Every problem in the chapter beside the book’s answer, a chapter at a time as you scroll.

Chapter 17: Physics of Hearing

44 problems · 5 figures

17-1 §17.2 source ↗

When poked by a spear, an operatic soprano lets out a 1200-Hz shriek. What is its wavelength if the speed of sound is 345 m/s?

Answer

0.288 m

17-3 §17.2 source ↗

Calculate the speed of sound on a day when a 1500 Hz frequency has a wavelength of 0.221 m.

Answer

332 m/s

17-5 §17.2 source ↗

Show that the speed of sound in 20.0ºC air is 343 m/s, as claimed in the text.

Answer

v w = ( 331 m/s ) T 273 K = ( 331 m/s ) 293 K 273 K = 343 m/s

17-7 §17.2 source ↗

Dolphins make sounds in air and water. What is the ratio of the wavelength of a sound in air to its wavelength in seawater? Assume air temperature is 20.0ºC .

Answer

0.223

17-9 §17.2 source ↗

(a) If a submarine’s sonar can measure echo times with a precision of 0.0100 s, what is the smallest difference in distances it can detect? (Assume that the submarine is in the ocean, not in fresh water.)

(b) Discuss the limits this time resolution imposes on the ability of the sonar system to detect the size and shape of the object creating the echo.

Answer

(a) 7.70 m

(b) This means that sonar is good for spotting and locating large objects, but it isn’t able to resolve smaller objects, or detect the detailed shapes of objects. Objects like ships or large pieces of airplanes can be found by sonar, while smaller pieces must be found by other means.

17-11 §17.2 source ↗

Suppose a bat uses sound echoes to locate its insect prey, 3.00 m away. (See Figure 17.9.) (a) Calculate the echo times for temperatures of 5.00ºC and 35.0ºC . (b) What percent uncertainty does this cause for the bat in locating the insect? (c) Discuss the significance of this uncertainty and whether it could cause difficulties for the bat. (In practice, the bat continues to use sound as it closes in, eliminating most of any difficulties imposed by this and other effects, such as motion of the prey.)
Figure 17.9 in the book ↗
A bat uses sound echoes to find its way about and to catch prey. The time for the echo to return is directly proportional to the distance.

Answer

(a) 18.0 ms, 17.1 ms

(b) 5.00%

(c) This uncertainty could definitely cause difficulties for the bat, if it didn’t continue to use sound as it closed in on its prey. A 5% uncertainty could be the difference between catching the prey around the neck or around the chest, which means that it could miss grabbing its prey.

17-12 §17.3 source ↗

What is the intensity in watts per meter squared of 85.0-dB sound?

Answer

3.16×10–4W/m2

17-14 §17.3 source ↗

A sound wave traveling in 20ºC air has a pressure amplitude of 0.5 Pa. What is the intensity of the wave?

Answer

3.04 × 10 –4 W/m 2

17-16 §17.3 source ↗

What sound intensity level in dB is produced by earphones that create an intensity of 4.00 × 10 −2 W/m 2 ?

Answer

106 dB

17-18 §17.3 source ↗

(a) What is the decibel level of a sound that is twice as intense as a 90.0-dB sound? (b) What is the decibel level of a sound that is one-fifth as intense as a 90.0-dB sound?

Answer

(a) 93 dB

(b) 83 dB

17-20 §17.3 source ↗

(a) How much more intense is a sound that has a level 17.0 dB higher than another? (b) If one sound has a level 23.0 dB less than another, what is the ratio of their intensities?

Answer

(a) 50.1

(b) 5.01×10–3 or 1200

17-22 §17.3 source ↗

If a large housefly 3.0 m away from you makes a noise of 40.0 dB, what is the noise level of 1000 flies at that distance, assuming interference has a negligible effect?

Answer

70.0 dB

17-24 §17.3 source ↗

The amplitude of a sound wave is measured in terms of its maximum gauge pressure. By what factor does the amplitude of a sound wave increase if the sound intensity level goes up by 40.0 dB?

Answer

100

17-26 §17.3 source ↗

An 8-hour exposure to a sound intensity level of 90.0 dB may cause hearing damage. What energy in joules falls on a 0.800-cm-diameter eardrum so exposed?

