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Chapter 6: Vector Calculus

293 problems · 48 figures

Checkpoint 6.1 §6.1 source ↗

Let G(x,y)= x2yi− (x+y)j be a vector field in ℝ2. What vector is associated with the point (−2,3)?

Answer

12 i − j

Checkpoint 6.2 §6.1 source ↗

Draw the radial field F(x,y)= − x3i− y3j.

Answer


A visual representation of the given radial field in a coordinate plane. The magnitudes increase further from the origin. The arrow seem to be stretching away from the origin in a rectangular shape.

Checkpoint 6.3 §6.1 source ↗

Sketch vector field F(x,y)= 〈−2y, 2x〉. Is the vector field radial, rotational, or neither?

Answer

Rotational

A visual representation of a rotational vector field in a coordinate plane. The arrows circle the origin in a counterclockwise manner.

Checkpoint 6.4 §6.1 source ↗

Vector field v(x,y)= 〈4|x|, 1〉 models the velocity of water on the surface of a river. What is the speed of the water at point (2,3)? Use meters per second as the units.

Answer

65 m/sec

Checkpoint 6.5 §6.1 source ↗

Is vector field F(x,y)= 〈−y, x〉 a unit vector field?

Answer

No.

Checkpoint 6.6 §6.1 source ↗

Sketch vector field G(x,y,z)= 〈2, z2, 1〉.

Answer


A visual representation of the given vector field in three dimensions. The x and z components are always 2 and 1, respectively. The y component is z/2. The closer z comes to zero, the smaller the y component is, and the further away z is from zero, the larger the y component is.

Checkpoint 6.7 §6.1 source ↗

The mass of asteroid 1 is 750,000 kg and the mass of asteroid 2 is 130,000 kg. Assume asteroid 1 is located at the origin, and asteroid 2 is located at (15,−5,10), measured in units of 10 to the eighth power kilometers. Given that the universal gravitational constant is G= 6.67384×10−11m3kg−1s−2, find the gravitational force vector that asteroid 1 exerts on asteroid 2.

Answer

–1.49063× 10 −18 , 4.96876× 10 −19 , –9.93752× 10 −19 N

Checkpoint 6.8 §6.1 source ↗

Use technology to plot the gradient vector field of f(x,y)= sinxcosy.

Answer


A visual representation of the given given vector in two dimensions. The arrows seem to be forming several ovals. The first is around the origin, where the arrows curve to the right above and below the x axis. The closer the arrows are to the x axis, the flatter they are. There appear to be six other ovals, three on either side of the central one. The vectors get longer as they get farther from the origin, and then they start to get shorter again.

Checkpoint 6.9 §6.1 source ↗

Is f(x,y,z)= x2cos(yz)+ y2z2 a potential function for F(x,y,z)= 〈2xcos(yz), −x2zsin(yz)+ 2yz2, y2〉?

Answer

No

Checkpoint 6.10 §6.1 source ↗

Verify that f(x,y)= x3y2+ 1 is a potential function for velocity field v(x,y)= ⟨3x2y2, 2x3y⟩.

Answer

∇ f = v

Checkpoint 6.11 §6.1 source ↗

Show that the vector field F(x,y)= yi− x2xyj is not conservative.

Answer

P y = x≠ Q x = −2xy

Checkpoint 6.12 §6.1 source ↗

Is vector field G(x,y,z)= 〈y, x, xyz〉 conservative?

Answer

No

6-1 §6.1 source ↗

The domain of vector field F=F(x,y) is a set of points (x,y) in a plane, and the range of F is a set of what in the plane?

Answer

Vectors

6-3 §6.1 source ↗

For the following exercises, determine whether the statement is true or false.

Vector field F= 〈y,x〉x2+y2 is constant in direction and magnitude on a unit circle.

Answer

False

6-5 §6.1 source ↗

For the following exercises, describe each vector field by drawing some of its vectors.

[T] F(x,y)= xi+ yj

Answer


A visual representation of a vector field in two dimensions. The arrows are larger the further they are from the origin. They stretch away from the origin in a radial pattern.

6-7 §6.1 source ↗

For the following exercises, describe each vector field by drawing some of its vectors.

[T] F(x,y)= xi− yj

Answer


A visual representation of a vector field in two dimensions. The arrows are larger the further they are from the origin and the further to the left and right they are from the y axis. The arrows asymptotically curve down and to the right in quadrant 1, down and to the left in quadrant 2, up and to the left in quadrant 3, and up and to the right in quadrant four.

6-9 §6.1 source ↗

For the following exercises, describe each vector field by drawing some of its vectors.

[T] F(x,y)= 2xi+ 3yj

Answer


A visual representation of a vector field in two dimensions. The arrows are larger the further away from the origin they are and, even more so, the further away from the y axis they are. They stretch out away from the origin in a radial manner.

6-11 §6.1 source ↗

For the following exercises, describe each vector field by drawing some of its vectors.

[T] F(x,y)= yi+ sinxj

Answer


A visual representation of a vector field in two dimensions. The arrows are larger the further away they are from the x axis. The arrows form two radial patterns, one on each side of the y axis. The patterns are clockwise.

6-13 §6.1 source ↗

For the following exercises, describe each vector field by drawing some of its vectors.

[T] F(x,y,z)= 2xi− 2yj− 2zk

Answer


A visual representation of a vector field in three dimensions. The arrows seem to get smaller as both the z component gest close to zero and the x component gets larger, and as both the y and z components get larger. The arrows seem to converge in both of those directions as well.

6-15 §6.1 source ↗

For the following exercises, find the gradient vector field of each function f.

f(x,y)= xsiny+ cosy

Answer

F (x,y)= sin(y) i + (xcosy−siny) j

6-17 §6.1 source ↗

For the following exercises, find the gradient vector field of each function f.

f(x,y,z)= x 2 y+ xy+ y 2 z

Answer

F (x,y,z)= (2xy+y) i + ( x 2 +x+2yz) j + y 2 k

6-19 §6.1 source ↗

For the following exercises, find the gradient vector field of each function f.

f(x,y)= ln(1+ x 2 +2 y 2 )

Answer

F (x,y)= ( 2 x 1 + x 2 + 2 y 2 ) i + ( 4 y 1 + x 2 + 2 y 2 ) j

6-21 §6.1 source ↗

For the following exercises, find the gradient vector field of each function f.

What is vector field F(x,y) with a value at (x,y) that is of unit length and points toward (1,0)?

Answer

F (x,y)= ( 1 − x ) i − y j ( 1 − x ) 2 + y 2

6-23 §6.1 source ↗

For the following exercises, write formulas for the vector fields with the given properties.

All vectors point toward the origin and have constant length.

Answer

F (x,y)= - x i − y j x 2 + y 2

6-25 §6.1 source ↗

For the following exercises, write formulas for the vector fields with the given properties.

Give a formula F(x,y)= M(x,y)i+ N(x,y)j for the vector field in a plane that has the properties that F=0 at (0,0) and that at any other point (a,b), F is tangent to circle x2+y2=a2+b2 and points in the clockwise direction with magnitude F=a2+b2.

Answer

F (x,y)= y i − x j

6-27 §6.1 source ↗

For the following exercises, write formulas for the vector fields with the given properties.

Find a formula for vector field F(x,y)= M(x,y)i+ N(x,y)j given the fact that for all points (x,y), F points toward the origin and F=10x2+y2.

Answer

F (x,y)= −10 ( x 2 + y 2 ) 3 / 2 (x i +y j )

6-29 §6.1 source ↗

For the following exercises, assume that an electric field in the xy-plane caused by an infinite line of charge along the x-axis is a gradient field with potential function V(x,y)= cln(r0x2+y2), where c>0 is a constant and r0 is a reference distance at which the potential is assumed to be zero.

Show that the electric field at a point in the xy-plane is directed outward from the origin and has magnitude E=cr, where r=x2+y2.

Answer

E = c x 2 + y 2 x 2 + y 2 = c x 2 + y 2 = c r

6-31 §6.1 source ↗

A flow line (or streamline) of a vector field F is a curve r(t) such that dr/dt= F(r(t)). If F represents the velocity field of a moving particle, then the flow lines are paths taken by the particle. Therefore, flow lines are tangent to the vector field. For the following exercises, show that the given curve c(t) is a flow line of the given velocity vector field F(x,y,z).

c(t)= sin t , cos t , e t ; F(x,y,z)= ⟨y, −x, z⟩

Answer

c ′(t)= (cost,−sint, e − t )= F ( c (t))

6-33 §6.1 source ↗

For the following exercises, let F=xi+yj, G=−yi+xj, and H=xi−yj. Match F, G, and H with their graphs.

A visual representation of a vector field in two dimensions. The arrows are larger the further away from the origin they are, particularly to the left and right of the y axis. They point to the left and to the right on the left and right sides of the y axis, respectively. They point down above the x axis and up below the x axis. The closer to the x axis, the flatter they are. The closer to the y axis they are, the more vertical they are.

Answer

H

6-35 §6.1 source ↗

For the following exercises, let F=xi+yj, G=−yi+xj, and H=xi–yj. Match the vector fields in a through d with their graphs.

A visual representation of a vector field in two dimensions. The arrows are larger the further away they are from the y axis. They curve in towards the orgin in a spiral pattern, with the arrows curving in from the right to the right of the y axis and curving in from the left to the left of the y axis. The arrows in quadrants 1 and 3 are flatter, and the arrows in quadrants 2 and 4 are more vertical.

Answer

d. −F+G

6-37 §6.1 source ↗

For the following exercises, let F=xi+yj, G=−yi+xj, and H=xi–yj. Match the vector fields in a through d with their graphs.

A visual representation of a vector field in two dimensions. The arrows are larger the further away from y axis they are. The arrows are pointing out from the origin in a spiral shape. In quadrant 1, the arrows are more vertical and curve up. In quadrant 2, the arrows are more horizontal and curve down. In quadrant 3, the arrows are more vertical and curve down. In quadrant 4, the arrows are more horizontal and curve up. Each quadrant’s arrows merge into the two on either side of it.

Answer

a. F+G

Checkpoint 6.13 §6.2 source ↗

Find the value of ∫C(x+y)ds, where C is the curve parameterized by x=t, y=t, 0≤t≤1.

Answer

2

Checkpoint 6.14 §6.2 source ↗

Evaluate ∫C(x2+y2+z)ds, where C is the curve with parameterization r(t)= ⟨sin(3t), cos(3t),t⟩, 0≤t≤2π.

Answer

2 10 π + 2 10 π 2

Checkpoint 6.15 §6.2 source ↗

Evaluate line integral ∫C(x2+yz)ds, where C is the line with parameterization r(t)= 〈2t, 5t, −t〉, 0≤t≤10. Reparameterize C with parameterization s(t)= 〈4t, 10t, −2t〉, 0≤t≤5, recalculate line integral ∫C(x2+yz)ds, and notice that the change of parameterization had no effect on the value of the integral.

Answer

Both line integrals equal −1000303.

Checkpoint 6.16 §6.2 source ↗

Find the length of a wire with parameterization r(t)= 〈3t+ 1, 4− 2t, 5+ 2t〉, 0≤t≤4.

Answer

4 17

Checkpoint 6.17 §6.2 source ↗

Let F=xi+yj be a vector field and let C be the curve with parameterization 〈t,t2〉 for 0≤t≤2. Which is greater: ∫CF·Tds or ∫−CF·Tds?

Answer

∫ C F · T d s

Checkpoint 6.18 §6.2 source ↗

Find the value of ∫C4xdx+zdy+4y2dz, where C is the curve parameterized by r(t)= 〈4cos(2t), 2sin(2t), 3〉, 0≤t≤π4.

Answer

−26

Checkpoint 6.19 §6.2 source ↗

Calculate line integral ∫CF·dr, where F is vector field 〈y2,2xy+1〉 and C is a triangle with vertices (0,0), (4,0), and (0,5), oriented counterclockwise.

Answer

0

Checkpoint 6.20 §6.2 source ↗

Calculate the mass of a spring in the shape of a helix parameterized by r(t)= 〈cost, sint, t〉, 0≤t≤6π, with a density function given by ρ(x,y,z)= x+ y+ z kg/m.

Answer

182π2 kg

Checkpoint 6.21 §6.2 source ↗

Calculate the flux of F=〈x+y,2y〉 across the line segment from (0,0) to (2,3), where the curve is oriented from left to right.

Answer

3/2

Checkpoint 6.22 §6.2 source ↗

Calculate the circulation of F(x,y)= 〈− yx2+y2, xx2+y2〉 along a unit circle oriented counterclockwise.

