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Chapter 7: Second-Order Differential Equations

87 problems · 5 figures

Checkpoint 7.1 §7.1 source ↗

Classify each of the following equations as linear or nonlinear. If the equation is linear, determine further whether it is homogeneous or nonhomogeneous.

a. (y″)2− y′+ 8x3y= 0

b. (sint)y″+ cost− 3ty′= 0

Answer

a. Nonlinear

b. Linear, nonhomogeneous

Checkpoint 7.4 §7.1 source ↗

Determine whether the following pairs of functions are linearly dependent or linearly independent: f1(x)=ex, f2(x)=3e3x.

Answer

Linearly independent

Checkpoint 7.5 §7.1 source ↗

If y1(x)=e3x and y2(x)=xe3x are solutions to y″− 6y′+ 9y= 0, what is the general solution?

Answer

y(x)= c 1 e 3 x + c 2 x e 3 x

Checkpoint 7.6 §7.1 source ↗

Find the general solution to the following differential equations:

a. y″− 2y′+ 10y= 0

b. y″+ 14y′+ 49y= 0

Answer

a. y(x)= ex(c1cos3x+c2sin3x)

b. y(x)= c1e−7x+ c2xe−7x

Checkpoint 7.7 §7.1 source ↗

Solve the initial-value problem y″− 3y′− 10y= 0, y(0)=0, y′(0)=7.

Answer

y(x)= − e −2 x + e 5 x

Checkpoint 7.8 §7.1 source ↗

Solve the following initial-value problem and graph the solution: y″− 2y′+ 10y= 0, y(0)= 2, y′(0)= −1

Answer

y(x)= ex(2cos3x−sin3x)

This figure is the graph of y(x) = e^x(2 cos 3x − sin 3x) It has the positive x axis scaled in increments of even tenths. The y axis is scaled in increments of twenty. The graph itself starts at the origin. Its amplitude increases as x increases.

Checkpoint 7.9 §7.1 source ↗

Suppose the following initial-value problem models the position (in feet) of a mass in a spring-mass system at any given time. Solve the initial-value problem and graph the solution. What is the position of the mass at time t=0.3 sec? How fast is it moving at time t=0.1 sec? In what direction?

y″+14y′+49y=0,y(0)=0,y′(0)=1

Answer

y(t)=te−7t

This figure is the graph of y(t) = te^−7t. The horizontal axis is labeled with t and is scaled in increments of tenths. The y axis is scaled in increments of 0.5. The graph passes through the origin and has a horizontal asymptote of the positive t axis.


At time t=0.3, y(0.3)= 0.3e(−7*0.3)= 0.3e−2.1≈ 0.0367. The mass is 0.0367 ft below equilibrium. At time t=0.1, y′(0.1)= 0.3e−0.7≈ 0.1490. The mass is moving downward at a speed of 0.1490 ft/sec.

7-1 §7.1 source ↗

Classify each of the following equations as linear or nonlinear. If the equation is linear, determine whether it is homogeneous or nonhomogeneous.

x 3 y ″ + (x−1) y ′ − 8y= 0

Answer

linear, homogenous

7-3 §7.1 source ↗

Classify each of the following equations as linear or nonlinear. If the equation is linear, determine whether it is homogeneous or nonhomogeneous.

x y ″ + e y y ′ = x

Answer

nonlinear

7-5 §7.1 source ↗

Classify each of the following equations as linear or nonlinear. If the equation is linear, determine whether it is homogeneous or nonhomogeneous.

y ″ + (sinx) y ′ − xy= 4y

Answer

linear, homogeneous

7-11 §7.1 source ↗

For each of the following problems, verify that the given function is a solution to the differential equation. Use a graphing utility to graph the particular solutions for several values of c1 and c2. What do the solutions have in common?

y ″ − 3 y ′ − 10y= 0

Answer

y= c 1 e 5 x + c 2 e −2 x

7-13 §7.1 source ↗

For each of the following problems, verify that the given function is a solution to the differential equation. Use a graphing utility to graph the particular solutions for several values of c1 and c2. What do the solutions have in common?

y ″ + 4 y ′ + 4 y = 0

Answer

y= c 1 e −2 x + c 2 x e −2 x

7-15 §7.1 source ↗

For each of the following problems, verify that the given function is a solution to the differential equation. Use a graphing utility to graph the particular solutions for several values of c1 and c2. What do the solutions have in common?

