and a dark line extending to the right of the parenthesis.

2.7-503 §2.7 source ↗

Translate to an Inequality and Solve

In the following exercises, translate and solve .Then write the solution in interval notation and graph on the number line.

Fifteen less than a is at least −7.

Answer

At the top of this figure is the the inequality a minus 15 is greater than or equal to negative 7. Below this is the solution to the inequality: a is greater than or equal to 8. Below the solution is the solution written in interval notation: bracket, 8 comma infinity, parenthesis. Below the interval notation is a number line ranging from 0 to 10 with tick marks for each integer. The inequality a is greater than or equal to 8 is graphed on the number line, with an open bracket at a equals 8, and a dark line extending to the right of the bracket.

2.7-505 §2.7 source ↗

Translate to an Inequality and Solve

In the following exercises, translate and solve .Then write the solution in interval notation and graph on the number line.

Fighter pilots The maximum height, h, of a fighter pilot is 77 inches. Write this as an inequality.

Answer

h ≤ 77

2.7-507 §2.7 source ↗

Translate to an Inequality and Solve

In the following exercises, translate and solve .Then write the solution in interval notation and graph on the number line.

Shopping The number of items, n, a shopper can have in the express check-out lane is at most 8. Write this as an inequality.

Answer

n ≤ 8

2.7-509 §2.7 source ↗

Translate to an Inequality and Solve

In the following exercises, translate and solve .Then write the solution in interval notation and graph on the number line.

Give an example from your life using the phrase ‘at most’.

Answer

Answers will vary.

2.7-511 §2.7 source ↗

Translate to an Inequality and Solve

In the following exercises, translate and solve .Then write the solution in interval notation and graph on the number line.

Explain why it is necessary to reverse the inequality when solving n−3<12.

Answer

Answers will vary.

2.R-513 §2.R source ↗

Verify a Solution of an Equation

In the following exercises, determine whether each number is a solution to the equation.

w + 2 = 5 8 ; w = 3 8

Answer

no

2.R-515 §2.R source ↗

Verify a Solution of an Equation

In the following exercises, determine whether each number is a solution to the equation.

6a− 3= −7a, a= 3 13

Answer

yes

2.R-517 §2.R source ↗

Solve Equations using the Subtraction and Addition Properties of Equality

In the following exercises, solve each equation using the Subtraction Property of Equality.

y + 2 = −6

Answer

y = −8

2.R-519 §2.R source ↗

Solve Equations using the Subtraction and Addition Properties of Equality

In the following exercises, solve each equation using the Subtraction Property of Equality.

n + 3.6 = 5.1

Answer

n = 1.5

2.R-521 §2.R source ↗

In the following exercises, solve each equation using the Addition Property of Equality.

x − 9 = −4

Answer

x = 5

2.R-523 §2.R source ↗

In the following exercises, solve each equation using the Addition Property of Equality.

p − 4.8 = 14

Answer

p = 18.8

2.R-525 §2.R source ↗

In the following exercises, solve each equation.

y + 16 = −9

Answer

y = −25

2.R-527 §2.R source ↗

In the following exercises, solve each equation.

d − 3.9 = 8.2

Answer

d = 12.1

2.R-529 §2.R source ↗

Solve Equations That Require Simplification

In the following exercises, solve each equation.

7x+ 10− 6x+ 3= 5

Answer

x = −8

2.R-531 §2.R source ↗

Solve Equations That Require Simplification

In the following exercises, solve each equation.

8(3p+5)− 23(p−1)= 35

Answer

p = −28

2.R-533 §2.R source ↗

Translate to an Equation and Solve

In the following exercises, translate each English sentence into an algebraic equation and then solve it.

Four less than n is 13.

Answer

n − 4 = 13 ; n = 17

2.R-535 §2.R source ↗

Translate and Solve Applications

In the following exercises, translate into an algebraic equation and solve.

Tan weighs 146 pounds. Minh weighs 15 pounds more than Tan. How much does Minh weigh?

Answer

161 pounds

2.R-537 §2.R source ↗

Translate and Solve Applications

In the following exercises, translate into an algebraic equation and solve.

Elissa earned $152.84 this week, which was $21.65 more than she earned last week. How much did she earn last week?

Answer

$131.19

2.R-539 §2.R source ↗

Solve Equations Using the Division and Multiplication Properties of Equality

In the following exercises, solve each equation using the division and multiplication properties of equality and check the solution.