Answer

2 π

Checkpoint 6.23 §6.2 source ↗

Calculate the work done by field F(x,y)= 〈2x, 3y〉 on a particle that traverses the unit circle. Assume the particle begins its movement at (−1,0).

Answer

0

6-39 §6.2 source ↗

True or False? Line integral ∫Cf(x,y)ds is equal to a definite integral if C is a smooth curve defined on [a,b] and if function f is continuous on some region that contains curve C.

Answer

True

6-41 §6.2 source ↗

True or False? ∫−C(Pdx+Qdy)=∫C(Pdx−Qdy)

Answer

False

6-43 §6.2 source ↗

True or False? If C is given by x(t)= t,y(t)= t, 0≤t≤1, then ∫Cxyds=∫01t2dt.

Answer

False

6-45 §6.2 source ↗

For the following exercises, use a computer algebra system (CAS) to evaluate the line integrals over the indicated path.

[T] ∫C(x−y)ds

C:r(t)= 4ti+ 3tj when 0≤t≤2

Answer

∫ C ( x − y ) d s = 10

6-47 §6.2 source ↗

For the following exercises, use a computer algebra system (CAS) to evaluate the line integrals over the indicated path.

[T] Evaluate ∫Cxy4ds, where C is the right half of circle x2+y2=16 and is traversed in the clockwise direction.

Answer

∫ C x y 4 d s = 8192 5

6-49 §6.2 source ↗

For the following exercises, find the work done.

Find the work done by vector field F(x,y,z)= xi+ 3xyj− (x+z)k on a particle moving along a line segment that goes from (1,4,2) to (0,5,1).

Answer

W = 8

6-51 §6.2 source ↗

For the following exercises, find the work done.

Find the work done by force field F(x,y,z)= − 12xi− 12yj+ 14k on a particle as it moves along the helix r(t)= costi+ sintj+ tk from point (1,0,0) to point (−1,0,3π).

Answer

W = 3 π 4

6-53 §6.2 source ↗

For the following exercises, find the work done.

Find the work done by force F(x,y)= 2yi+ 3xj+ (x+y)k in moving an object along curve r(t)= cos(t)i+ sin(t)j+ 16k, where 0≤t≤2π.

Answer

W = π

6-55 §6.2 source ↗

For the following exercises, evaluate the line integrals.

Evaluate ∫CF·dr, where F(x,y)=−1j, and C is the part of the graph of y=12x3−x from (2,2) to (−2,−2).

Answer

∫ C F · d r = 4

6-57 §6.2 source ↗

For the following exercises, evaluate the line integrals.

Evaluate ∫Cyzdx+xzdy+xydz over the line segment from (1,1,1) to (3,2,0).

Answer

∫ C y z d x + x z d y + x y d z = −1

6-59 §6.2 source ↗

For the following exercises, evaluate the line integrals.

[T] Use a computer algebra system to evaluate the line integral ∫Cy2dx+xdy, where C is the arc of the parabola x=4−y2 from (−5, −3) to (0, 2).

Answer

∫ C ( y 2 ) d x + ( x ) d y = 245 6

6-61 §6.2 source ↗

For the following exercises, evaluate the line integrals.

[T] Use a CAS to evaluate line integral ∫Cxydx+ydy over path C given by x=2t,y=10t, where 0≤t≤1.

Answer

∫ C x y d x + y d y = 190 3

6-63 §6.2 source ↗

For the following exercises, evaluate the line integrals.

[T] Use a CAS to evaluate ∫Cy2x2−y2ds, where C is x= t,y= t,1≤t≤5.

Answer

∫ C y 2 x 2 − y 2 d s = 2 ln 5

6-65 §6.2 source ↗

In the following exercises, find the work done by force field F on an object moving along the indicated path.

F (x,y)= −x i − 2y j

C:y= x 3 from (0, 0) to (2, 8)

Answer

W = −66

6-67 §6.2 source ↗

In the following exercises, find the work done by force field F on an object moving along the indicated path.

F (x,y,z)= x i + y j − 5z k

C: r (t)= 2cost i + 2sint j + t k ,0≤t≤2π

Answer

W = −10 π 2

6-69 §6.2 source ↗

In the following exercises, find the work done by force field F on an object moving along the indicated path.

Compute the work done by force F(x,y,z)= 2xi+ 3yj− zk along path r(t)= ti+ t2j+ t3k, where 0≤t≤1.

Answer

W = 2

6-71 §6.2 source ↗

In the following exercises, find the work done by force field F on an object moving along the indicated path.

Force F(x,y,z)= zyi+ xj+ z2xk acts on a particle that travels from the origin to point (1, 2, 3). Calculate the work done if the particle travels:

a. along the path (0,0,0)→ (1,0,0)→ (1,2,0)→ (1,2,3) along straight-line segments joining each pair of endpoints;

b. along the straight line joining the initial and final points.

c. Is the work the same along the two paths?
A curve and vector field in three dimensions. The curve segments go from (1,2,3) to (0,0,0) to (1,0,0) to (1,2,0), and the arrowheads point to (0,0,0), (1,0,0), and (1,2,0). The surrounding vectors are larger the more the z component increases.

Answer

a. W=11; b. W=394; c. No

6-73 §6.2 source ↗

In the following exercises, find the work done by force field F on an object moving along the indicated path.

How much work is required to move an object in vector field F(x,y)= yi+ 3xj along the upper part of ellipse x24+y2=1 from (2, 0) to (−2,0)?

Answer

W = 2 π

6-75 §6.2 source ↗

In the following exercises, find the work done by force field F on an object moving along the indicated path.

Evaluate the line integral of scalar function xy along parabolic path y=x2 connecting the origin to point (1, 1).

Answer

∫ C x y   d s = 25 5 + 1 120

6-77 §6.2 source ↗

In the following exercises, find the work done by force field F on an object moving along the indicated path.

Find ∫Cy2dx+(xy−x2)dy along C: y2=9x from (0, 0) to (1, 3).

Answer

∫ C y 2 d x + ( x y − x 2 ) d y = 6.15

6-79 §6.2 source ↗

For the following exercises, use a CAS to evaluate the given line integrals.

[T] Evaluate line integral ∫γxeyds where, γ is the arc of curve x=ey from (1,0) to (e,1).

Answer

∫ γ x e y d s ≈ 7.157

6-81 §6.2 source ↗

For the following exercises, use a CAS to evaluate the given line integrals.

[T] Evaluate line integral ∫γ(y2−xy)ds, where γ is curve y=lnx from (1, 0) toward (e,1).

Answer

∫ γ ( y 2 − x y ) d x ≈ −1.379

6-83 §6.2 source ↗

For the following exercises, use a CAS to evaluate the given line integrals.

[T] Evaluate ∫CF·dr, where F(x,y,z)= x2yi+ (x−z)j+ xyzk and

C: r(t)= ti+ t2j+ 2k,0≤t≤1.

Answer

∫ C F · d r ≈ −1.133

6-85 §6.2 source ↗

For the following exercises, use a CAS to evaluate the given line integrals.

Find the line integral of F(x,y,z)= 12x2i− 5xyj+ xzk over path C defined by y=x2, z=x3 from point (0, 0, 0) to point (2, 4, 8).

Answer

∫ C F · d r ≈ 2 2 . 8 5 7

6-87 §6.2 source ↗

For the following exercises, find the flux.

Compute the flux of F=x2i+yj across a line segment from (0, 0) to (1, 2).

Answer

flux = − 1 3

6-89 §6.2 source ↗

For the following exercises, find the flux.

Let F=5j and let C be curve y=0,0≤x≤4. Find the flux across C.

Answer

flux = −20

6-91 §6.2 source ↗

For the following exercises, find the flux.

Let F= (x2+y3)i+ (2xy)j. Calculate flux F orientated counterclockwise across curve C: x2+y2=9.

Answer

flux = 0

6-93 §6.2 source ↗

For the following exercises, find the flux.

A spring is made of a thin wire twisted into the shape of a circular helix x= 2cost,y= 2sint,z= t. Find the mass of two turns of the spring if the wire has constant mass density.

Answer

m = 4 π ρ 5

6-95 §6.2 source ↗

For the following exercises, find the flux.

An object moves in force field F(x,y,z)= y2i+ 2(x+1)yj counterclockwise from point (2, 0) along elliptical path x2+4y2=4 to (−2,0), and back to point (2, 0) along the x-axis. How much work is done by the force field on the object?

Answer

W = 0

6-97 §6.2 source ↗

For the following exercises, find the flux.

If an inverse force field F is given by F(x,y,z)= k‖r‖3r, where k is a constant, find the work done by F as its point of application moves along the x-axis from A(1,0,0)toB(2,0,0).

Answer

W = k 2

Checkpoint 6.24 §6.3 source ↗

Is the curve given by parameterization r(t)= 〈2cost, 3sint〉, 0≤t≤6π, a simple closed curve?

Answer

Yes

Checkpoint 6.25 §6.3 source ↗

Is the region in the below image connected? Is the region simply connected?

A shaded circle with an open space in the shape of a circle inside it but very close to the boundary.

Answer

The region in the figure is connected. The region in the figure is not simply connected.

Checkpoint 6.26 §6.3 source ↗

Given that f(x,y)= (x−1)2y+ (y+1)2x is a potential function for F= 〈2xy− 2y+ (y+1)2, (x−1)2+ 2yx+ 2x〉, calculate integral ∫CF·dr, where C is the lower half of the unit circle oriented counterclockwise.

A vector field in two dimensions. The arrows near the origin are the shortest, and the arrows in the upper right and lower left corners of quadrants 1 and 3 are the shortest. The arrows go up and to the left in quadrants 1 and 3. In quadrant 2, the arrows stretch up and to the right for values greater than x=-1. The closer the arrows are to y=1, the more horizontal they become. For values less than x=-1, the arrows point up and form a curve to the left. The closer the arrows are to y=1, the more horizontal they become. Above y=1, it looks like the arrows are shifting from vertical, going down to horizontal. In quadrant 4, the arrows go up and to the right fairly regularly, but they tend to be curving to the right the larger the x value becomes. For y values less than -1, the arrows shift from pointing up to pointing down, following x=1. The lower half of the unit circle with center at the origin is drawn in quadrants 3 and 4.

Answer

2

Checkpoint 6.27 §6.3 source ↗

Show that F(x,y)= 〈xy, x2y2〉 is not path independent by considering the line segment from (0,0) to (2,2) and the piece of the graph of y=x22 that goes from (0,0) to (2,2).

Answer

If C1 and C2 represent the two curves, then ∫C1F·dr≠∫C2F·dr.

Checkpoint 6.28 §6.3 source ↗

Find a potential function for F(x,y)= 〈exy3+ y, 3exy2+ x〉.

Answer

f(x,y)= e x y 3 + xy

Checkpoint 6.29 §6.3 source ↗

Find a potential function for F(x,y,z)= 〈12x2, cosycosz, 1− sinysinz〉.

Answer

f(x,y,z)= 4 x 3 + sinycosz+ z

Checkpoint 6.30 §6.3 source ↗

Find a potential function f for the three-dimensional gravitational force F(x,y,z)= 〈−Gx(x2+y2+z2)3/2, −Gy(x2+y2+z2)3/2, −Gz(x2+y2+z2)3/2〉.

Answer

f(x,y,z)= G x 2 + y 2 + z 2

Checkpoint 6.31 §6.3 source ↗

Determine whether F(x,y)= 〈sinxcosy, cosxsiny〉 is conservative.

Answer

It is conservative.

Checkpoint 6.32 §6.3 source ↗

Calculate integral ∫CF·dr, where F(x,y)= 〈sinxsiny, 5− cosxcosy〉 and C is a semicircle with starting point (0,π) and endpoint (0,−π).

Answer

−10 π

Checkpoint 6.33 §6.3 source ↗

Let F(x,y)= 〈4x3y4, 4x4y3〉, and suppose that a particle moves from point (4,4) to (1,1) along any smooth curve. Is the work done by F on the particle positive, negative, or zero?

Answer

Negative

6-99 §6.3 source ↗

True or False? If vector field F is conservative on the open and connected region D, then line integrals of F are path independent on D, regardless of the shape of D.

Answer

True

6-101 §6.3 source ↗

True or False? Vector field F(x,y,z)= (ysinz)i+ (xsinz)j+ (xycosz)k is conservative.

Answer

True

6-103 §6.3 source ↗

Verify the Fundamental Theorem of Line Integrals for ∫CF·dr by computing the integral using a parameterization and, separately, by finding a potential function for the case when F(x,y)= (2x+2y)i+ (2x+2y)j and C is a portion of circle x2+y2=25 oriented counterclockwise from (5, 0) to (3, 4).