2 y ″ − 3 y ′ − 5y= 0

Answer

y= c 1 e 5 x / 2 + c 2 e − x

7-17 §7.1 source ↗

For each of the following problems, verify that the given function is a solution to the differential equation. Use a graphing utility to graph the particular solutions for several values of c1 and c2. What do the solutions have in common?

y ″ + y ′ + y = 0

Answer

y= e − x / 2 ( c 1 cos 3 x 2 + c 2 sin 3 x 2 )

7-19 §7.1 source ↗

For each of the following problems, verify that the given function is a solution to the differential equation. Use a graphing utility to graph the particular solutions for several values of c1 and c2. What do the solutions have in common?

y ″ − 121 y = 0

Answer

y= c 1 e −11 x + c 2 e 11 x

7-21 §7.1 source ↗

For each of the following problems, verify that the given function is a solution to the differential equation. Use a graphing utility to graph the particular solutions for several values of c1 and c2. What do the solutions have in common?

y ″ + 81 y = 0

Answer

y= c 1 cos9x+ c 2 sin9x

7-23 §7.1 source ↗

For each of the following problems, verify that the given function is a solution to the differential equation. Use a graphing utility to graph the particular solutions for several values of c1 and c2. What do the solutions have in common?

2 y ″ = 0

Answer

y = c 1 + c 2 x

7-25 §7.1 source ↗

For each of the following problems, verify that the given function is a solution to the differential equation. Use a graphing utility to graph the particular solutions for several values of c1 and c2. What do the solutions have in common?

3 y ″ − 2 y ′ − 7y= 0

Answer

y= c 1 e ( ( 1 + 22 ) / 3 ) x + c 2 e ( ( 1 − 22 ) / 3 ) x

7-27 §7.1 source ↗

For each of the following problems, verify that the given function is a solution to the differential equation. Use a graphing utility to graph the particular solutions for several values of c1 and c2. What do the solutions have in common?

36 d 2 y d x 2 + 12 d y d x + y= 0

Answer

y= c 1 e − x / 6 + c 2 x e − x / 6

7-29 §7.1 source ↗

For each of the following problems, verify that the given function is a solution to the differential equation. Use a graphing utility to graph the particular solutions for several values of c1 and c2. What do the solutions have in common?

d 2 y d x 2 − 9 d y d x = 0

Answer

y = c 1 + c 2 e 9 x

7-31 §7.1 source ↗

Solve the initial-value problem.

y ″ + 5 y ′ + 6y= 0, y(0)= 0, y ′ (0)= −2

Answer

y= −2 e −2 x + 2 e −3 x

7-33 §7.1 source ↗

Solve the initial-value problem.

y ″ + 4y= 0, y(0)= 3, y ′ (0)= 10

Answer

y= 3cos(2x)+ 5sin(2x)

7-35 §7.1 source ↗

Solve the initial-value problem.

y ″ − y ′ − 30y= 0, y(0)= 1, y ′ (0)= −16

Answer

y= − e 6 x + 2 e −5 x

7-37 §7.1 source ↗

Solve the initial-value problem.

25 y ″ + 10 y ′ + y= 0, y(0)= 2, y ′ (0)= 1

Answer

y= 2 e − x / 5 + 7 5 x e − x / 5

7-39 §7.1 source ↗

Solve the boundary-value problem, if possible.

y ″ + y ′ − 42y= 0, y(0)= 0, y(1)= 2

Answer

y= ( 2 e 6 − e −7 ) e 6 x − ( 2 e 6 − e −7 ) e −7 x

7-41 §7.1 source ↗

Solve the boundary-value problem, if possible.

y ″ + 10 y ′ + 34y= 0, y(0)= 6, y(π)= 2

Answer

No solutions exist.

