Every problem in the chapter beside the book’s answer, a chapter at a time as you scroll.
Chapter 29: Quantum Physics
46 problems · 0 figures29-1 §29.1 source ↗
Answer
(a) 0.070 eV
(b) 14
29-3 §29.1 source ↗
Answer
(a)
(b)
(c) No
29-4 §29.2 source ↗
Answer
29-6 §29.2 source ↗
Answer
29-8 §29.2 source ↗
Answer
29-10 §29.2 source ↗
Answer
29-12 §29.2 source ↗
Answer
(a) 264 nm
(b) Ultraviolet
29-14 §29.2 source ↗
Answer
29-16 §29.2 source ↗
Answer
(a)
(b) 0.256 mW
29-18 §29.2 source ↗
Unreasonable Results
Red light having a wavelength of 700 nm is projected onto magnesium metal to which electrons are bound by 3.68 eV. (a) Use to calculate the kinetic energy of the ejected electrons. (b) What is unreasonable about this result? (c) Which assumptions are unreasonable or inconsistent?
Answer
(a)
(b) Negative kinetic energy
(c) That the electrons would be knocked free.
29-20 §29.3 source ↗
Answer
29-22 §29.3 source ↗
Answer
29-24 §29.3 source ↗
Answer
29-26 §29.3 source ↗
Answer
(a) 0.0829 eV
(b) 121
(c) 1.24 MeV
(d)
29-28 §29.3 source ↗
Answer
(a)
(b)
29-30 §29.3 source ↗
Answer
(a) 2.69
(b) 0.371
29-32 §29.3 source ↗
Answer
(a)
(b) 997 km
29-34 §29.3 source ↗
Answer
29-36 §29.3 source ↗
Answer
29-38 §29.4 source ↗
Answer
(a)
(b) The wavelength of microwave photons is large, so the momentum they carry is very small.
29-40 §29.4 source ↗
Answer
(a) 13.3 μm
(b) eV
29-42 §29.4 source ↗
Answer
(a)
(b) 291 m/s
(c) electron , photon , ratio
29-44 §29.4 source ↗
Answer
(a)
(b) 9.39 MeV
(c)
29-46 §29.4 source ↗
Answer
and , so
As the mass of particle approaches zero, its velocity will approach , so that the ratio of energy to momentum in this limit is
which is consistent with the equation for photon energy.
29-48 §29.4 source ↗
Unreasonable Results
A car feels a small force due to the light it sends out from its headlights, equal to the momentum of the light divided by the time in which it is emitted. (a) Calculate the power of each headlight, if they exert a total force of backward on the car. (b) What is unreasonable about this result? (c) Which assumptions are unreasonable or inconsistent?
Answer
(a)
(b) Headlights are way too bright.
(c) Force is too large.
29-49 §29.6 source ↗
Answer
29-51 §29.6 source ↗
Answer
29-53 §29.6 source ↗
Answer
29-55 §29.6 source ↗
Answer
(a)
(b)
29-57 §29.6 source ↗
Answer
29-59 §29.6 source ↗
Answer
(a) 5.29 fm
(b)
(c) 29.4 MV
29-61 §29.6 source ↗
Unreasonable Results
(a) Assuming it is nonrelativistic, calculate the velocity of an electron with a 0.100-fm wavelength (small enough to detect details of a nucleus). (b) What is unreasonable about this result? (c) Which assumptions are unreasonable or inconsistent?
Answer
(a)
(b) This is thousands of times the speed of light (an impossibility).
(c) The assumption that the electron is non-relativistic is unreasonable at this wavelength.
29-62 §29.7 source ↗
Answer
(a) 57.9 m/s
(b)
(c) From Table 29.1, we see that typical molecular binding energies range from about 1eV to 10 eV, therefore the result in part (b) is approximately 9 orders of magnitude smaller than typical molecular binding energies.
| Rotational energies of molecules | eV |
| Vibrational energies of molecules | 0.1 eV |
| Energy between outer electron shells in atoms | 1 eV |
| Binding energy of a weakly bound molecule | 1 eV |
| Energy of red light | 2 eV |
| Binding energy of a tightly bound molecule | 10 eV |
| Energy to ionize atom or molecule | 10 to 1000 eV |
29-64 §29.7 source ↗
Answer
29 nm,
290 times greater
29-66 §29.7 source ↗
Answer
29-68 §29.7 source ↗
Answer
29-70 §29.7 source ↗
Answer
29-72 §29.8 source ↗
Integrated Concepts
The 54.0-eV electron in Example 29.7 has a 0.167-nm wavelength. If such electrons are passed through a double slit and have their first maximum at an angle of , what is the slit separation ?