Answer

∫ C F · d r = 24

6-105 §6.3 source ↗

[T] Evaluate line integral ∫CF·dr, where F(x,y)= (exsiny−y)i+ (excosy−x−2)j, and C is the path given by r(t)= [t3sinπt2]i− [π2cos(πt2+π2)]j for 0≤t≤1.

Answer

∫ C F · d r = e− 3 π 2

6-107 §6.3 source ↗

For the following exercises, determine whether the vector field is conservative and, if it is, find the potential function.

F (x,y)= (−y+ e x siny) i + [(x+2) e x cosy] j

Answer

Not conservative

6-109 §6.3 source ↗

For the following exercises, determine whether the vector field is conservative and, if it is, find the potential function.

F (x,y)= (6x+5y) i + (5x+4y) j

Answer

Conservative, f(x,y)= 3x2+ 5xy+ 2y2

6-111 §6.3 source ↗

For the following exercises, determine whether the vector field is conservative and, if it is, find the potential function.

F (x,y)= [y e x +sin(y)] i + [ e x +xcos(y)] j

Answer

Conservative, f(x,y)= yex+ xsin(y)

6-113 §6.3 source ↗

For the following exercises, evaluate the line integrals using the Fundamental Theorem of Line Integrals.

∫C(2ydx+2xdy), where C is the line segment from (0, 0) to (4, 4)

Answer

∫ C ( 2 y d x + 2 x d y ) = 32

6-115 §6.3 source ↗

For the following exercises, evaluate the line integrals using the Fundamental Theorem of Line Integrals.

Find the conservative vector field for the potential function

f ( x , y ) = 5 x 2 + 3 x y + 10 y 2 .

Answer

F (x,y)= (10x+3y) i + (3x+20y) j

6-117 §6.3 source ↗

For the following exercises, determine whether the vector field is conservative and, if so, find a potential function.

F (x,y)= ( e x cosy) i + 6( e x siny) j

Answer

F is not conservative.

6-119 §6.3 source ↗

For the following exercises, determine whether the vector field is conservative and, if so, find a potential function.

F (x,y,z)= (y e z ) i + (x e z ) j + (xy e z ) k

Answer

F is conservative and a potential function is f(x,y,z)= xyez.

6-121 §6.3 source ↗

For the following exercises, determine whether the vector field is conservative and, if so, find a potential function.

F (x,y,z)= (– 1 y ) i + ( x y 2 ) j + (2z−1) k

Answer

F is conservative and a potential function is f(x,y,z)= z2–z–xy.

6-123 §6.3 source ↗

For the following exercises, determine whether the vector field is conservative and, if so, find a potential function.

F (x,y,z)= (2xy) i + ( x 2 +2yz) j + y 2 k

Answer

F is conservative and a potential function is f(x,y,z)= x2y+ y2z.

6-125 §6.3 source ↗

For the following exercises, determine whether the vector field is conservative and, if so, find a potential function.

F (x,y)= (y e x 2 ) i + ( x 2 e y 2 ) j

Answer

F is conservative and a potential function is f(x,y)=ex2y

6-127 §6.3 source ↗

For the following exercises, evaluate the integral using the Fundamental Theorem of Line Integrals.

[T] Evaluate ∫C∇f·dr, where f(x,y)= xy+ ex and C is a straight line from (0,0) to (2,1).

Answer

∫ C F · d r = e 2 + 1

6-129 §6.3 source ↗

For the following exercises, evaluate the integral using the Fundamental Theorem of Line Integrals.

Evaluate ∫C∇f·dr, where f(x,y,z)= xyz2− yz and C has initial point (1, 2, 3) and terminal point (3, 5, 1).

Answer

∫ C F · d r = -2

6-131 §6.3 source ↗

For the following exercises, let F(x,y)= 2xy2i+ (2yx2+2y)j and G(x,y)= (y+x)i+ (y−x)j, and let C1 be the curve consisting of the circle of radius 2, centered at the origin and oriented counterclockwise, and C2 be the curve consisting of a line segment from (0, 0) to (1, 1) followed by a line segment from (1, 1) to (3, 1).

A vector fields in two dimensions is shown. It has short arrows close to the origin. Longer arrows are in the upper right corner of quadrant 1 and somewhat in the bottom right of quadrant 4, upper left of quadrant 2, and lower left of quadrant 3. The arrows all point away from the origin at about 90-degrees in their respective quadrants. A unit circle with center at the origin is drawn as C_1. Curve C_2 connects the origin, (1,1), and (3,1) with arrowheads pointing in that order. A vector field has the same curves C_1 and C_2. However, the arrows are different. Here, the arrows spiral out from the origin in a clockwise manner. The further away they are from the origin, the longer they become. They are largely horizontal in quadrants 1 and 3 and largely vertical in quadrants 2 and 4.

Calculate the line integral of G over C1.

Answer

∫ C 1 G · d r = −8 π

6-133 §6.3 source ↗

For the following exercises, let F(x,y)= 2xy2i+ (2yx2+2y)j and G(x,y)= (y+x)i+ (y−x)j, and let C1 be the curve consisting of the circle of radius 2, centered at the origin and oriented counterclockwise, and C2 be the curve consisting of a line segment from (0, 0) to (1, 1) followed by a line segment from (1, 1) to (3, 1).

A vector fields in two dimensions is shown. It has short arrows close to the origin. Longer arrows are in the upper right corner of quadrant 1 and somewhat in the bottom right of quadrant 4, upper left of quadrant 2, and lower left of quadrant 3. The arrows all point away from the origin at about 90-degrees in their respective quadrants. A unit circle with center at the origin is drawn as C_1. Curve C_2 connects the origin, (1,1), and (3,1) with arrowheads pointing in that order. A vector field has the same curves C_1 and C_2. However, the arrows are different. Here, the arrows spiral out from the origin in a clockwise manner. The further away they are from the origin, the longer they become. They are largely horizontal in quadrants 1 and 3 and largely vertical in quadrants 2 and 4.

Calculate the line integral of G over C2.

Answer

∫ C 2 G · d r = 7

6-135 §6.3 source ↗

For the following exercises, let F(x,y)= 2xy2i+ (2yx2+2y)j and G(x,y)= (y+x)i+ (y−x)j, and let C1 be the curve consisting of the circle of radius 2, centered at the origin and oriented counterclockwise, and C2 be the curve consisting of a line segment from (0, 0) to (1, 1) followed by a line segment from (1, 1) to (3, 1).

A vector fields in two dimensions is shown. It has short arrows close to the origin. Longer arrows are in the upper right corner of quadrant 1 and somewhat in the bottom right of quadrant 4, upper left of quadrant 2, and lower left of quadrant 3. The arrows all point away from the origin at about 90-degrees in their respective quadrants. A unit circle with center at the origin is drawn as C_1. Curve C_2 connects the origin, (1,1), and (3,1) with arrowheads pointing in that order. A vector field has the same curves C_1 and C_2. However, the arrows are different. Here, the arrows spiral out from the origin in a clockwise manner. The further away they are from the origin, the longer they become. They are largely horizontal in quadrants 1 and 3 and largely vertical in quadrants 2 and 4.

[T] Find line integral ∫CF·dr of vector field F(x,y,z)= 3x2zi+ z2j+ (x3+2yz)k along curve C parameterized by r(t)= (lntln2)i+ t3/2j+ tcos(πt)k,1≤t≤4.

Answer

∫ C F · d r = 159

6-137 §6.3 source ↗

For the following exercises, show that the following vector fields are conservative by using a computer. Calculate ∫CF·dr for the given curve.

F= 2xy2+1i− 2y(x2+1)(y2+1)2j; C is parameterized by x= t3− 1, y= t6− t, 0≤t≤1.

Answer

∫ C F · d r = −1

6-139 §6.3 source ↗

For the following exercises, show that the following vector fields are conservative by using a computer. Calculate ∫CF·dr for the given curve.

The mass of Earth is approximately 6×1027g and that of the Sun is 330,000 times as much. The gravitational constant is 6.7×10−8cm3/(s2·g). The distance of Earth from the Sun is about 1.5×1012cm. Compute, approximately, the work necessary to increase the distance of Earth from the Sun by 1cm.

Answer

4 × 10 29 erg

6-141 §6.3 source ↗

For the following exercises, show that the following vector fields are conservative by using a computer. Calculate ∫CF·dr for the given curve.

[T] Let r:[1,2]→ℝ2 be given by x= et−1, y= sin(πt). Use a computer to compute the integral ∫CF·dr=∫C2xcosydx−x2sinydy, where F= (2xcosy)i− (x2siny)j.

Answer

∫ C F · d r ≈ 2 . 9923

6-143 §6.3 source ↗

For the following exercises, show that the following vector fields are conservative by using a computer. Calculate ∫CF·dr for the given curve.

Find the circulation and flux of field F=−yi+xj around and across the closed semicircular path that consists of semicircular arch r1(t)= (acost)i+ (asint)j, 0≤t≤π, followed by line segment r2(t)= ti, −a≤t≤a.

A vector field in two dimensions. The arrows are shorter the closer they are to the origin. They surround the origin in a counterclockwise radial pattern. The outline of the circle has counterclockwise arrows. The upper half of a circle with radius 2 and center at the origin is drawn. (-2,0) and (2,0) are labeled as –a and a, respectively, and the curve is labeled r_1.

Answer

circulation= π a 2 and flux= 0

Checkpoint 6.34 §6.4 source ↗

Use Green’s theorem to calculate line integral

∫Csin(x2)dx+(3x−y)dy,

where C is a right triangle with vertices (−1,2), (4,2), and (4,5) oriented counterclockwise.

Answer

45 2

Checkpoint 6.35 §6.4 source ↗

Find the area of the region enclosed by the curve with parameterization r(t)= 〈sintcost, sint〉, 0≤t≤π.

An image of a curve in quadrants 1 and 2. The curve begins at the origin, curves up and to the right until about (.5, 1), turns left to go through (0, 1), and curves down going through (-.5, 1) and then goes down and right until it hits the origin again.

Answer

2 3

Checkpoint 6.36 §6.4 source ↗

Calculate the flux of F(x,y)= 〈x3, y3〉 across a unit circle oriented counterclockwise.

Answer

3 π 2

Checkpoint 6.37 §6.4 source ↗

Find a stream function for vector field F(x,y)= 〈xsiny, cosy〉.

Answer

g(x,y)= −xcosy

Checkpoint 6.38 §6.4 source ↗

Is the function f(x,y)= ex+5y harmonic?

Answer

No

Checkpoint 6.39 §6.4 source ↗

Calculate integral ∫∂DF·dr, where D is the annulus given by the polar inequalities 2≤r≤5, 0≤θ≤2π, and F(x,y)= 〈x3, 5x+ eysiny〉.

Answer

105 π

6-147 §6.4 source ↗

For the following exercises, evaluate the line integrals by applying Green’s theorem.

∫C2xydx+(x+y)dy, where C is the boundary of the region lying between the graphs of y=0 and y=4−x2 oriented in the counterclockwise direction

Answer

∫ C 2 x y d x + ( x + y ) d y = 32 3

6-149 §6.4 source ↗

For the following exercises, evaluate the line integrals by applying Green’s theorem.

∫Csinxcosydx+(xy+cosxsiny)dy, where C is the boundary of the region lying between the graphs of y=x and y=x oriented in the counterclockwise direction

Answer

∫ C sin x cos y d x + ( x y + cos x sin y ) d y = 1 12

6-151 §6.4 source ↗

For the following exercises, evaluate the line integrals by applying Green’s theorem.

∫C(−ydx+xdy), where C consists of line segment C1 from (−1,0) to (1, 0), followed by the semicircular arc C2 from (1, 0) back to (–1, 0)

Answer

∫ C ( − y d x + x d y ) = π

6-153 §6.4 source ↗

For the following exercises, use Green’s theorem.

Evaluate line integral ∫Cxe−2xdx+(x4+2x2y2)dy, where C is the boundary of the region between circles x2+y2=1 and x2+y2=4, and is a positively oriented curve.

Answer

∫ C x e −2 x d x + ( x 4 + 2 x 2 y 2 ) d y = 0

6-155 §6.4 source ↗

For the following exercises, use Green’s theorem.

Evaluate ∫Cy3dx−x3y2dy, where C is the positively oriented circle of radius 2 centered at the origin.

Answer

∫Cy3dx−x3ydy=−20π

6-157 §6.4 source ↗

For the following exercises, use Green’s theorem.

Calculate ∫C−x2ydx+xy2dy, where C is a circle of radius 2 centered at the origin and oriented in the counterclockwise direction.

Answer

∫ C − x 2 y d x + x y 2 d y = 8π

6-159 §6.4 source ↗

For the following exercises, use Green’s theorem.