Answer

1.45 × 10 –3 J

17-28 §17.3 source ↗

Sound is more effectively transmitted into a stethoscope by direct contact than through the air, and it is further intensified by being concentrated on the smaller area of the eardrum. It is reasonable to assume that sound is transmitted into a stethoscope 100 times as effectively compared with transmission though the air. What, then, is the gain in decibels produced by a stethoscope that has a sound gathering area of 15.0 cm2, and concentrates the sound onto two eardrums with a total area of 0.900 cm2 with an efficiency of 40.0%?

Answer

28.2 dB

17-30 §17.4 source ↗

(a) What frequency is received by a person watching an oncoming ambulance moving at 110 km/h and emitting a steady 800-Hz sound from its siren? The speed of sound on this day is 345 m/s. (b) What frequency does she receive after the ambulance has passed?

Answer

(a) 878 Hz

(b) 735 Hz

17-32 §17.4 source ↗

What frequency is received by a mouse just before being dispatched by a hawk flying at it at 25.0 m/s and emitting a screech of frequency 3500 Hz? Take the speed of sound to be 331 m/s.

Answer

3.79 × 10 3 Hz

17-34 §17.4 source ↗

A commuter train blows its 200-Hz horn as it approaches a crossing. The speed of sound is 335 m/s. (a) An observer waiting at the crossing receives a frequency of 208 Hz. What is the speed of the train? (b) What frequency does the observer receive as the train moves away?

Answer

(a) 12.9 m/s

(b) 193 Hz

17-36 §17.4 source ↗

Two eagles fly directly toward one another, the first at 15.0 m/s and the second at 20.0 m/s. Both screech, the first one emitting a frequency of 3200 Hz and the second one emitting a frequency of 3800 Hz. What frequencies do they receive if the speed of sound is 330 m/s?

Answer

First eagle hears 4.23×103Hz

Second eagle hears 3.56×103Hz

17-38 §17.5 source ↗

A “showy” custom-built car has two brass horns that are supposed to produce the same frequency but actually emit 263.8 and 264.5 Hz. What beat frequency is produced?

Answer

0.7 Hz

17-40 §17.5 source ↗

What beat frequencies result if a piano hammer hits three strings that emit frequencies of 127.8, 128.1, and 128.3 Hz?

Answer

0.3 Hz, 0.2 Hz, 0.5 Hz

17-42 §17.5 source ↗

(a) What is the fundamental frequency of a 0.672-m-long tube, open at both ends, on a day when the speed of sound is 344 m/s? (b) What is the frequency of its second harmonic?

Answer

(a) 256 Hz

(b) 512 Hz

17-44 §17.5 source ↗

What are the first three overtones of a bassoon that has a fundamental frequency of 90.0 Hz? It is open at both ends. (The overtones of a real bassoon are more complex than this example, because its double reed makes it act more like a tube closed at one end.)

Answer

180 Hz, 270 Hz, 360 Hz

17-46 §17.5 source ↗

What length should an oboe have to produce a fundamental frequency of 110 Hz on a day when the speed of sound is 343 m/s? It is open at both ends.

Answer

1.56 m

17-48 §17.5 source ↗

(a) Find the length of an organ pipe closed at one end that produces a fundamental frequency of 256 Hz when air temperature is 18.0ºC. (b) What is its fundamental frequency at 25.0ºC?

Answer

(a) 0.334 m

(b) 259 Hz

17-50 §17.5 source ↗

The ear canal resonates like a tube closed at one end. (See Figure 17.37.) If ear canals range in length from 1.80 to 2.60 cm in an average population, what is the range of fundamental resonant frequencies? Take air temperature to be 37.0ºC, which is the same as body temperature. How does this result correlate with the intensity versus frequency graph (Figure 17.35 of the human ear?
Figure 17.37 in the book ↗
The illustration shows the gross anatomy of the human ear.
Figure 17.35 in the book ↗
The shaded region represents frequencies and intensity levels found in normal conversational speech. The 0-phon line represents the normal hearing threshold, while those at 40 and 60 represent thresholds for people with 40- and 60-phon hearing losses, respectively.