Answer
29-74 §29.8 source ↗
Integrated Concepts
A certain heat lamp emits 200 W of mostly IR radiation averaging 1500 nm in wavelength. (a) What is the average photon energy in joules? (b) How many of these photons are required to increase the temperature of a person’s shoulder by , assuming the affected mass is 4.0 kg with a specific heat of . Also assume no other significant heat transfer. (c) How long does this take?
Answer
(a)
(b)
(c)
29-76 §29.8 source ↗
Integrated Concepts
(a) Calculate the amount of microwave energy in joules needed to raise the temperature of 1.00 kg of soup from to . (b) What is the total momentum of all the microwave photons it takes to do this? (c) Calculate the velocity of a 1.00-kg mass with the same momentum. (d) What is the kinetic energy of this mass?
Answer
(a)
(b)
(c)
(d)
29-78 §29.8 source ↗
Integrated Concepts
(a) What is for a proton having an energy of 1.00 TeV, produced by the Fermilab accelerator? (b) Find its momentum. (c) What is the proton’s wavelength?
Answer
(a)
(b)
(c)
29-80 §29.8 source ↗
Integrated Concepts
(a) Calculate the velocity of electrons that form the same pattern as 450-nm light when passed through a double slit. (b) Calculate the kinetic energy of each and compare them. (c) Would either be easier to generate than the other? Explain.
Answer
(a)
(b) for photon, for electron, photon energy is times greater
(c) The light is easier to make because 450-nm light is blue light and therefore easy to make. Creating electrons with of energy would not be difficult, but would require a vacuum.
29-81 §29.8 source ↗
Integrated Concepts
(a) What is the separation between double slits that produces a second-order minimum at for 650-nm light? (b) What slit separation is needed to produce the same pattern for 1.00-keV protons.
Answer
(a)
(b)
29-83 §29.8 source ↗
Integrated Concepts
One problem with x rays is that they are not sensed. Calculate the temperature increase of a researcher exposed in a few seconds to a nearly fatal accidental dose of x rays under the following conditions. The energy of the x-ray photons is 200 keV, and of them are absorbed per kilogram of tissue, the specific heat of which is . (Note that medical diagnostic x-ray machines cannot produce an intensity this great.)
Answer
29-85 §29.8 source ↗
Integrated Concepts
The momentum of light is exactly reversed when reflected straight back from a mirror, assuming negligible recoil of the mirror. Thus the change in momentum is twice the photon momentum. Suppose light of intensity reflects from a mirror of area . (a) Calculate the energy reflected in 1.00 s. (b) What is the momentum imparted to the mirror? (c) Using the most general form of Newton’s second law, what is the force on the mirror? (d) Does the assumption of no mirror recoil seem reasonable?
Answer
(a) 2.00 kJ
(b)
(c)
(d) yes
29-87 §29.8 source ↗
Answer
(a)
(b)
(c) Yes, conservation of momentum applies.
(d) The photon with the longer wavelength has less momentum than the one with the shorter wavelength.
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Problems and answers are adapted from College Physics 2e by Paul Peter Urone, Roger Hinrichs, Kim Dirks and Manjula Sharma, OpenStax, and are used under the CC BY-NC-SA 4.0 licence. Access for free at https://openstax.org/books/college-physics-2e/pages/1-introduction-to-science-and-the-realm-of-physics-physical-quantities-and-units. Illustrations: Copyright Rice University, OpenStax, under CC BY-NC-SA 4.0 license. This adaptation is released under the same licence, is non-commercial, and is neither affiliated with nor endorsed by OpenStax or Rice University.