Evaluate integral ∫C(x2+y2)dx+2xydy, where C is the curve that follows parabola y= x2from(0,0) to (2,4), then the line from (2, 4) to (2, 0), and finally the line from (2, 0) to (0, 0).

A vector field in quadrant 1. The arrows are much smaller closer to the origin. They point up and away from the origin, with increasing slope the further they are to the right. The curve follows the parabola y=x^2 from the origin to (2,4), the line from (2,4) to (2,0), and the line from (2,0) to (0,0). The area under y=x^2 and below the parabola is shaded.

Answer

∫ C ( x 2 + y 2 ) d x + 2 x y d y = 0

6-161 §6.4 source ↗

For the following exercises, use Green’s theorem to find the area.

Find the area between ellipse x29+y24=1 and circle x2+y2=25.

Answer

A = 19 π

6-163 §6.4 source ↗

For the following exercises, use Green’s theorem to find the area.

Find the area of the region bounded by hypocycloid r(t)= cos3(t)i+ sin3(t)j. The curve is parameterized by t∈[0,2π].

Answer

A = 3 π 8

6-165 §6.4 source ↗

For the following exercises, use Green’s theorem to find the area.

Use Green’s theorem to evaluate ∫C+(y2+x3)dx+ x4dy, where C+ is the perimeter of square [0,1]×[0,1] oriented counterclockwise.

Answer

∫ C + ( y 2 + x 3 ) d x + x 4 d y = 0

6-167 §6.4 source ↗

For the following exercises, use Green’s theorem to find the area.

Use Green’s theorem to find the area of one loop of a four-leaf rose r=3sin2θ. (Hint: xdy− ydx= r2dθ).

Answer

A = 9 π 8

6-169 §6.4 source ↗

For the following exercises, use Green’s theorem to find the area.

Use Green’s theorem to find the area of the region enclosed by curve

r ( t ) = t 2 i + ( t 3 3 − t ) j , − 3 ≤ t ≤ 3 . A horizontal teardrop-shaped region symmetric about the x axis and a-intercepts at the origin and (3,0). The larger, curved end is at the origin, and the pointed end is at (3,0).

Answer

A = 8 3 5

6-171 §6.4 source ↗

For the following exercises, use Green’s theorem to find the area.

Evaluate ∫C(x2y−2xy+y2)ds, where C is the boundary of the unit square 0≤x≤1,0≤y≤1, traversed counterclockwise. Use ds =  dx +  dy for this exercise.

Answer

∫ C ( x 2 y − 2 x y + y 2 ) d s = 1 2

6-173 §6.4 source ↗

For the following exercises, use Green’s theorem to find the area.

Evaluate ∫Cxdx+ydyx2+y2, where C is any piecewise, smooth simple closed curve enclosing the origin, traversed counterclockwise.

Answer

∫ C x d x + y d y x 2 + y 2 = 0

6-175 §6.4 source ↗

For the following exercises, use Green’s theorem to calculate the work done by force F on a particle that is moving counterclockwise around closed path C.

F(x,y)= (x3/2−3y)i+ (6x+5y)j, C : boundary of a triangle with vertices (0, 0), (5, 0), and (0, 5)

Answer

W = 225 2

6-177 §6.4 source ↗

For the following exercises, use Green’s theorem to calculate the work done by force F on a particle that is moving counterclockwise around closed path C.

A particle starts at point (−2,0), moves along the x-axis to (2, 0), and then travels along semicircle y=4−x2 to the starting point. Use Green’s theorem to find the work done on this particle by force field F(x,y)= xi+ (x3+3xy2)j.

Answer

W = 12 π

6-179 §6.4 source ↗

For the following exercises, use Green’s theorem to calculate the work done by force F on a particle that is moving counterclockwise around closed path C.

Use Green’s theorem to find the work done by force field F(x,y)= (3y−4x)i+ (4x−y)j when an object moves once counterclockwise around ellipse 4x2+y2=4.

Answer

W = 2 π

6-181 §6.4 source ↗

For the following exercises, use Green’s theorem to calculate the work done by force F on a particle that is moving counterclockwise around closed path C.

Evaluate line integral ∫Cy2dx+x2dy, where C is the boundary of a triangle with vertices (0,0), (1,1), and(1,0), with the counterclockwise orientation.

Answer

∫ C y 2 d x + x 2 d y = 1 3

6-183 §6.4 source ↗

For the following exercises, use Green’s theorem to calculate the work done by force F on a particle that is moving counterclockwise around closed path C.

Use Green’s theorem to evaluate line integral ∫C1+x3dx+2xydy where C is a triangle with vertices (0, 0), (1, 0), and (1, 3) oriented clockwise.

Answer

∫ C 1 + x 3 d x + 2 x y d y = -3

6-185 §6.4 source ↗

For the following exercises, use Green’s theorem to calculate the work done by force F on a particle that is moving counterclockwise around closed path C.

Use Green’s theorem to evaluate line integral ∫C(3y−esinx)dx+ (7x+y4+1)dy where C is circle x2+y2=9 oriented in the counterclockwise direction.

Answer

∫ C ( 3 y − e sin x ) d x + (7x+ y 4 + 1 )dy= 36π

6-187 §6.4 source ↗

For the following exercises, use Green’s theorem to calculate the work done by force F on a particle that is moving counterclockwise around closed path C.

Let C be a triangular closed curve from (0, 0) to (1, 0) to (1, 1) and finally back to (0, 0). Let F(x,y)= 4yi+ 6x2j. Use Green’s theorem to evaluate ∫CF·dr.

Answer

∫ C F · d r = 2

6-189 §6.4 source ↗

For the following exercises, use Green’s theorem to calculate the work done by force F on a particle that is moving counterclockwise around closed path C.

Use Green’s theorem to evaluate line integral ∫C(y+x)dx+(x+siny)dy, where C is any smooth simple closed curve joining the origin to itself oriented in the counterclockwise direction.

Answer

∫ C ( y + x ) d x + ( x + sin y ) d y = 0

6-191 §6.4 source ↗

For the following exercises, use Green’s theorem to calculate the work done by force F on a particle that is moving counterclockwise around closed path C.

Use Green’s theorem to evaluate ∫Cxydx+x3y3dy, where C is a triangle with vertices (0, 0), (1, 0), and (1, 2) with positive orientation.

Answer

∫ C x y d x + x 3 y 3 d y = 22 21

6-193 §6.4 source ↗

For the following exercises, use Green’s theorem to calculate the work done by force F on a particle that is moving counterclockwise around closed path C.

Let F(x,y)= (cos(x5))− 13y3i+ 13x3j. Find the counterclockwise circulation ∫CF·dr, where C is a curve consisting of the line segment joining (−2,0)and(−1,0), half circle y=1−x2, the line segment joining (1, 0) and (2, 0), and half circle y=4−x2.

Answer

∫ C F · d r = 15 π 4

6-195 §6.4 source ↗

For the following exercises, use Green’s theorem to calculate the work done by force F on a particle that is moving counterclockwise around closed path C.

Let C be the boundary of square 0≤x≤π,0≤y≤π, traversed counterclockwise. Use Green’s theorem to find ∫Csin(x+y)dx+cos(x+y)dy.

Answer

∫ C sin ( x + y ) d x + cos ( x + y ) d y = 4

6-197 §6.4 source ↗

For the following exercises, use Green’s theorem to calculate the work done by force F on a particle that is moving counterclockwise around closed path C.

Use Green’s Theorem to evaluate integral ∫CF·dr, where F(x,y)= (xy2)i+ xj, and C is a unit circle oriented in the counterclockwise direction.

Answer

∫ C F · d r = π

6-199 §6.4 source ↗

For the following exercises, use Green’s theorem to calculate the work done by force F on a particle that is moving counterclockwise around closed path C.

Calculate the outward flux of F=−xi+2yj over a square with corners (±1,±1), where the unit normal is outward pointing and oriented in the counterclockwise direction.

Answer

∫ C F · N ^ d s = 4

6-201 §6.4 source ↗

For the following exercises, use Green’s theorem to calculate the work done by force F on a particle that is moving counterclockwise around closed path C.

Find the flux of field F=−xi+yj across x2+y2=16 oriented in the counterclockwise direction.

Answer

∫ C F · N d s = 0

6-203 §6.4 source ↗

For the following exercises, use Green’s theorem to calculate the work done by force F on a particle that is moving counterclockwise around closed path C.

[T] Let C be unit circle x2+y2=1 traversed once counterclockwise. Evaluate ∫C[−y3+sin(xy)+xycos(xy)]dx+[x3+x2cos(xy)]dy by using a computer algebra system.

Answer

∫ C [ − y 3 + sin ( x y ) + x y cos ( x y ) ] d x + [ x 3 + x 2 cos ( x y ) ] d y = 4.7124

6-205 §6.4 source ↗

For the following exercises, use Green’s theorem to calculate the work done by force F on a particle that is moving counterclockwise around closed path C.

Consider region R bounded by parabolas y= x2andx= y2. Let C be the boundary of R oriented counterclockwise. Use Green’s theorem to evaluate ∫C(y+ex)dx+(2x+cos(y2))dy.

Answer

∫ C ( y + e x ) d x + ( 2 x + cos ( y 2 ) ) d y = 1 3

Checkpoint 6.40 §6.5 source ↗

Find divF for F(x,y,z)= 〈xy, 5− z2y, x2+ y2〉.

Answer

y − z 2

Checkpoint 6.41 §6.5 source ↗

Let F(x,y)= 〈−ay, bx〉 be a rotational field where a and b are positive constants. Is F source free?

Answer

Yes

Checkpoint 6.42 §6.5 source ↗

For vector field v(x,y)= 〈−xy, y〉, y> 0, find all points P such that the amount of fluid flowing in to P equals the amount of fluid flowing out of P.

Answer

All points on line y=1.

Checkpoint 6.43 §6.5 source ↗

Find the curl of F= 〈sinxcosz, sinysinz, cosxcosy〉 at point (0,π2,π2).

Answer

− i

Checkpoint 6.44 §6.5 source ↗

Field v(x,y)= 〈− yx2+y2, xx2+y2〉 models the flow of a fluid. Show that if you drop a leaf into this fluid, as the leaf moves over time, the leaf does not rotate.

Answer

curl v = 0

Checkpoint 6.45 §6.5 source ↗

Is it possible for G(x,y,z)= 〈sinx, cosy, sin(xyz)〉 to be the curl of a vector field?

Answer

No

Checkpoint 6.46 §6.5 source ↗

Is it possible for function f(x,y)= x2− y2+ x to be the potential function of an electrostatic field located in a region of ℝ2 free of static charge?

Answer

Yes

6-207 §6.5 source ↗

For the following exercises, determine whether the statement is true or false.

∇·(x i +y j +z k )= 1.

Answer

False

6-209 §6.5 source ↗

For the following exercises, determine whether the statement is true or false.

If curlF=0, then F is conservative.

Answer

True

6-211 §6.5 source ↗

For the following exercises, determine whether the statement is true or false.

If F is a constant vector field then curlF=0.

Answer

True

6-213 §6.5 source ↗

For the following exercises, find the curl of F.

F (x,y,z)= x 2 z i + y 2 x j + (y+2z) k

Answer

curl F = i + x 2 j + y 2 k

6-215 §6.5 source ↗

For the following exercises, find the curl of F.

F (x,y,z)= x 2 yz i + x y 2 z j + xy z 2 k

Answer

curl F = (x z 2 −x y 2 ) i + ( x 2 y−y z 2 ) j + ( y 2 z− x 2 z) k

6-217 §6.5 source ↗

For the following exercises, find the curl of F.

F (x,y,z)= (x−y) i + (y−z) j + (z−x) k

Answer

curl F = i + j + k

6-219 §6.5 source ↗

For the following exercises, find the curl of F.

F (x,y,z)= xy i + yz j + xz k

Answer

curl F = −y i − z j − x k

6-221 §6.5 source ↗

For the following exercises, find the curl of F.

F(x,y,z)= axi+ byj+ ck for constants a, b, c

Answer

curl F = 0

6-223 §6.5 source ↗

For the following exercises, find the divergence of F.

F (x,y,z)= 3xy z 2 i + y 2 sinz j + x e 2 z k

Answer

div F = 3y z 2 + 2ysinz+ 2x e 2 z

6-225 §6.5 source ↗

For the following exercises, find the divergence of F.

F (x,y,z)= x 2 i + y 2 j + z 2 k

Answer

div F = 2(x+y+z)

6-227 §6.5 source ↗

For the following exercises, find the divergence of F.

F (x,y)= x x 2 + y 2 i + y x 2 + y 2 j

Answer

div F = 1 x 2 + y 2

6-229 §6.5 source ↗

For the following exercises, find the divergence of F.