13 a = −65

Answer

a = −5

2.R-541 §2.R source ↗

Solve Equations Using the Division and Multiplication Properties of Equality

In the following exercises, solve each equation using the division and multiplication properties of equality and check the solution.

− y = 4

Answer

y = −4

2.R-543 §2.R source ↗

Solve Equations Using the Division and Multiplication Properties of Equality

In the following exercises, solve each equation using the division and multiplication properties of equality and check the solution.

y −10 = 30

Answer

y = −300

2.R-545 §2.R source ↗

Solve Equations Using the Division and Multiplication Properties of Equality

In the following exercises, solve each equation using the division and multiplication properties of equality and check the solution.

5 8 u = 15 16

Answer

u = 3 2

2.R-547 §2.R source ↗

Solve Equations Using the Division and Multiplication Properties of Equality

In the following exercises, solve each equation using the division and multiplication properties of equality and check the solution.

c 9 = 36

Answer

c = 324

2.R-549 §2.R source ↗

Solve Equations Using the Division and Multiplication Properties of Equality

In the following exercises, solve each equation using the division and multiplication properties of equality and check the solution.

11 12 = 2 3 y

Answer

y = 11 8

2.R-551 §2.R source ↗

Solve Equations That Require Simplification

In the following exercises, solve each equation requiring simplification.

24x+ 8x− 11x= −7− 14

Answer

x = −1

2.R-553 §2.R source ↗

Solve Equations That Require Simplification

In the following exercises, solve each equation requiring simplification.

−9(d−2)− 15= −24

Answer

d = 3

2.R-555 §2.R source ↗

Translate to an Equation and Solve

In the following exercises, translate to an equation and then solve.

The quotient of b and 9 is −27.

Answer

b 9 = −27; b= −243

2.R-557 §2.R source ↗

Translate to an Equation and Solve

In the following exercises, translate to an equation and then solve.

The difference of s and one-twelfth is one fourth.

Answer

s− 1 12 = 1 4 ; s= 1 3

2.R-559 §2.R source ↗

Translate and Solve Applications

In the following exercises, translate into an equation and solve.

Janet gets paid $24 per hour. She heard that this is 34 of what Adam is paid. How much is Adam paid per hour?

Answer

$32

2.R-561 §2.R source ↗

Solve an Equation with Constants on Both Sides

In the following exercises, solve the following equations with constants on both sides.

10 w − 5 = 65

Answer

w = 7

2.R-563 §2.R source ↗

Solve an Equation with Constants on Both Sides

In the following exercises, solve the following equations with constants on both sides.

32 = −4 − 9 n

Answer

n = −4

2.R-565 §2.R source ↗

Solve an Equation with Variables on Both Sides

In the following exercises, solve the following equations with variables on both sides.

5 a + 21 = 2 a

Answer

a = −7

2.R-567 §2.R source ↗

Solve an Equation with Variables on Both Sides

In the following exercises, solve the following equations with variables on both sides.

4 x − 3 8 = 3 x

Answer

x = 3 8

2.R-569 §2.R source ↗

Solve an Equation with Variables and Constants on Both Sides

In the following exercises, solve the following equations with variables and constants on both sides.

5n− 20= −7n− 80

Answer

n = −5

2.R-571 §2.R source ↗

Solve an Equation with Variables and Constants on Both Sides

In the following exercises, solve the following equations with variables and constants on both sides.

5 8 c − 4 = 3 8 c + 4

Answer

c = 32

2.R-573 §2.R source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

9 ( 2 p − 5 ) = 72

Answer

p = 13 2

2.R-575 §2.R source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

8 + 3 ( n − 9 ) = 17

Answer

n = 12

2.R-577 §2.R source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

1 3 (6m+21)= m− 7

Answer

m = −14

2.R-579 §2.R source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

0.25(q−8)= 0.1(q+7)

Answer

q = 18

2.R-581 §2.R source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

5+ 7(2−5x)= 2(9x+1)
− ( 13 x − 57 )

Answer

x = −1

2.R-583 §2.R source ↗

Solve Equations Using the General Strategy for Solving Linear Equations

In the following exercises, solve each linear equation.

2 [ −16 + 5 ( 8 k − 6 ) ]
= 8 ( 3 − 4 k ) − 32

Answer

k = 3 4

2.R-585 §2.R source ↗

Classify Equations

In the following exercises, classify each equation as a conditional equation, an identity, or a contradiction and then state the solution.