7-43 §7.1 source ↗

Solve the boundary-value problem, if possible.

y ″ − 4 y ′ + 4y= 0, y(0)= 2, y(1)= −1

Answer

y= 2 e 2 x − 2 e 2 + 1 e 2 x e 2 x

7-45 §7.1 source ↗

Solve the boundary-value problem, if possible.

y ″ + 9y= 0, y(0)= 4, y( π 3 )= −4

Answer

y= 4cos3x+ c 2 sin3x, infinitely many solutions

7-47 §7.1 source ↗

Solve the boundary-value problem, if possible.

Find a differential equation with a general solution that is y= c1ex/5+ c2e−4x.

Answer

5 y ″ + 19 y ′ − 4y= 0

7-49 §7.1 source ↗

For each of the following differential equations:

y ″ + 64y= 0; y(0)= 3, y ′ (0)= –24

Answer

a. y=3cos(8x)
b.

This figure is a periodic graph. It has an amplitude of 3.5. Both the x and y axes are scaled in increments of 1.

7-51 §7.1 source ↗

For each of the following differential equations:

y ″ + 5 y ′ + 15y= 0 y(0)= −2, y ′ (0)= 7

Answer

a. y= e(−5/2)x[−2cos(352x)+43535sin(352x)]
b.

This figure is a graph of an oscillating function. The amplitude of the graph is decreasing as x increases.

Checkpoint 7.10 §7.2 source ↗

Given that yp(x)=−2 is a particular solution to y″− 3y′− 4y= 8, write the general solution and verify that the general solution satisfies the equation.

Answer

y(x)= c 1 e − x + c 2 e 4 x − 2

Checkpoint 7.11 §7.2 source ↗

Find the general solution to y″− 4y′+ 4y= 7sint− cost.

Answer

y(t)= c 1 e 2 t + c 2 t e 2 t + sint+ cost

Checkpoint 7.12 §7.2 source ↗

Find the general solution to the following differential equations.

a. y″− 5y′+ 4y= 3ex

b. y″+ y′− 6y= 52cos2t

Answer

a. y(x)= c1e4x+ c2ex− xex

b. y(t)= c1e−3t+ c2e2t− 5cos2t+ sin2t

Checkpoint 7.13 §7.2 source ↗

Use Cramer’s rule to solve the following system of equations.

2xz1−3z2=0x2z1+4xz2=x+1

Answer

z1= 3x+311x2, z2=2x+211x

Checkpoint 7.14 §7.2 source ↗

Find the general solution to the following differential equations.

a. y″+y=secx

b. x″− 2x′+ x= ett

Answer

a. y(x)= c1cosx+ c2sinx+ cosxln|cosx|+ xsinx

b. x(t)= c1et+ c2tet+ tetln|t|

7-55 §7.2 source ↗

Solve the following equations using the method of undetermined coefficients.

3 y ″ + y ′ − 4 y = 8

Answer

y= c 1 e −4 x / 3 + c 2 e x − 2

7-57 §7.2 source ↗

Solve the following equations using the method of undetermined coefficients.

y ″ + 16 y = e −2 x

Answer

y= c 1 cos4x+ c 2 sin4x+ 1 20 e −2 x

7-59 §7.2 source ↗

Solve the following equations using the method of undetermined coefficients.

y ″ − 4 y ′ + 4y= 8 x 2 + 4x

Answer

y= c 1 e 2 x + c 2 x e 2 x + 2 x 2 + 5x+ 4

7-61 §7.2 source ↗

Solve the following equations using the method of undetermined coefficients.

y ″ + 2 y ′ + y= sinx+ cosx

Answer

y= c 1 e − x + c 2 x e − x + 1 2 sinx− 1 2 cosx

7-63 §7.2 source ↗

Solve the following equations using the method of undetermined coefficients.