F(x,y,z)= axi+ byj+ ck for constants a, b, c

Answer

div F = a + b

6-231 §6.5 source ↗

For the following exercises, find the divergence of F.

F (x,y,z)= xy i + yz j + xz k

Answer

div F = x + y + z

6-233 §6.5 source ↗

For the following exercises, determine whether each of the given scalar functions is harmonic.

w(x,y,z)= ( x 2 + y 2 + z 2 ) − 1 / 2

Answer

Harmonic

6-235 §6.5 source ↗

For the following exercises, determine whether each of the given scalar functions is harmonic.

If F(x,y,z)= 2i+ 2xj+ 3yk and G(x,y,z)= xi− yj+ zk, find div(F×G).

Answer

div( F × G )= 2z+ 3x

6-237 §6.5 source ↗

For the following exercises, determine whether each of the given scalar functions is harmonic.

Find the divergence of F for vector field F(x,y,z)= (y2+z2)(x+y)i+ (z2+x2)(y+z)j+ (x2+y2)(z+x)k.

Answer

div F = 2( x 2  +  y 2  +  z 2 )

6-239 §6.5 source ↗

For the following exercises, use r=||r|| and r=x,y,z.

Find curlr.

Answer

curl r = 0

6-241 §6.5 source ↗

For the following exercises, use r=||r|| and r=x,y,z.

Find curlrr3.

Answer

curl r r 3 = 0

6-243 §6.5 source ↗

For the following exercises, use a computer algebra system to find the curl of the given vector fields.

[T] F(x,y,z)= arctan(xy)i+ lnx2+y2j+ k

Answer

curl F = 2 x x 2 + y 2 k

6-245 §6.5 source ↗

For the following exercises, find the divergence of F at the given point.

F(x,y,z)= i+ j+ k at (2,−1,3)

Answer

div F = 0

6-247 §6.5 source ↗

For the following exercises, find the divergence of F at the given point.

F(x,y,z)= e−xyi+ exzj+ eyzk at (3,2,0)

Answer

div F = 2 − 2 e −6

6-249 §6.5 source ↗

For the following exercises, find the divergence of F at the given point.

F(x,y,z)= exsinyi− excosyj at (0, 0, 3)

Answer

div F = 0

6-251 §6.5 source ↗

For the following exercises, find the curl of F at the given point.

F(x,y,z)= xyzi+ yj+ xk at (1,2,3)

Answer

curl F = j − 3 k

6-253 §6.5 source ↗

For the following exercises, find the curl of F at the given point.

F(x,y,z)= xyzi+ yj+ zk at (1, 2, 1)

Answer

curl F = 2 j − k

6-255 §6.5 source ↗

For the following exercises, find the curl of F at the given point.

Let F(x,y,z)= (3x2y+az)i+ x3j+ (3x+3z2)k. For what value of a is F conservative?

Answer

a = 3

6-257 §6.5 source ↗

For the following exercises, find the curl of F at the given point.

Given vector field F(x,y)= 1x2+y2x,y on domain D= ℝ2-{(0,0)}= {(x,y)∈ℝ2|(x,y)≠(0,0)}, is F conservative?

Answer

F is conservative.

6-259 §6.5 source ↗

For the following exercises, find the curl of F at the given point.

Compute the divergence of F= (sinhx)i+ (coshy)j− xyzk.

Answer

div F = coshx+ sinhy− xy

6-261 §6.5 source ↗

For the following exercises, consider a rigid body that is rotating about the x-axis counterclockwise with constant angular velocity ω=〈a,b,c〉. If P is a point in the body located at r=xi+yj+zk, the velocity at P is given by vector field F=ω×r.

A three dimensional diagram of an object rotating about the x axis in a counterclockwise manner with constant angular velocity w = less than a,b,c greater than . The object is roughly a sphere with pointed ends on the x axis, which cuts it in half. An arrow r is drawn from (0,0,0) to P(x,y,z) and down from P(x,y,z) to the x axis.

Express F in terms of i, j, and k vectors.

Answer

(bz−cy) i + (cx−az) j + (ay−bx) k

6-263 §6.5 source ↗

For the following exercises, consider a rigid body that is rotating about the x-axis counterclockwise with constant angular velocity ω=〈a,b,c〉. If P is a point in the body located at r=xi+yj+zk, the velocity at P is given by vector field F=ω×r.

A three dimensional diagram of an object rotating about the x axis in a counterclockwise manner with constant angular velocity w = less than a,b,c greater than . The object is roughly a sphere with pointed ends on the x axis, which cuts it in half. An arrow r is drawn from (0,0,0) to P(x,y,z) and down from P(x,y,z) to the x axis.

Find the curl ofF

Answer

curl F = 2 ω

6-265 §6.5 source ↗

In the following exercises, suppose that ∇·F=0 and ∇·G=0.

Does F×G necessarily have zero divergence?

Answer

F×G does not have zero divergence.

6-267 §6.5 source ↗

In the following exercises, suppose a solid object in ℝ3 has a temperature distribution given by Tx,y,z= 100e-x2+y2+z2. The heat flow vector field in the object is F=−k∇T, where k>0 is a property of the material. The heat flow vector points in the direction opposite to that of the gradient, which is the direction of greatest temperature decrease. The divergence of the heat flow vector is ∇·F= −k∇·∇T= −k∇2T.

Compute the divergence.

Answer

∇· F = −200k[1+2( x 2 + y 2 + z 2 )] e − x 2 + y 2 + z 2

Checkpoint 6.47 §6.6 source ↗

Describe the surface with parameterization r(u,v)= 〈2cosu, 2sinu, v〉, 0≤u< 2π, −∞< v< ∞.

Answer

Cylinder x2+y2=4

Checkpoint 6.48 §6.6 source ↗

Describe the surface parameterized by r(u,v)= 〈ucosv, usinv, u〉, −∞< u< ∞, 0≤v< 2π.

Answer

Cone x2+y2=z2

Checkpoint 6.49 §6.6 source ↗

Give a parameterization for the portion of cone x2+y2=z2 lying in the first octant.

Answer

r(u,v)= 〈ucosv, usinv, u〉, 0< u< ∞, 0≤v< π2

Checkpoint 6.50 §6.6 source ↗

Is the surface parameterization r(u,v)= 〈u2v, v+ 1, sinu〉, 0≤u≤2, 0≤v≤3 smooth?

Answer

Yes

Checkpoint 6.51 §6.6 source ↗

Find the surface area of the surface with parameterization r(u,v)= 〈u+ v, u2, 2v〉, 0≤u≤3, 0≤v≤2.

Answer

≈ 43.02

Checkpoint 6.52 §6.6 source ↗

Show that the surface area of cylinder x2+ y2= r2, 0≤z≤h is 2πrh. Notice that this cylinder does not include the top and bottom circles.

Answer

With the standard parameterization of a cylinder, Equation 6.18 shows that the surface area is 2πrh.

Checkpoint 6.53 §6.6 source ↗

Use Equation 6.18 to find the area of the surface of revolution obtained by rotating curve y= sinx, 0≤x≤π about the x-axis.

Answer

2 π ( 2 + sinh −1 ( 1 ) )

Checkpoint 6.54 §6.6 source ↗

Calculate ∬S(x2−z)dS, where S is the surface with parameterization r(u,v)= 〈v, u2+ v2, 1〉, 0≤u≤2, 0≤v≤3.

Answer

24

Checkpoint 6.55 §6.6 source ↗

Calculate surface integral ∬S(x−y)dS, where S is cylinder x2+ y2= 1, 0≤z≤2, including the circular top and bottom.

Answer

0

Checkpoint 6.56 §6.6 source ↗

A piece of metal has a shape that is modeled by paraboloid z= x2+ y2, 0≤z≤4, and the density of the metal is given by ρ(x,y,z)= z+ 1. Find the mass of the piece of metal.

Answer

38.401π≈ 120.640

Checkpoint 6.57 §6.6 source ↗

Give the “upward” orientation of the graph of f(x,y)=xy.

Answer

N (x,y)= 〈 − y 1 + x 2 + y 2 , − x 1 + x 2 + y 2 , 1 1 + x 2 + y 2 〉

Checkpoint 6.58 §6.6 source ↗

Calculate surface integral ∬SF·dS, where F=〈0,−z,y〉 and S is the portion of the unit sphere in the first octant with outward orientation.

Answer

0

Checkpoint 6.59 §6.6 source ↗

Let v(x,y,z)= 〈x2+ y2, z, 4y〉 m/sec represent a velocity field of a fluid with constant density 100 kg/m3. Let S be the half-cylinder r(u,v)= 〈cosu, sinu, v〉, 0≤u≤π, 0≤v≤2 oriented outward. Calculate the mass flux of the fluid across S.

Answer

400 kg/sec/m

Checkpoint 6.60 §6.6 source ↗

A cast-iron solid ball is given by inequality x2+y2+z2≤1. The temperature at a point in a region containing the ball is T(x,y,z)= 13(x2+y2+z2). Find the heat flow across the boundary of the solid if this boundary is oriented outward.

Answer

− 440 π 3

6-269 §6.6 source ↗

For the following exercises, determine whether the statements are true or false.

If surface S is given by {(x,y,z):0≤x≤1,0≤y≤1,z=10}, then ∬Sf(x,y,z)dS= ∫01∫01f(x,y,10)dxdy.

Answer

True

6-271 §6.6 source ↗

For the following exercises, determine whether the statements are true or false.

Surface r= 〈vcosu, vsinu, v2〉, for0≤u≤π, 0≤v≤2, is the same as surface r= 〈vcos2u, vsin2u, v〉, for 0≤u≤π2, 0≤v≤4.

Answer

True

6-273 §6.6 source ↗

For the following exercises, find parametric descriptions for the following surfaces.

Plane 3x−2y+z=2

Answer

r(u,v)= 〈u, v, 2− 3u+ 2v〉 for −∞≤u<∞ and −∞≤v<∞.

6-275 §6.6 source ↗

For the following exercises, find parametric descriptions for the following surfaces.

Plane 2x−4y+3z=16

Answer

r(u,v)= 〈u, v, 13(16−2u+4v)〉 for |u|<∞ and |v|<∞.

6-277 §6.6 source ↗

For the following exercises, find parametric descriptions for the following surfaces.

The portion of cylinder x2+y2=9 in the first octant, for 0≤z≤3

A diagram in three dimensions of a section of a cylinder with radius 3. The center of its circular top is (0,0,3). The section exists for x, y, and z between 0 and 3.

Answer

r(u,v)= 〈3cosu, 3sinu, v〉 for 0≤u≤π2, 0≤v≤3

6-279 §6.6 source ↗

For the following exercises, use a computer algebra system to approximate the area of the following surfaces using a parametric description of the surface.

[T] Half cylinder {(r,θ,z):r=4,0≤θ≤π,0≤z≤7}

Answer

A= 28π= 87.9646

6-281 §6.6 source ↗

For the following exercises, let S be the hemisphere x2+y2+z2=4, with z≥0, and evaluate each surface integral.

∬ S z d S

Answer

∬ S z d S = 8 π

6-283 §6.6 source ↗

For the following exercises, let S be the hemisphere x2+y2+z2=4, with z≥0, and evaluate each surface integral.

∬ S ( x 2 + y 2 ) z d S

Answer

∬ S ( x 2 + y 2 ) z d S = 16π

6-285 §6.6 source ↗

For the following exercises, evaluate ∫∫SF·NdS for vector field F, where N is an upward pointing normal vector to surface S.

F(x,y,z)= xi+ yj, and S is hemisphere z=1−x2−y2.

Answer

∬ S F · N d S = 4 π 3

6-287 §6.6 source ↗

For the following exercises, approximate the mass of the lamina that has the shape of given surface S. Round to four decimal places.

[T] S is surface z= 4− x− 2y, withz≥0,x≥0,y≥0;ρ= x.

Answer

m ≈ 13.0639

6-289 §6.6 source ↗

For the following exercises, approximate the mass of the lamina that has the shape of given surface S. Round to four decimal places.

[T] S is surface x2+ y2+ z2= 5, withz≥1;ρ= θ2.

Answer

m ≈ 228.5313

6-291 §6.6 source ↗

For the following exercises, approximate the mass of the lamina that has the shape of given surface S. Round to four decimal places.

Evaluate surface integral ∬SgdS, where g(x,y,z)= xz+ 2x2− 3xy and S is the portion of plane 2x−3y+z=6 that lies over unit square R: 0≤x≤1,0≤y≤1.

Answer

∬ S g d S = 3 14

6-293 §6.6 source ↗

For the following exercises, approximate the mass of the lamina that has the shape of given surface S. Round to four decimal places.