9u+ 32= 15(u−4)
− 3 ( 2 u + 21 )

Answer

contradiction; no solution

2.R-587 §2.R source ↗

Classify Equations

In the following exercises, classify each equation as a conditional equation, an identity, or a contradiction and then state the solution.

21(c−1)− 19(c+1)
= 2 ( c − 20 )

Answer

identity; all real numbers

2.R-589 §2.R source ↗

Solve Equations with Fraction Coefficients

In the following exercises, solve each equation with fraction coefficients.

1 3 x + 1 5 x = 8

Answer

x = 15

2.R-591 §2.R source ↗

Solve Equations with Fraction Coefficients

In the following exercises, solve each equation with fraction coefficients.

1 2 (k−3)= 1 3 (k+16)

Answer

k = 41

2.R-593 §2.R source ↗

Solve Equations with Fraction Coefficients

In the following exercises, solve each equation with fraction coefficients.

5 y − 1 3 + 4= −8 y + 4 6

Answer

y = −1

2.R-595 §2.R source ↗

Solve Equations with Decimal Coefficients

In the following exercises, solve each equation with decimal coefficients.

0.36u+ 2.55= 0.41u+ 6.8

Answer

u = −85

2.R-597 §2.R source ↗

Solve Equations with Decimal Coefficients

In the following exercises, solve each equation with decimal coefficients.

0.7y+ 2.5= 0.95y− 9.25

Answer

y = 47

2.R-599 §2.R source ↗

Use the Distance, Rate, and Time Formula

In the following exercises, solve.

Mallory is taking the bus from St. Louis to Chicago. The distance is 300 miles and the bus travels at a steady rate of 60 miles per hour. How long will the bus ride be?

Answer

5 hours

2.R-601 §2.R source ↗

Use the Distance, Rate, and Time Formula

In the following exercises, solve.

Link rode his bike at a steady rate of 15 miles per hour for 212 hours. How much distance did he travel?

Answer

37.5 miles

2.R-603 §2.R source ↗

Solve a Formula for a Specific Variable

In the following exercises, solve.

Use the formula. d=rt to solve for r
ⓐ when when d=451 and t=5.5
ⓑ in general

Answer

ⓐ r=82mph; ⓑ r=Dt

2.R-605 §2.R source ↗

Solve a Formula for a Specific Variable

In the following exercises, solve.

Use the formula A=12bh to solve for h
ⓐ when A=153 and b=18
ⓑ in general

Answer

ⓐ h=17 ⓑ h=2Ab

2.R-607 §2.R source ↗

Solve a Formula for a Specific Variable

In the following exercises, solve.

Solve the formula 4x+3y=6 for y
ⓐ when x=−2
ⓑ in general

Answer

ⓐ y=143 ⓑ y=6−4x3

2.R-609 §2.R source ↗

Solve a Formula for a Specific Variable

In the following exercises, solve.

Solve the formula V=LWH for H.

Answer

H = V L W

2.R-611 §2.R source ↗

Graph Inequalities on the Number Line

In the following exercises, graph each inequality on the number line.


ⓐ x>0
ⓑ x<−3
ⓒ x≥−1

Answer

ⓐ
This figure is a number line ranging from negative 5 to 5 with tick marks for each integer. The inequality x is greater than 0 is graphed on the number line, with an open parenthesis at x equals 0, and a dark line extending to the right of the parenthesis.

ⓑ
This figure is a number line ranging from negative 5 to 5 with tick marks for each integer. The inequality x is less than negative 3 is graphed on the number line, with an open parenthesis at x equals negative 3, and a dark line extending to the left of the parenthesis.

ⓒ
This figure is a number line ranging from negative 5 to 5 with tick marks for each integer. The inequality x is greater than or equal to 1 is graphed on the number line, with an open bracket at x equals 1, and a dark line extending to the right of the bracket.

2.R-613 §2.R source ↗

In the following exercises, graph each inequality on the number line and write in interval notation.


ⓐ x>2
ⓑ x≤−1.5
ⓒ x≥53

Answer

ⓐ
This figure is a number line ranging from negative 5 to 5 with tick marks for each integer. The inequality x is greater than 2 is graphed on the number line, with an open parenthesis at x equals 2, and a dark line extending to the right of the parenthesis. Below the number line is the solution written in interval notation: parenthesis, 2 comma infinity, parenthesis.