y ″ + y= 3sin2x+ xcos2x

Answer

y= c 1 cosx+ c 2 sinx− 1 3 xcos2x− 5 9 sin2x

7-65 §7.2 source ↗

Solve the following equations using the method of undetermined coefficients.

y ″ + 10 y ′ + 25y= x e −5 x + 4

Answer

y= c 1 e −5 x + c 2 x e −5 x + 1 6 x 3 e −5 x + 4 25

7-67 §7.2 source ↗

In each of the following problems,

y ″ − 3y= x 2 − 4x+ 11

Answer

a. yp(x)= Ax2+ Bx+ C
b. yp(x)= − 13x2+ 43x− 359

7-69 §7.2 source ↗

In each of the following problems,

2 y ″ − y ′ + y= ( x 2 −5x) e − x

Answer

a. yp(x)= (Ax2+Bx+C)e−x
b. yp(x)= (14x2−58x−3332)e−x

7-71 §7.2 source ↗

In each of the following problems,

y ″ − y ′ − 2y= x 2 e x sinx

Answer

a. yp(x)= (Ax2+Bx+C)excosx + (Dx2+Ex+F)exsinx
b. yp(x)= (−110x2−1125x−27250)excosx + (−310x2+225x+39250)exsinx

7-73 §7.2 source ↗

Solve the differential equation using either the method of undetermined coefficients or the variation of parameters.

y ″ + 2 y ′ = e 3 x

Answer

y= c 1 + c 2 e −2 x + 1 15 e 3 x

7-75 §7.2 source ↗

Solve the differential equation using either the method of undetermined coefficients or the variation of parameters.

y ″ + 2 y ′ − 8y= 6 e 2 x

Answer

y= c 1 e 2 x + c 2 e −4 x + x e 2 x

7-77 §7.2 source ↗

Solve the differential equation using the method of variation of parameters.

y ″ − 9 y = 8 x

Answer

y= c 1 e 3 x + c 2 e −3 x − 8 x 9

7-79 §7.2 source ↗

Solve the differential equation using the method of variation of parameters.

y ″ + 4y= 3csc2x, 0< x< π/2

Answer

y= c 1 cos2x+ c 2 sin2x− 3 2 xcos2x+ 3 4 sin2xln(sin2x)

7-81 §7.2 source ↗

Find the unique solution satisfying the differential equation and the initial conditions given, where yp(x) is the particular solution.

y″− 7y′= 4xe7x, yp(x)= 27x2e7x− 449xe7x, y(0)= −1, y′(0)= 0

Answer

y= − 347 343 + 4 343 e 7 x + 2 7 x 2 e 7 x − 4 49 x e 7 x

7-83 §7.2 source ↗

Find the unique solution satisfying the differential equation and the initial conditions given, where yp(x) is the particular solution.

y″− 5y′= e5x+ 8e−5x, yp(x)= 15xe5x+ 425e−5x, y(0)= −2, y′(0)= 0

Answer

y= − 57 25 + 3 25 e 5 x + 1 5 x e 5 x + 4 25 e −5 x

7-85 §7.2 source ↗

In each of the following problems, two linearly independent solutions—y1 and y2—are given that satisfy the corresponding homogeneous equation. Use the method of variation of parameters to find a particular solution to the given nonhomogeneous equation. Assume x > 0 in each exercise.

x2y″− 2y= 10x2− 1, y1(x)= x2, y2(x)= x−1

Answer

y p = 1 2 + 10 3 x 2 lnx

Checkpoint 7.15 §7.3 source ↗

A 200-g mass stretches a spring 5 cm. Find the equation of motion of the mass if it is released from rest from a position 10 cm below the equilibrium position. What is the frequency of this motion?

Answer

x(t)= 0.1cos(14t) (in meters); frequency is 142π Hz.

Checkpoint 7.16 §7.3 source ↗

Express the function x(t)= cos(4t)+ 4sin(4t) in the form Asin(ωt+ϕ). What is the frequency of motion? The amplitude?