[T] Evaluate ∬S(x−y2+z)dS, where S is the surface defined by r(u,v)= u2i+ vj+ uk,0≤u≤1,0≤v≤1.

A three-dimensional diagram of the given surface, which appears to be a curve with edges parallel to the y-axis. It increases in x components and decreases in z components the further it is from the y axis.A three-dimensional diagram of the given surface, which appears to be a curve with edges parallel to the y-axis. It increases in x components and decreases in z components the further it is from the y axis.

Answer

∬ S ( x - y 2 + z ) dS≈ 0.9617

6-295 §6.6 source ↗

For the following exercises, approximate the mass of the lamina that has the shape of given surface S. Round to four decimal places.

Evaluate ∬S(x2+y2)dS, where S is the surface of hemisphere z=1−x2−y2, and above the plane z=0.

Answer

∬ S ( x 2 + y 2 ) d S = 4 π 3

6-297 §6.6 source ↗

For the following exercises, approximate the mass of the lamina that has the shape of given surface S. Round to four decimal places.

[T] Evaluate ∬Sx2zdS, where S is the portion of cone z2=x2+y2 that lies between planes z=1 and z=4.

A diagram of the given upward opening cone in three dimensions. The cone is cut by planes z=1 and z=4.

Answer

∬ S x 2 z d S = 1023 π 2 5

6-299 §6.6 source ↗

For the following exercises, approximate the mass of the lamina that has the shape of given surface S. Round to four decimal places.

[T] Evaluate ∬S(z+y)dS, where S is the part of the graph of z=1−x2 in the first octant between the xz-plane and plane y=3.

A diagram of the given surface in three dimensions in the first octant between the xz-plane and plane y=3. The given graph of z= the square root of (1-x^2) stretches down in a concave down curve from along (0,y,1) to along (1,y,0). It looks like a portion of a horizontal cylinder with base along the xz-plane and height along the y axis.A diagram of the given surface in three dimensions in the first octant between the xz-plane and plane y=3. The given graph of z= the square root of (1-x^2) stretches down in a concave down curve from along (0,y,1) to along (1,y,0). It looks like a portion of a horizontal cylinder with base along the xz-plane and height along the y axis.

Answer

∬ S ( z + y ) d S ≈ 10.1

6-301 §6.6 source ↗

For the following exercises, approximate the mass of the lamina that has the shape of given surface S. Round to four decimal places.

Find the mass of a lamina of density ρ(x,y,z)=z in the shape of hemisphere z= (a2−x2−y2)1/2.

Answer

m = π a 3

6-303 §6.6 source ↗

For the following exercises, approximate the mass of the lamina that has the shape of given surface S. Round to four decimal places.

Compute ∬SF·NdS, where F(x,y,z)= xyi+ zj+ (x+y)k and N is an upward pointing normal vector S, where S is the triangular region of the plane x+y+z=1 in the first octant.

Answer

∬ S F · N d S = 13 24

6-305 §6.6 source ↗

For the following exercises, approximate the mass of the lamina that has the shape of given surface S. Round to four decimal places.

Compute ∬SF·NdS, where F(x,y,z)= xyzi+ xyzj+ xyzk and N is an outward normal vector S, where S is the surface of the five faces of the unit cube 0≤x≤1,0≤y≤1,0≤z≤1 missing z=0.

Answer

∬ S F · N d S = 3 4

6-307 §6.6 source ↗

For the following exercises, express the surface integral as an iterated double integral by using a projection on S on the yz-plane.

∬S(x2−2y+z)dS; S is the portion of the graph of 4x+y=8 bounded by the coordinate planes and plane z=6.

Answer

∫ 0 8 ∫ 0 6 ( 4 − 3 y + 1 16 y 2 + z ) ( 1 4 17 ) d z d y

6-309 §6.6 source ↗

For the following exercises, express the surface integral as an iterated double integral by using a projection on S on the xz-plane

∬S(x2−2y+z)dS; S is the portion of the graph of 4x+y=8 bounded by the coordinate planes and plane z=6.

Answer

∫ 0 2 ∫ 0 6 [ x 2 − 2 ( 8 − 4 x ) + z ] 17 d z d x

6-311 §6.6 source ↗

For the following exercises, express the surface integral as an iterated double integral by using a projection on S on the xz-plane

Evaluate surface integral ∬S(x2z+y2z)dS, where S is hemisphere x2+ y2+ z2= a2, z≥0.

Answer

∬ S ( x 2 z + y 2 z ) d S = π a 5 2

6-313 §6.6 source ↗

For the following exercises, express the surface integral as an iterated double integral by using a projection on S on the xz-plane

Evaluate surface integral ∬Sx2yzdS, where S is the part of plane z=1+2x+3y that lies above rectangle 0≤x≤3and0≤y≤2.

Answer

∬ S x 2 y z d S = 171 14

6-315 §6.6 source ↗

For the following exercises, express the surface integral as an iterated double integral by using a projection on S on the xz-plane

Evaluate surface integral ∬SyzdS, where S is the part of plane z=y+3 that lies inside cylinder x2+y2=1.

Answer

∬ S y z d S = 2 π 4

6-317 §6.6 source ↗

For the following exercises, use geometric reasoning to evaluate the given surface integrals.

∬S(xi+yj)·dS, where S is surface x2+ y2= 4, 1≤z≤3, oriented with unit normal vectors pointing outward

Answer

∬ S ( x i + y j ) · d S = 16π

6-319 §6.6 source ↗

For the following exercises, use geometric reasoning to evaluate the given surface integrals.

A lamina has the shape of a portion of sphere x2+y2+z2=a2 that lies within cone z=x2+y2. Let S be the spherical shell centered at the origin with radius a, and let C be the right circular cone with a vertex at the origin and an axis of symmetry that coincides with the z-axis. Determine the mass of the lamina if ρ(x,y,z)= x2y2z.

A diagram in three dimensions. A cone opens upward with point at the origin and an asic of symmetry that coincides with the z-axis. The upper half of a hemisphere with center at the origin opens downward and is cut off by the xy-plane.

Answer

m = π a 7 192

6-321 §6.6 source ↗

For the following exercises, use geometric reasoning to evaluate the given surface integrals.

A paper cup has the shape of an inverted right circular cone of height 6 in. and radius of top 3 in. If the cup is full of water weighing 62.5lb/ft3, find the total force exerted by the water on the inside surface of the cup.

Answer

F ≈ 4.57 lb .

6-323 §6.6 source ↗

For the following exercises, the heat flow vector field for conducting objects is F= −k∇T, whereT(x,y,z) is the temperature in the object and k>0 is a constant that depends on the material. Find the outward flux of F across the following surfaces S for the given temperature distributions and assume k=1.

T(x,y,z)= −ln(x2+y2+z2); S is sphere x2+ y2+ z2= a2.

Answer

8 π a

6-325 §6.6 source ↗

For the following exercises, consider the radial fields F= ⟨x,y,z⟩(x2+y2+z2)p2= rrp, where p is a real number. Let S consist of spheres A and B centered at the origin with radii 0< a< b. The total outward flux across S consists of the outward flux across the outer sphere B less the flux into S across inner sphere A.

A diagram in three dimensions of two spheres, one contained completely inside the other. Their centers are both at the origin. Arrows point in toward the origin from outside both spheres.

Show that for p=3 the flux across S is independent of a and b.

Answer

The net flux is zero.

Checkpoint 6.61 §6.7 source ↗

Verify that Stokes’ theorem is true for vector field F(x,y,z)= 〈y, x, −z〉 and surface S, where S is the upwardly oriented portion of the graph of f(x,y)=x2y over a triangle in the xy-plane with vertices (0,0), (2,0), and (0,2).

Answer

Both integrals give 0

Checkpoint 6.62 §6.7 source ↗

Use Stokes’ theorem to calculate surface integral ∬ScurlF·dS, where F=〈z,x,y〉 and S is the surface as shown in the following figure. The boundary curve, C, is oriented clockwise when looking along the positive y-axis.

A three-dimensional diagram of a surface. One end is an open circle with radius 1 and centered at the origin. It is on the (x, z) plane. The rest of the surface stretches back symmetrically over the y axis. The surface narrows slightly, opens up into a sphere, narrows again, and then ends in another sphere. It looks like a vase lying on its side with an open circular end, a large, spherical body, and a medium sized spherical base.A three-dimensional diagram of a surface. One end is an open circle with radius 1 and centered at the origin. It is on the (x, z) plane. The rest of the surface stretches back symmetrically over the y axis. The surface narrows slightly, opens up into a sphere, narrows again, and then ends in another sphere. It looks like a vase lying on its side with an open circular end, a large, spherical body, and a medium sized spherical base.

Answer

− π

Checkpoint 6.63 §6.7 source ↗

Use Stokes’ theorem to calculate line integral ∫CF·dr, where F=〈z,x,y〉 and C is oriented clockwise and is the boundary of a triangle with vertices (0,0,1), (3,0,−2), and (0,1,2).

Answer

3 2

Checkpoint 6.64 §6.7 source ↗

Calculate the curl of electric field E if the corresponding magnetic field is B(t)= 〈tx, ty, −2tz〉, 0≤t< ∞.

Answer

curl E = 〈x, y, −2z〉

6-327 §6.7 source ↗

For the following exercises, without using Stokes’ theorem, calculate directly both the flux of curlF·N over the given surface and the circulation integral around its boundary, assuming all boundaries have positive orientation.

F(x,y,z)= zi+ xj+ yk; S is hemisphere z= (a2−x2−y2)1/2.

Answer

∬ S ( curl F · N ) d S = π a 2

6-329 §6.7 source ↗

For the following exercises, without using Stokes’ theorem, calculate directly both the flux of curlF·N over the given surface and the circulation integral around its boundary, assuming all boundaries have positive orientation.

F(x,y,z)= zi+ 2xj+ 3yk; S is upper hemisphere z=9−x2−y2.

Answer

∬ S ( curl F · N ) d S = 18π

6-331 §6.7 source ↗

For the following exercises, without using Stokes’ theorem, calculate directly both the flux of curlF·N over the given surface and the circulation integral around its boundary, assuming all boundaries have positive orientation.

F(x,y,z)= 2yi− 6zj+ 3xk; S is a portion of paraboloid z=4−x2−y2 and is above the xy-plane.

Answer

∬ S ( curl F · N ) d S = −8π

6-333 §6.7 source ↗

For the following exercises, use Stokes’ theorem to evaluate ∬S(curlF·N)dS for the vector fields and surface.

F(x,y,z)= xyi+ x2j+ z2k; and S is the part of paraboloid z=x2+y2 below plane z=y, and using the outward normal vector.

Answer

∬ S ( curl F · N ) d S = 0

6-335 §6.7 source ↗

For the following exercises, use Stokes’ theorem to evaluate ∬S(curlF·N)dS for the vector fields and surface.

Use Stokes’ theorem to evaluate ∫C[2xy2zdx+2x2yzdy+(x2y2−2z)dz], where C is the curve given by x= cost, y= sint, z= sint, 0≤t≤2π, traversed in the direction of increasing t.

A vector field in three dimensional space. The arrows are larger the further they are from the x, y plane. The arrows curve up from below the x, y plane and slightly above it. The rest tend to curve down and horizontally. An oval-shaped curve is drawn through the middle of the space.

Answer

∫ C F · d r = 0

6-337 §6.7 source ↗

For the following exercises, use Stokes’ theorem to evaluate ∬S(curlF·N)dS for the vector fields and surface.

[T] Use a CAS and Stokes’ theorem to approximate line integral ∫C(3ydx+2zdy−5xdz), where C is the intersection of the xy-plane and hemisphere z=1−x2−y2, traversed counterclockwise viewed from the top—that is, from the positive z-axis toward the xy-plane.

Answer

∫ s F · d r = - 3 π ≈ - 9 . 4248

6-339 §6.7 source ↗

For the following exercises, use Stokes’ theorem to evaluate ∬S(curlF·N)dS for the vector fields and surface.

Use Stokes’ theorem to evaluate ∬ScurlF·dS, where F(x,y,z)= exycoszi+ x2zj+ xyk, and S is half of sphere x=1−y2−z2, oriented out toward the positive x-axis.

Answer

∬ S curl F · d S = 0

6-341 §6.7 source ↗

For the following exercises, use Stokes’ theorem to evaluate ∬S(curlF·N)dS for the vector fields and surface.

[T] Use a CAS and Stokes’ theorem to evaluate ∬ScurlF·dS, where F(x,y,z)= (sin(y+z)−yx2−y33)i+ xcos(y+z)j+ cos(2y)k and S consists of the top and the four sides but not the bottom of the cube with vertices (±1,±1,±1), oriented outward.