ⓑ
This figure is a number line ranging from negative 5 to 5 with tick marks for each integer. The inequality x is less than or equal to negative 1.5 is graphed on the number line, with an open bracket at x equals negative 1.5, and a dark line extending to the left of the bracket. Below the number line is the solution written in interval notation: parenthesis, negative infinity comma negative 1.5, bracket.

ⓒ
This figure is a number line ranging from negative 5 to 5 with tick marks for each integer. The inequality x is greater than or equal to 5/3 is graphed on the number line, with an open bracket at x equals 5/3, and a dark line extending to the right of the bracket. Below the number line is the solution written in interval notation: bracket, 5/3 comma infinity, parenthesis.

2.R-615 §2.R source ↗

Solve Inequalities using the Subtraction and Addition Properties of Inequality

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

m + 14 ≤ 56

Answer

At the top of this figure is the solution to the inequality: m is less than or equal to 42. Below this is a number line ranging from 40 to 44 with tick marks for each integer. The inequality m is less than or equal to 42 is graphed on the number line, with an open bracket at m equals 42, and a dark line extending to the left of the bracket. Below the number line is the solution written in interval notation: parenthesis, negative infinity comma 42, bracket

2.R-617 §2.R source ↗

Solve Inequalities using the Subtraction and Addition Properties of Inequality

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

b − 7 8 ≥ − 1 2

Answer

At the top of this figure is the solution to the inequality: b is greater than or equal to 3/8. Below this is a number line ranging from negative 2 to 2 with tick marks for each integer. The inequality b is greater than or equal to 3/8 is graphed on the number line, with an open bracket at b equals 3/8 (written in), and a dark line extending to the right of the bracket. Below the number line is the solution written in interval notation: bracket, 3/8 comma infinity, bracket

2.R-619 §2.R source ↗

Solve Inequalities using the Division and Multiplication Properties of Inequality

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

−12 d ≤ 108

Answer

At the top of this figure is the solution to the inequality: d is greater than or equal to negative 9. Below this is a number line ranging from negative 11 to negative 7 with tick marks for each integer. The inequality d is greater than or equal to negative 9 is graphed on the number line, with an open bracket at d equals negative 9, and a dark line extending to the right of the bracket. Below the number line is the solution written in interval notation: bracket, negative 9 comma infinity, parenthesis.

2.R-621 §2.R source ↗

Solve Inequalities using the Division and Multiplication Properties of Inequality

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

q − 2 ≥ − 24

Answer

At the top of this figure is the solution to the inequality: q is less than or equal to 48. Below this is a number line ranging from 46 to 50 with tick marks for each integer. The inequality q is less than or equal to 48 is graphed on the number line, with an open bracket at q equals 48, and a dark line extending to the left of the bracket. Below the number line is the solution written in interval notation: parenthesis, negative infinity comma 48, bracket.

2.R-623 §2.R source ↗

Solve Inequalities That Require Simplification

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

9h− 7(h−1)≤4h− 23

Answer

At the top of this figure is the solution to the inequality: h is greater than or equal to 15. Below this is a number line ranging from 13 to 17 with tick marks for each integer. The inequality h is greater than or equal to 15 is graphed on the number line, with an open bracket at h equals 15, and a dark line extending to the right of the bracket. Below the number line is the solution written in interval notation: bracket, 15 comma infinity, parenthesis.

2.R-625 §2.R source ↗

Solve Inequalities That Require Simplification

In the following exercises, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

3 8 a− 1 12 a> 5 12 a+ 3 4

Answer

At the top of this figure is the solution to the inequality: a is less than negative 6. Below this is a number line ranging from negative 8 to negative 4 with tick marks for each integer. The inequality a is less than negative 6 is graphed on the number line, with an open parenthesis at a equals negative 6, and a dark line extending to the left of the parenthesis. Below the number line is the solution written in interval notation: parenthesis, negative infinity comma negative 6, parenthesis.

2.R-627 §2.R source ↗

Translate to an Inequality and Solve

In the following exercises, translate and solve. Then write the solution in interval notation and graph on the number line.

Three less than c is at least 360.

Answer

At the top of this figure is the inequality c minus 3 is greater than or equal to 360. To the right of this is the solution to the inequality: c is greater than or equal to 363. To the right of the solution is the solution written in interval notation: bracket, 363 comma infinity, parenthesis. Below all of this is a number line ranging from 361 to 365 with tick marks for each integer. The inequality c is greater than or equal to 363 is graphed on the number line, with an open bracket at c equals 363, and a dark line extending to the right of the bracket.