Answer

x(t)= 17sin(4t+0.245), frequency= 42π≈ 0.637, A=17

Checkpoint 7.17 §7.3 source ↗

A 2-kg mass is attached to a spring with spring constant 24 N/m. The system is then immersed in a medium imparting a damping force equal to 16 times the instantaneous velocity of the mass. Find the equation of motion if it is released from rest at a point 40 cm below equilibrium.

Answer

x(t)= 0.6 e −2 t − 0.2 e −6 t

Checkpoint 7.18 §7.3 source ↗

A 1-lb weight stretches a spring 6 in., and the system is attached to a dashpot that imparts a damping force equal to half the instantaneous velocity of the mass. Find the equation of motion if the mass is released from rest at a point 6 in. below equilibrium.

Answer

x(t)= 1 2 e −8 t + 4t e −8 t

Checkpoint 7.19 §7.3 source ↗

A 1-kg mass stretches a spring 49 cm. The system is immersed in a medium that imparts a damping force equal to four times the instantaneous velocity of the mass. Find the equation of motion if the mass is released from rest at a point 24 cm above equilibrium.

Answer

x(t)= −0.24 e −2 t cos(4t)− 0.12 e −2 t sin(4t)

Checkpoint 7.20 §7.3 source ↗

A mass of 2 kg is attached to a spring with constant 32 N/m and comes to rest in the equilibrium position. Beginning at time t=0, an external force equal tof(t)= 68e−2tcos(4t) is applied to the system. Find the equation of motion if there is no damping. What is the transient solution? What is the steady-state solution?

Answer

x(t)= − 12cos(4t)+ 94sin(4t)+ 12e−2tcos(4t)− 2e−2tsin(4t)
Transient solution:12e−2tcos(4t)− 2e−2tsin(4t)
Steady-state solution:− 12cos(4t)+ 94sin(4t)

Checkpoint 7.21 §7.3 source ↗

Find the charge on the capacitor in an RLC series circuit where L=1/5 H, R=2/5Ω, C=1/2 F, and E(t)=50 V. Assume the initial charge on the capacitor is 0 C and the initial current is 4 A.

Answer

q(t)= −25 e − t cos(3t)− 7 e − t sin(3t)+ 25

7-87 §7.3 source ↗

A mass weighing 2 lb stretches a spring 2 ft. Find the equation of motion if the spring is released from 2 in. below the equilibrium position with an upward velocity of 8 ft/sec. What is the period and frequency of the motion?

Answer

x″+16x=0, x(t)= 16cos(4t)− 2sin(4t), period =π2sec, frequency =2πHz

7-89 §7.3 source ↗

A 400-g mass stretches a spring 5 cm. Find the equation of motion of the mass if it is released from rest from a position 15 cm below the equilibrium position. What is the frequency of this motion?

Answer

x″+196x=0, x(t)= 0.15cos(14t), period =π7sec, frequency =7πHz

7-91 §7.3 source ↗

A block has a mass of 5 kg and is attached to a vertical spring with a spring constant of 20 N/m. The block is released from the equilibrium position with a downward velocity of 10 m/sec.

a. Find the position function x(t) of the block.

b. Find the period and frequency of the vibration.

c. Sketch a graph of x(t).

d. At what time does the block first pass through the equilibrium position?

Answer

a. x(t)= 5sin(2t)
b. period =πsec, frequency =1πHz
c.

This figure is the graph of a function. It is a periodic function with consistent amplitude. The horizontal axis is labeled in increments of 1. The vertical axis is labeled in increments of 1.5.


d. t=π2sec

7-93 §7.3 source ↗

An 800-lb weight (25 slugs) is attached to a vertical spring with a spring constant of 226 lb/ft. The system is immersed in a medium that imparts a damping force equal to 10 times the instantaneous velocity of the mass.

a. Find the equation of motion if it is released from a position 20 ft below its equilibrium position with a downward velocity of 41 ft/sec.

b. Graph the solution and determine whether the motion is overdamped, critically damped, or underdamped.