Answer

∬ S curl F · d S = 2.6667

6-343 §6.7 source ↗

For the following exercises, use Stokes’ theorem to evaluate ∬S(curlF·N)dS for the vector fields and surface.

Use Stokes’ theorem to evaluate ∬S(curlF·N)dS, where F(x,y,z)= z2i+ y2j+ xk and S is a triangle with vertices (1, 0, 0), (0, 1, 0) and (0, 0, 1) with upward orientation.

Answer

∬ S ( curl F · N ) d S = − 1 6

6-345 §6.7 source ↗

For the following exercises, use Stokes’ theorem to evaluate ∬S(curlF·N)dS for the vector fields and surface.

Use Stokes’ theorem to evaluate ∫C(12y2dx+zdy+xdz), where C is the curve of intersection of plane x+z=1 and ellipsoid x2+ 2y2+ z2= 1, oriented clockwise from the origin.

A diagram of an intersecting plane and ellipsoid in three dimensional space. There is an orange curve drawn to show the intersection.

Answer

∫ C ( 1 2 y 2 d x + z d y + x d z ) = − π 4

6-347 §6.7 source ↗

For the following exercises, use Stokes’ theorem to evaluate ∬S(curlF·N)dS for the vector fields and surface.

Use Stokes’ theorem to evaluate ∬S(curlF·N)dS, for vector field F(x,y,z)= zi+ 3xj+ 2zk where S is surface z= 1− x2− y2, z≥0, C is boundary circle x2+y2=1, and S is oriented in the positive z-direction.

Answer

∬ S ( curl F · N ) d S = 3π

6-349 §6.7 source ↗

For the following exercises, use Stokes’ theorem to evaluate ∬S(curlF·N)dS for the vector fields and surface.

A certain closed path C in plane 2x+2y+z=1 is known to project onto unit circle x2+y2=1 in the xy-plane. Let c be a constant and let R(x,y,z)= xi+ yj+ zk. Use Stokes’ theorem to evaluate ∫C(ck×R)·dr.

Answer

∫ C ( c k × R ) · d r = 2πc

6-351 §6.7 source ↗

For the following exercises, use Stokes’ theorem to evaluate ∬S(curlF·N)dS for the vector fields and surface.

Let S be hemisphere x2+y2+z2=4 with z≥0, oriented upward. Let F(x,y,z)= x2eyzi+ y2exzj+ z2exyk be a vector field. Use Stokes’ theorem to evaluate ∬ScurlF·dS.

Answer

∬ S curl F · d S = 0

6-353 §6.7 source ↗

For the following exercises, use Stokes’ theorem to evaluate ∬S(curlF·N)dS for the vector fields and surface.

Use Stokes’ theorem to evaluate ∫CF·dr where F(x,y,z)= yi+ zj+ xk and C is a triangle with vertices (0, 0, 0), (2, 0, 0) and (0,−2,2) oriented counterclockwise when viewed from above.

Answer

∫ C F · d r = −4

6-355 §6.7 source ↗

For the following exercises, use Stokes’ theorem to evaluate ∬S(curlF·N)dS for the vector fields and surface.

Use Stokes’ theorem to compute ∬ScurlF·dS, where F(x,y,z)= i+ xy2j+ xy2k and S is a part of plane y+z=2 inside cylinder x2+y2=1 and oriented upward.

A diagram of a vector field in three dimensional space showing the intersection of a plane and a cylinder. The curve where the plane and cylinder intersect is drawn in blue.A diagram of a vector field in three dimensional space showing the intersection of a plane and a cylinder. The curve where the plane and cylinder intersect is drawn in blue.

Answer

∬ S curl F · d S = 0

6-357 §6.7 source ↗

For the following exercises, use Stokes’ theorem to evaluate ∬S(curlF·N)dS for the vector fields and surface.

Let F(x,y,z)= xyi+ 2zj− 2yk and let C be the intersection of plane x+z=5 and cylinder x2+y2=9, which is oriented counterclockwise when viewed from the top. Compute the line integral of F over C using Stokes’ theorem.

Answer

∬ S curl F · d S = −36π

6-359 §6.7 source ↗

For the following exercises, use Stokes’ theorem to evaluate ∬S(curlF·N)dS for the vector fields and surface.

Let S be ellipsoid x24+ y29+ z2= 1 oriented outward and let F be a vector field with component functions that have continuous partial derivatives. Compute ∬scurl F·dS

Answer

∬ S curlF·dS= 0

6-361 §6.7 source ↗

For the following exercises, use Stokes’ theorem to evaluate ∬S(curlF·N)dS for the vector fields and surface.

[T] Use a CAS and Stokes’ theorem to evaluate ∫CF·dr if F(x,y,z)= (3z−sinx)i+ (x2+ey)j+ (y3−cosz)k, where C is the curve given by x= cost, y= sint, z= 1; 0≤t≤2π.

Answer

∫ C F · d r = 0

6-363 §6.7 source ↗

For the following exercises, use Stokes’ theorem to evaluate ∬S(curlF·N)dS for the vector fields and surface.

[T] Use a CAS to evaluate ∬ScurlF·dS, where F(x,y,z)= 2zi+ 3xj+ 5yk and S is the surface parametrically by r(r,θ)= rcosθi+ rsinθj+ (4−r2)k (0≤θ≤2π,0≤r≤3).

Answer

∬ S curl ( F ) · d S = 84.8230

6-365 §6.7 source ↗

For the following application exercises, the goal is to evaluate A= ∬Scurl F·dS where F= 〈xz, −xz, xy〉 and S is the upper half of ellipsoid x2+ y2+ 8z2= 1, wherez≥0.

Evaluate a surface integral over a more convenient surface to find the value of A.

Answer

A= ∬ S curl F·dS= 0

6-367 §6.7 source ↗

For the following application exercises, the goal is to evaluate A= ∬Scurl F·dS where F= 〈xz, −xz, xy〉 and S is the upper half of ellipsoid x2+ y2+ 8z2= 1, wherez≥0.

Take paraboloid z=x2+y2, for 0≤z≤4, and slice it with plane y=0. Let S be the surface that remains for y≥0, including the planar surface in the xz-plane. Let C be the semicircle and line segment that bounded the cap of S in plane z=4 with counterclockwise orientation. Let F= 〈2z+ y, 2x+ z, 2y+ x〉. Evaluate ∬Scurl F·dS

A diagram of a vector field in three dimensional space where a paraboloid with vertex at the origin, plane at y=0, and plane at z=4 intersect. The remaining surface is the half of a paraboloid under z=4 and above y=0.

Answer

∬ S curl F·dS= 2π

6-369 §6.7 source ↗

For the following exercises, let S be the disk enclosed by curve

C:r(t)= 〈cosφcost, sint, sinφcost〉, for 0≤t≤2π, where 0≤φ≤π2 is a fixed angle.

What is the circulation of C of vector field F=〈−y,−z,x〉 as a function of φ?

Answer

C= π(cosφ−sinφ)

6-371 §6.7 source ↗

For the following exercises, let S be the disk enclosed by curve

C:r(t)= 〈cosφcost, sint, sinφcost〉, for 0≤t≤2π, where 0≤φ≤π2 is a fixed angle.

Circle C in plane x+y+z=8 has radius 4 and center (2, 3, 3). Evaluate ∫CF·dr for F= 〈0, −z, 2y〉, where C has a counterclockwise orientation when viewed from above.

Answer

∫ C F · d r = 48 π

6-373 §6.7 source ↗

For the following exercises, let S be the disk enclosed by curve

C:r(t)= 〈cosφcost, sint, sinφcost〉, for 0≤t≤2π, where 0≤φ≤π2 is a fixed angle.

Evaluate integral ∬Scurl F·dS where F= −xzi+ yzj+ xyezk and S is the cap of paraboloid z=5−x2−y2 above plane z=3, and n points in the positive z-direction on S.

Answer

∬ S curl F·dS= 0

6-375 §6.7 source ↗

For the following exercises, use Stokes’ theorem to find the circulation of the following vector fields around any smooth, simple closed curve C.

F = 〈 y 2 z 3 , 2xy z 3 , 3x y 2 z 2 〉

Answer

0

Checkpoint 6.65 §6.8 source ↗

Verify the divergence theorem for vector field F(x,y,z)= 〈x+ y+ z, y, 2x− y〉 and surface S given by the cylinder x2+ y2= 1, 0≤z≤3 plus the circular top and bottom of the cylinder. Assume that S is oriented outward.

Answer

Both integrals equal 6π.

Checkpoint 6.66 §6.8 source ↗

Use the divergence theorem to calculate flux integral ∬SF·dS, where S is the boundary of the box given by 0≤x≤2, 1≤y≤4, 0≤z≤1, and F= 〈x2+ yz, y-z, 2x+ 2y+ 2z〉 (see the following figure).

This figure is a vector diagram in three dimensions. The box of the figure spans x from 0 to 2; y from 0 to 4; and z from 0 to 1. The vectors point up increasingly with distance from the origin; toward larger x with increasing distance from the origin; and toward smaller y values with increasing height.This figure is a vector diagram in three dimensions. The box of the figure spans x from 0 to 2; y from 0 to 4; and z from 0 to 1. The vectors point up increasingly with distance from the origin; toward larger x with increasing distance from the origin; and toward smaller y values with increasing height.

Answer

30

Checkpoint 6.67 §6.8 source ↗

Let v=〈xz,yz,0〉 be the velocity field of a fluid. Let C be the solid cube given by 1≤x≤4, 2≤y≤5, 1≤z≤4, and let S be the boundary of this cube (see the following figure). Find the flow rate of the fluid across S.

This is a figure of a diagram of the given vector field in three dimensions. The x components are x/z, the y components are y/z, and the z components are 0.This is a figure of a diagram of the given vector field in three dimensions. The x components are x/z, the y components are y/z, and the z components are 0.

Answer

9 ln ( 16 )

Checkpoint 6.68 §6.8 source ↗

Work the previous example for surface S that is a sphere of radius 4 centered at the origin, oriented outward.

Answer

≈ 6.777 × 10 9

6-377 §6.8 source ↗

For the following exercises, use a computer algebraic system (CAS) and the divergence theorem to evaluate surface integral ∬SF·Nds for the given choice of F and the boundary surface S. For each closed surface, assume N is the outward unit normal vector.

[T] F(x,y,z)= (cosyz)i+ exzj+ 3z2k; S is the surface of hemisphere z=4−x2−y2 together with disk x2+y2≤4 in the xy-plane.

Answer

∫ S F · N d s = 24π ≈ 75.3982

6-379 §6.8 source ↗

For the following exercises, use a computer algebraic system (CAS) and the divergence theorem to evaluate surface integral ∬SF·Nds for the given choice of F and the boundary surface S. For each closed surface, assume N is the outward unit normal vector.

[T] F(x,y,z)= xi+ yj+ zk; S is the surface of the solid bounded by the parabola z=x2+y2 and the plane z=9.

Answer

∫ S F · N d s = 243 π 2 ≈ 381.704

6-381 §6.8 source ↗

For the following exercises, use a computer algebraic system (CAS) and the divergence theorem to evaluate surface integral ∬SF·Nds for the given choice of F and the boundary surface S. For each closed surface, assume N is the outward unit normal vector.

[T] F(x,y,z)= xi+ yj+ (z2−1)k; S is the surface of the solid bounded by cylinder x2+y2=4 and planes z=0andz=1.

Answer

∫ S F · N d s = 12π ≈ 37.6991

6-383 §6.8 source ↗

For the following exercises, use a computer algebraic system (CAS) and the divergence theorem to evaluate surface integral ∬SF·Nds for the given choice of F and the boundary surface S. For each closed surface, assume N is the outward unit normal vector.

[T] F(x,y,z)= x3i+ y3j+ 3a2zk(constanta>0); S is the surface of the solid bounded by cylinder x2+y2=a2 and planes z=0andz=1.

Answer

∫ S F · N d s = 9 π a 4 2

6-385 §6.8 source ↗

For the following exercises, use a computer algebraic system (CAS) and the divergence theorem to evaluate surface integral ∬SF·Nds for the given choice of F and the boundary surface S. For each closed surface, assume N is the outward unit normal vector.

Use the divergence theorem to calculate surface integral ∬SF·dS, where F(x,y,z)= (ey2)i+ (y+sin(z2))j+ (z−1)k and S is the surface of the solid bounded by the sphere x2+y2+z2=1, and below by the plane z=0.

Answer

∬ S F · d S = 4 π 3

6-387 §6.8 source ↗

For the following exercises, use a computer algebraic system (CAS) and the divergence theorem to evaluate surface integral ∬SF·Nds for the given choice of F and the boundary surface S. For each closed surface, assume N is the outward unit normal vector.