Answer

3.39 to 4.90 kHz

17-52 §17.5 source ↗

A crude approximation of voice production is to consider the breathing passages and mouth to be a resonating tube closed at one end. (See Figure 17.29.) (a) What is the fundamental frequency if the tube is 0.240-m long, by taking air temperature to be 37.0ºC? (b) What would this frequency become if the person replaced the air with helium? Assume the same temperature dependence for helium as for air.
Figure 17.29 in the book ↗
The throat and mouth form an air column closed at one end that resonates in response to vibrations in the voice box. The spectrum of overtones and their intensities vary with mouth shaping and tongue position to form different sounds. The voice box can be replaced with a mechanical vibrator, and understandable speech is still possible. Variations in basic shapes make different voices recognizable.

Answer

(a) 367 Hz

(b) 1.07 kHz

17-54 §17.5 source ↗

What frequencies will a 1.80-m-long tube produce in the audible range at 20.0ºC if: (a) The tube is closed at one end? (b) It is open at both ends?

Answer

(a) fn= n(47.6 Hz), n= 1, 3, 5,..., 419

(b) fn= n(95.3 Hz), n= 1, 2, 3,..., 210

17-55 §17.6 source ↗

The factor of 10−12 in the range of intensities to which the ear can respond, from threshold to that causing damage after brief exposure, is truly remarkable. If you could measure distances over the same range with a single instrument and the smallest distance you could measure was 1 mm, what would the largest be?

Answer

1 × 10 6 km

17-57 §17.6 source ↗

What are the closest frequencies to 500 Hz that an average person can clearly distinguish as being different in frequency from 500 Hz? The sounds are not present simultaneously.

Answer

498.5 or 501.5 Hz

17-59 §17.6 source ↗

If your radio is producing an average sound intensity level of 85 dB, what is the next lowest sound intensity level that is clearly less intense?

Answer

82 dB

17-61 §17.6 source ↗

Based on the graph in Figure 17.34, what is the threshold of hearing in decibels for frequencies of 60, 400, 1000, 4000, and 15,000 Hz? Note that many AC electrical appliances produce 60 Hz, music is commonly 400 Hz, a reference frequency is 1000 Hz, your maximum sensitivity is near 4000 Hz, and many older TVs produce a 15,750 Hz whine.
Figure 17.34 in the book ↗
The relationship of loudness in phons to intensity level (in decibels) and intensity (in watts per meter squared) for persons with normal hearing. The curved lines are equal-loudness curves—all sounds on a given curve are perceived as equally loud. Phons and decibels are defined to be the same at 1000 Hz.

Answer

approximately 48, 9, 0, –7, and 20 dB, respectively

17-63 §17.6 source ↗

What is the approximate sound intensity level in decibels of a 600-Hz tone if it has a loudness of 20 phons? If it has a loudness of 70 phons?

Answer

(a) 23 dB

(b) 70 dB

17-65 §17.6 source ↗

Suppose a person has a 50-dB hearing loss at all frequencies. By how many factors of 10 will low-intensity sounds need to be amplified to seem normal to this person? Note that smaller amplification is appropriate for more intense sounds to avoid further hearing damage.

Answer

Five factors of 10

17-67 §17.6 source ↗

(a) What is the intensity in watts per meter squared of a just barely audible 200-Hz sound? (b) What is the intensity in watts per meter squared of a barely audible 4000-Hz sound?

Answer

(a) 2 × 10 − 10 W/m 2

(b) 2 × 10 − 13 W/m 2

17-69 §17.6 source ↗

A person has a hearing threshold 10 dB above normal at 100 Hz and 50 dB above normal at 4000 Hz. How much more intense must a 100-Hz tone be than a 4000-Hz tone if they are both barely audible to this person?

Answer

2.5

17-71 §17.6 source ↗

What is the ratio of intensities of two sounds of identical frequency if the first is just barely discernible as louder to a person than the second?

Answer

1.26

17-72 §17.7 source ↗

Unless otherwise indicated, for problems in this section, assume that the speed of sound through human tissues is 1540 m/s.

What is the sound intensity level in decibels of ultrasound of intensity 105W/m2, used to pulverize tissue during surgery?

Answer

170 dB

17-74 §17.7 source ↗

Unless otherwise indicated, for problems in this section, assume that the speed of sound through human tissues is 1540 m/s.