Answer

a. x(t)= e−t/5(20cos(3t)+15sin(3t))
b. underdamped

7-95 §7.3 source ↗

A 1-kg mass stretches a spring 61.25 cm. The resistance in the spring-mass system is equal to eight times the instantaneous velocity of the mass.

a. Find the equation of motion if the mass is released from a position 5 m below its equilibrium position with an upward velocity of 10 m/sec.

b. Determine whether the motion is overdamped, critically damped, or underdamped.

Answer

a. x(t)= e−4t(–5cos11.866t – 0.834sin11.866t)
b. underdamped

7-97 §7.3 source ↗

A 64-lb weight is attached to a vertical spring with a spring constant of 4.625 lb/ft. The resistance in the spring-mass system is equal to the instantaneous velocity. The weight is set in motion from a position 1 ft below its equilibrium position with an upward velocity of 2 ft/sec. Is the mass above or below the equilibrium position at the end of π sec? By what distance?

Answer

x(π)= 7e−π/46 ft below

7-99 §7.3 source ↗

A mass that weighs 6 lb stretches a spring 3 in. The system is acted on by an external force of 8sin(4t) lb. If the mass is pulled down 1 inch and then released, determine the position of the mass at any time.

Answer

x(t)= 1 2 cos(8 2 t)– 4 2 21 sin 8 2 t + 8 21 sin 8 2 t

7-101 §7.3 source ↗

Find the charge on the capacitor in an RLC series circuit where L=2 H, R=24Ω, C=0.005 F, and E(t)= 12sin10t V. Assume the initial charge on the capacitor is 0.001 C and the initial current is 0 A.

Answer

q(t)= e −6 t (0.051cos(8t)+0.03825sin(8t))− 1 20 cos(10t)

7-103 §7.3 source ↗

A series circuit consists of a device where L=12 H, R=10Ω, C=150 F, and E(t)=250 V. If the initial charge on the capacitor is 0 C and the initial current is 18 A, find the charge and current at time t.

Answer

q(t)= e −10 t (−32t−5)+ 5, I(t)= 2 e −10 t (160t+9)

Checkpoint 7.22 §7.4 source ↗

Find a power series solution for the following differential equations.

a. y′+2xy=0

b. (x+1)y′=3y

Answer

a. y(x)= a0∑n=0∞(−1)nn!x2n= a0e−x2

b. y(x)= a0(x+1)3

7-105 §7.4 source ↗

Find a power series solution for the following differential equations.

5 y ″ + y ′ = 0

Answer

y= a 0 + 5 a 1 ∑ n = 1 ∞ ( − x / 5 ) n n ! = c 0 + 5 c 1 e − x / 5

7-107 §7.4 source ↗

Find a power series solution for the following differential equations.

y ″ − y = 0

Answer

y= a 0 ∑ n = 0 ∞ ( x ) 2 n ( 2 n ) ! + a 1 ∑ n = 0 ∞ ( x ) 2 n + 1 ( 2 n + 1 ) !

7-109 §7.4 source ↗

Find a power series solution for the following differential equations.

y ′ − 2 x y = 0

Answer

y= a 0 ∑ n = 0 ∞ x 2 n n ! = c 0 e x 2

7-111 §7.4 source ↗

Find a power series solution for the following differential equations.

y ″ − x y ′ − y = 0

Answer

y= a 0 ∑ n = 0 ∞ x 2 n 2 n n ! + a 1 ∑ n = 0 ∞ x 2 n + 1 1 ⋅ 3 ⋅ 5 ⋅ 7 ⋯ ( 2 n + 1 )

7-113 §7.4 source ↗

Find a power series solution for the following differential equations.

x 2 y ″ − x y ′ − 3y= 0

Answer

y = c 0 x 3 + c 1 x

7-115 §7.4 source ↗

Find a power series solution for the following differential equations.

y ″ − 2xy= 0, y(0)= 1, y ′ (0)= −3

Answer

y= 1− 3x+ 2 x 3 3 ! − 12 x 4 4 ! + 16 x 6 6 ! − 120 x 7 7 ! + ⋯

7-117 §7.R source ↗

True or False? Justify your answer with a proof or a counterexample.