2.R-629 §2.R source ↗

Translate to an Inequality and Solve

In the following exercises, translate and solve. Then write the solution in interval notation and graph on the number line.

Negative two times a is no more than 8.

Answer

At the top of this figure is the inequality negative 2a is less than or equal to 8. To the right of this is the solution to the inequality: a is greater than or equal to negative 4. To the right of the solution is the solution written in interval notation: bracket, negative 4 comma infinity, parenthesis. Below all of this is a number line ranging from negative 6 to negative 2 with tick marks for each integer. The inequality a is greater than or equal to negative 4 is graphed on the number line, with an open bracket at a equals negative 4, and a dark line extending to the right of the bracket.

2.T-631 §2.T source ↗

Determine whether each number is a solution to the equation 6x−3=x+20.

ⓐ 5ⓑ 235

Answer

ⓐ no ⓑ yes

2.T-633 §2.T source ↗

In the following exercises, solve each equation.

9 2 c = 144

Answer

c = 32

2.T-635 §2.T source ↗

In the following exercises, solve each equation.

−8x− 15+ 9x− 1= −21

Answer

x = −5

2.T-637 §2.T source ↗

In the following exercises, solve each equation.

2 3 x = 6

Answer

x = 9

2.T-639 §2.T source ↗

In the following exercises, solve each equation.

10 y = −5 y − 60

Answer

y = −4

2.T-641 §2.T source ↗

In the following exercises, solve each equation.

9m− 2− 4m− m= 42− 8

Answer

m = 9

2.T-643 §2.T source ↗

In the following exercises, solve each equation.

− ( d − 9 ) = 23

Answer

d = −14

2.T-645 §2.T source ↗

In the following exercises, solve each equation.

2(6x−5)− 8= −22

Answer

x = − 1 3

2.T-647 §2.T source ↗

In the following exercises, solve each equation.

1 4 p − 1 3 = 1 2

Answer

p = 10 3

2.T-649 §2.T source ↗

In the following exercises, solve each equation.

14n− 3(4n+5)= −9+ 2(n−8)

Answer

contradiction; no solution

2.T-651 §2.T source ↗

In the following exercises, solve each equation.

Solve the formula x−2y=5 for y
ⓐ when x=−3
ⓑ in general

Answer

ⓐ y=4 ⓑ y=5−x2

2.T-653 §2.T source ↗

In the following exercises, graph on the number line and write in interval notation.

x < 11 4

Answer

This figure is a number line ranging from 1 to 5 with tick marks for each integer. The inequality x is less than 11/4 is graphed on the number line, with an open parenthesis at x equals 11/4, and a dark line extending to the left of the parenthesis. Below the number line is the solution written in interval notation: parenthesis, negative infinity comma 11/4, parenthesis.

2.T-655 §2.T source ↗

In the following exercises,, solve each inequality, graph the solution on the number line, and write the solution in interval notation.

3c− 10(c−2)< 5c+ 16

Answer

This figure is a number line ranging from negative 2 to 3 with tick marks for each integer. The inequality c is greater than 1/3 is graphed on the number line, with an open parenthesis at c equals 1/3, and a dark line extending to the right of the parenthesis. Below the number line is the solution: c is greater than 1/3. To the right of the solution is the solution written in interval notation: parenthesis, 1/3 comma infinity, parenthesis

2.T-657 §2.T source ↗

In the following exercises, translate to an equation or inequality and solve.

Fifteen more than n is at least 48.

Answer

n+ 15≥48; n≥33

2.T-659 §2.T source ↗

In the following exercises, translate to an equation or inequality and solve.

Jenna bought a coat on sale for $120, which was 23 of the original price. What was the original price of the coat?

Answer

120=23p; The original price was $180.

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Problems and answers are adapted from Elementary Algebra 2e by Lynn Marecek and MaryAnne Anthony-Smith, OpenStax, and are used under the CC BY-NC-SA 4.0 licence. Access for free at https://openstax.org/books/elementary-algebra-2e/pages/1-introduction. Illustrations: Copyright Rice University, OpenStax, under CC BY-NC-SA 4.0 license. This adaptation is released under the same licence, is non-commercial, and is neither affiliated with nor endorsed by OpenStax or Rice University.