Find the sound intensity level in decibels of 2.00×10–2W/m2ultrasound used in medical diagnostics.

Answer

103 dB

17-76 §17.7 source ↗

Unless otherwise indicated, for problems in this section, assume that the speed of sound through human tissues is 1540 m/s.

In the clinical use of ultrasound, transducers are always coupled to the skin by a thin layer of gel or oil, replacing the air that would otherwise exist between the transducer and the skin. (a) Using the values of acoustic impedance given in Table 17.5 calculate the intensity reflection coefficient between transducer material and air. (b) Calculate the intensity reflection coefficient between transducer material and gel (assuming for this problem that its acoustic impedance is identical to that of water). (c) Based on the results of your calculations, explain why the gel is used.

Table 17.5 The Ultrasound Properties of Various Media, Including Soft Tissue Found in the Body in the book ↗
Medium Density (kg/m3) Speed of Ultrasound (m/s) Acoustic Impedance ( kg/ ( m 2 ⋅ s ) )
Air 1.3 330 429
Water 1000 1500 1.5×106
Blood 1060 1570 1.66×106
Fat 925 1450 1.34×106
Muscle (average) 1075 1590 1.70×106
Bone (varies) 1400–1900 4080 5.7×106 to 7.8×106
Barium titanate (transducer material) 5600 5500 30.8×106

Answer

(a) 1.00

(b) 0.823

(c) Gel is used to facilitate the transmission of the ultrasound between the transducer and the patient’s body.

17-78 §17.7 source ↗

Unless otherwise indicated, for problems in this section, assume that the speed of sound through human tissues is 1540 m/s.

(a) Find the size of the smallest detail observable in human tissue with 20.0-MHz ultrasound. (b) Is its effective penetration depth great enough to examine the entire eye (about 3.00 cm is needed)? (c) What is the wavelength of such ultrasound in 0ºC air?

Answer

(a) 77.0 μm

(b) Effective penetration depth = 3.85 cm, which is enough to examine the eye.

(c) 16.6 μm

17-80 §17.7 source ↗

Unless otherwise indicated, for problems in this section, assume that the speed of sound through human tissues is 1540 m/s.

(a) How far apart are two layers of tissue that produce echoes having round-trip times (used to measure distances) that differ by 0.750 μs ? (b) What minimum frequency must the ultrasound have to see detail this small?

Answer

(a) 5.78×10–4m

(b) 2.67×106Hz

17-82 §17.7 source ↗

Unless otherwise indicated, for problems in this section, assume that the speed of sound through human tissues is 1540 m/s.

A dolphin is able to tell in the dark that the ultrasound echoes received from two sharks come from two different objects only if the sharks are separated by 3.50 m, one being that much farther away than the other. (a) If the ultrasound has a frequency of 100 kHz, show this ability is not limited by its wavelength. (b) If this ability is due to the dolphin’s ability to detect the arrival times of echoes, what is the minimum time difference the dolphin can perceive?

Answer

(a) vw= 1540 m/s= fλ⇒λ= 1540 m/s 100×103Hz = 0.0154 m < 3.50 m. Because the wavelength is much shorter than the distance in question, the wavelength is not the limiting factor.

(b) 4.55 ms

17-84 §17.7 source ↗

Unless otherwise indicated, for problems in this section, assume that the speed of sound through human tissues is 1540 m/s.

Ultrasound reflected from an oncoming bloodstream that is moving at 30.0 cm/s is mixed with the original frequency of 2.50 MHz to produce beats. What is the beat frequency? (Assume that the frequency of 2.50 MHz is accurate to seven significant figures.)

Answer

974 Hz

(Note: extra digits were retained in order to show the difference.)

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Problems and answers are adapted from College Physics 2e by Paul Peter Urone, Roger Hinrichs, Kim Dirks and Manjula Sharma, OpenStax, and are used under the CC BY-NC-SA 4.0 licence. Access for free at https://openstax.org/books/college-physics-2e/pages/1-introduction-to-science-and-the-realm-of-physics-physical-quantities-and-units. Illustrations: Copyright Rice University, OpenStax, under CC BY-NC-SA 4.0 license. This adaptation is released under the same licence, is non-commercial, and is neither affiliated with nor endorsed by OpenStax or Rice University.