If y and z are both solutions to y″+2y′+y=0, then y+z is also a solution.

Answer

True

7-119 §7.R source ↗

True or False? Justify your answer with a proof or a counterexample.

y= excos(3x)+ exsin(2x) is a solution to the second-order differential equation y″+ 2y′+ 10= 0.

Answer

False

7-121 §7.R source ↗

Classify the differential equation. Determine the order, whether it is linear and, if linear, whether the differential equation is homogeneous or nonhomogeneous. If the equation is second-order homogeneous and linear, find the characteristic equation.

y ″ − 2 y = 0

Answer

second order, linear, homogeneous, λ2−2=0

7-123 §7.R source ↗

Classify the differential equation. Determine the order, whether it is linear and, if linear, whether the differential equation is homogeneous or nonhomogeneous. If the equation is second-order homogeneous and linear, find the characteristic equation.

( d y d t ) 2 + y y ′ = 1

Answer

first order, nonlinear, nonhomogeneous

7-125 §7.R source ↗

For the following problems, find the general solution.

y ″ + 9 y = 0

Answer

y= c 1 cos(3x)+ c 2 sin(3x)

7-127 §7.R source ↗

For the following problems, find the general solution.

y ″ − 2 y ′ + 10y= 4x

Answer

y= c 1 e x cos(3x)+ c 2 e x sin(3x)+ 2 5 x+ 2 25

7-129 §7.R source ↗

For the following problems, find the general solution.

y '' + 5y′+ 4y= x+ e 2 x

Answer

y= c 1 e − x + c 2 e −4 x + x 4 + e 2 x 18 − 5 16

7-131 §7.R source ↗

For the following problems, find the general solution.

y ″ − x 2 = −3 y ′ − 9 4 y+ 3x

Answer

y= c 1 e ( −3 / 2 ) x + c 2 x e ( −3 / 2 ) x + 4 9 x 2 + 4 27 x− 16 27

7-133 §7.R source ↗

For the following problems, find the solution to the initial-value problem, if possible.

y″+ 4y′+ 6y= 0, y(0)=0, y′(0)=2

Answer

y= e −2 x sin( 2 x)

7-135 §7.R source ↗

For the following problems, find the solution to the boundary-value problem, if possible.

4y′= −6y+ 2y″, y(0)=0, y(1)=1

Answer

y= e 1 − x e 4 − 1 ( e 4 x −1)

7-137 §7.R source ↗

For the following problem, set up and solve the differential equation.

The motion of a swinging pendulum for small angles θ can be approximated by d2θdt2+ gLθ= 0, where θ is the angle the pendulum makes with respect to a vertical line, g is the acceleration resulting from gravity, and L is the length of the pendulum. Find the equation describing the angle of the pendulum at time t, assuming an initial displacement of θ0 and an initial velocity of zero.

Answer

θ(t)= θ 0 cos( g l L)

7-141 §7.R source ↗

For the following problem, set up and solve the differential equations.

An opera singer is attempting to shatter a glass by singing a particular note. The vibrations of the glass can be modeled by y″+ay=0, where a>0 represents the natural frequency of the glass and the singer is forcing the vibrations at cos(bt). For what value b would the singer be able to break that glass? (Note: in order for the glass to break, the oscillations would need to get higher and higher.)

Answer

b = a

End of the book.

Problems and answers are adapted from Calculus Volume 3 by Gilbert Strang and Edwin “Jed” Herman, OpenStax, and are used under the CC BY-NC-SA 4.0 licence. Access for free at https://openstax.org/books/calculus-volume-3/pages/1-introduction. Illustrations: Copyright Rice University, OpenStax, under CC BY-NC-SA 4.0 license. This adaptation is released under the same licence, is non-commercial, and is neither affiliated with nor endorsed by OpenStax or Rice University.