Use the divergence theorem to calculate surface integral ∬SF·dS when F(x,y,z)= x2z3i+ 2xyz3j+ xz4k and S is the surface of the box with vertices (±1,±2,±3).

Answer

∬ S F · d S = 0

6-389 §6.8 source ↗

For the following exercises, use a computer algebraic system (CAS) and the divergence theorem to evaluate surface integral ∬SF·Nds for the given choice of F and the boundary surface S. For each closed surface, assume N is the outward unit normal vector.

[T] Use a CAS and the divergence theorem to calculate flux ∬SF·dS, where F(x,y,z)= (x3+y3)i+ (y3+z3)j+ (z3+x3)k and S is a sphere with center (0, 0, 0) and radius 2.

Answer

∬ S F · d S = 384 π 5 ≈ 241.2743

6-391 §6.8 source ↗

For the following exercises, use a computer algebraic system (CAS) and the divergence theorem to evaluate surface integral ∬SF·Nds for the given choice of F and the boundary surface S. For each closed surface, assume N is the outward unit normal vector.

Use the divergence theorem to compute flux integral ∬SF·dS, where F(x,y,z)= yj− zk and S consists of the union of paraboloid y= x2+ z2, 0≤y≤1, and disk x2+ z2≤1, y= 1, oriented outward. What is the flux through just the paraboloid?

Answer

∬DF·dS= Net flux =0; flux through the paraboloid =–π

6-393 §6.8 source ↗

For the following exercises, use a computer algebraic system (CAS) and the divergence theorem to evaluate surface integral ∬SF·Nds for the given choice of F and the boundary surface S. For each closed surface, assume N is the outward unit normal vector.

Use the divergence theorem to calculate surface integral ∬SF·dS for F(x,y,z)= x4i− x3z2j+ 4xy2zk, where S is the surface inside the cylinder x2+y2=1 between the planes z= x+ 2andz= 0.

Answer

∬ S F · d S = 2 π 3

6-395 §6.8 source ↗

For the following exercises, use a CAS along with the divergence theorem to compute the net outward flux for the fields across the given surfaces S.

[T] F= 〈x, −2y, 3z〉; S is sphere {(x,y,z):x2+y2+z2=6}.

Answer

16 6 π

6-397 §6.8 source ↗

For the following exercises, use a CAS along with the divergence theorem to compute the net outward flux for the fields across the given surfaces S.

[T] F= 〈y− 2x, x3− y, y2− z〉; S is sphere {(x,y,z):x2+y2+z2=4}.

Answer

− 128 π 3

6-399 §6.8 source ↗

For the following exercises, use a CAS and the divergence theorem to compute the net outward flux for the vector fields across the boundary of the given regions D.

[T] F= 〈z− x, x− y, 2y− z〉; D is the region between spheres of radius 2 and 4 centered at the origin.

Answer

–224π ≈ −703.7168

6-401 §6.8 source ↗

For the following exercises, use a CAS and the divergence theorem to compute the net outward flux for the vector fields across the boundary of the given regions D.

[T] F= 〈x2, −y2, z2〉; D is the region in the first octant between planes z=4−x−y and z=2−x−y.

Answer

20

6-403 §6.8 source ↗

For the following exercises, use a CAS and the divergence theorem to compute the net outward flux for the vector fields across the boundary of the given regions D.

Use the divergence theorem to find the outward flux of field F(x,y,z)= (x3−3y)i+ (2yz+1)j+ xyzk through the cube bounded by planes x= ±1, y= ±1, andz= ±1.

Answer

∬ S F · d S = 8

6-405 §6.8 source ↗

For the following exercises, use a CAS and the divergence theorem to compute the net outward flux for the vector fields across the boundary of the given regions D.

Evaluate ∬SF·NdS, where F(x,y,z)= x2i+ xyj+ x3y3k and S is the surface consisting of all faces of the tetrahedron bounded by plane x+y+z=1 and the coordinate planes, with outward unit normal vector N.

A vector field in three dimensions, with arrows becoming larger the further away from the origin they are, especially in their x components. S is the surface consisting of all faces of the tetrahedron bounded by the plane x + y + z = 1. As such, a portion of the given plane, the (x, y) plane, the (x, z) plane, and the (y, z) plane are shown. The arrows point towards the origin for negative x components, away from the origin for positive x components, down for positive x and negative y components, as well as positive y and negative x components, and for positive x and y components, as well as negative x and negative y components.

Answer

∬ S F · N d S = 1 8

6-407 §6.8 source ↗

For the following exercises, use a CAS and the divergence theorem to compute the net outward flux for the vector fields across the boundary of the given regions D.

Use the divergence theorem to evaluate ∬S‖R‖R·ndS, where R(x,y,z)= xi+ yj+ zk and S is sphere x2+ y2+ z2= a2, with constant a>0.

Answer

∬ S ‖R‖R·ndS= 4π a 4

6-409 §6.8 source ↗

For the following exercises, use a CAS and the divergence theorem to compute the net outward flux for the vector fields across the boundary of the given regions D.

Let R be the region defined by x2+y2+z2≤1. Use the divergence theorem to find ∭Rz2dV.

Answer

∭ R z 2 d V = 4 π 15

6-411 §6.8 source ↗

For the following exercises, use a CAS and the divergence theorem to compute the net outward flux for the vector fields across the boundary of the given regions D.

Let E be the solid unit cube with diagonally opposite corners at the origin and (1, 1, 1), and faces parallel to the coordinate planes. Let S be the surface of E, oriented with the outward-pointing normal. Use a CAS to find ∬SF·dS using the divergence theorem if F(x,y,z)= 2xyi+ 3yezj+ xsinzk.

Answer

∬ S F · d S = 3e-2+ 1 2 sin1≈ 6.5759

6-413 §6.8 source ↗

For the following exercises, use a CAS and the divergence theorem to compute the net outward flux for the vector fields across the boundary of the given regions D.

Find ∬SF·dS, where F(x,y,z)= xi+ yj+ zk and S is the outwardly oriented surface obtained by removing cube [1,2]×[1,2]×[1,2] from cube [0,2]×[0,2]×[0,2].

Answer

∬ S F · d S = 21

6-415 §6.8 source ↗

For the following exercises, use a CAS and the divergence theorem to compute the net outward flux for the vector fields across the boundary of the given regions D.

Compute the flux of water through parabolic cylinder S:y=x2, from 0≤x≤2, 0≤z≤3, if the velocity vector is F(x,y,z)= 3z2i+ 6j+ 6xzk.

Answer

∬ S F · d S = 72

6-417 §6.8 source ↗

For the following exercises, use a CAS and the divergence theorem to compute the net outward flux for the vector fields across the boundary of the given regions D.

[T] Use a CAS to find the flux of vector field F(x,y,z)= (ey+x)i+ (3cos(xz)−y)j+ zk through surface S, where S is given by z2=4x2+4y2 from 0≤z≤4, oriented so the unit normal vector points downward.

Answer

∬ S F · d S = - 32 π 3 ≈ −33.5103

6-419 §6.8 source ↗

For the following exercises, use a CAS and the divergence theorem to compute the net outward flux for the vector fields across the boundary of the given regions D.

Evaluate ∬SF·dS, where F(x,y,z)= bxy2i+ bx2yj+ (x2+y2)z2k and S is the boundary of the solid cylinder x2+y2≤a2 and 0≤z≤b.

Answer

∬ S F · d S = π a 4 b 2

6-421 §6.8 source ↗

For the following exercises, use a CAS and the divergence theorem to compute the net outward flux for the vector fields across the boundary of the given regions D.

Use the divergence theorem to evaluate ∬SF·dS, where F(x,y,z)= xyi− 12y2j+ zk and S is the surface consisting of three pieces: z= 4− 3x2− 3y2, 1≤z≤4 on the top; x2+ y2= 1, 0≤z≤1 on the sides; and z=0 on the bottom.

Answer

∬ S F · d S = 5 π 2

6-423 §6.8 source ↗

For the following exercises, use a CAS and the divergence theorem to compute the net outward flux for the vector fields across the boundary of the given regions D.

Use the divergence theorem to evaluate ∬SF·dS, where F(x,y,z)= xi+ yj+ zk and S is the boundary of the solid enclosed by paraboloid y=x2+z2−2, cylinder x2+z2=1, and plane x+y=2, and S is oriented outward.

Answer

∬ S F · d S = 21 π 2

6-425 §6.8 source ↗

For the following exercises, Fourier’s law of heat transfer states that the heat flow vector F at a point is proportional to the negative gradient of the temperature; that is, F=−k∇T, which means that heat energy flows hot regions to cold regions. The constant k>0 is called the conductivity, which has metric units of joules per meter per second-kelvin or watts per meter-kelvin. A temperature function for region D is given. Use the divergence theorem to find net outward heat flux ∬SF·NdS= −k∬S∇T·NdS across the boundary S of D, where k=1.

T(x,y,z)= 100+ e−z; D= {(x,y,z):0≤x≤1,0≤y≤1,0≤z≤1}

Answer

e - 1 - 1

6-427 §6.R source ↗

True or False? Justify your answer with a proof or a counterexample.

Vector field F(x,y)= x2yi+ y2xj is conservative.

Answer

False

6-429 §6.R source ↗

True or False? Justify your answer with a proof or a counterexample.

The divergence of a vector field is a vector field.

Answer

False

6-431 §6.R source ↗

Draw the following vector fields.

F (x,y)= 1 2 i + 2x j

Answer


A vector field in two dimensions. All quadrants are shown. The arrows are larger the further from the y axis they become. They point up and to the right for positive x values and down and to the right for negative x values. The further from the y axis they are, the steeper the slope they have.

6-433 §6.R source ↗

Are the following the vector fields conservative? If so, find the potential function f such that F=∇f.

F (x,y)= y i + (x−2 e y ) j

Answer

Conservative, f(x,y)= xy− 2ey

6-435 §6.R source ↗

Are the following the vector fields conservative? If so, find the potential function f such that F=∇f.

F (x,y,z)= (2xy+ z 2 ) i + ( x 2 +2yz) j + (2xz+ y 2 ) k

Answer

Conservative, f(x,y,z)= x2y+ y2z+ z2x

6-437 §6.R source ↗

Evaluate the following integrals.

∫Cx2dy+(2x−3xy)dx, along C:y=12x from (0, 0) to (4, 2)

Answer

− 16 3

6-439 §6.R source ↗

Evaluate the following integrals.

∬Sxy2dS, where S is surface z= x2− y, 0≤x≤1, 0≤y≤4

Answer

32 2 9 ( 3 3 − 1 )

6-441 §6.R source ↗

Find the divergence and curl for the following vector fields.

F (x,y,z)= e x i + e x y j + e x y z k

Answer

Divergence: ex+ xexy+ xyexyz, curl: xzexyzi− yzexyzj+ yexyk

6-443 §6.R source ↗

Use Green’s theorem to evaluate the following integrals.

∫C3ydx+(x+ey)dy, where C is a circle centered at the origin with radius 3

Answer

−18 π

6-445 §6.R source ↗

Use Stokes’ theorem to evaluate ∬ScurlF·dS.

F(x,y,z)= yi+ xyzj− 2zxk, where S is the upward-facing paraboloid z=x2+y2 lying in cylinder x2+y2=1

Answer

− π

6-447 §6.R source ↗

Use the divergence theorem to evaluate ∬SF·dS.

F(x,y,z)= (2xy)i+ (−y2)j+ (2z3)k, where S is bounded by paraboloid z=x2+y2 and plane z=2

Answer

24 π

6-449 §6.R source ↗

Use the divergence theorem to evaluate ∬SF·dS.

Find the total mass of a thin wire in the shape of an upper semicircle with radius 2, and a density function of ρ(x,y)= y+ x2.

Answer

2 (2 2 +π)= 4+ π 2

6-451 §6.R source ↗

Use the divergence theorem to evaluate ∬SF·dS.

Use the divergence theorem to compute the value of the flux integral over the unit sphere with F(x,y,z)= 3zi+ 2yj+ 2xk.

Answer

8 π / 3

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Problems and answers are adapted from Calculus Volume 3 by Gilbert Strang and Edwin “Jed” Herman, OpenStax, and are used under the CC BY-NC-SA 4.0 licence. Access for free at https://openstax.org/books/calculus-volume-3/pages/1-introduction. Illustrations: Copyright Rice University, OpenStax, under CC BY-NC-SA 4.0 license. This adaptation is released under the same licence, is non-commercial, and is neither affiliated with nor endorsed by OpenStax or Rice University.