Every problem in the chapter beside the book’s answer, a chapter at a time as you scroll.
Chapter 19: Electric Potential and Electric Field
54 problems · 4 figures19-1 §19.1 source ↗
Answer
19-4 §19.1 source ↗
Integrated Concepts
Singly charged gas ions are accelerated from rest through a voltage of 13.0 V. At what temperature will the average kinetic energy of gas molecules be the same as that given these ions?
Answer
19-6 §19.1 source ↗
Integrated Concepts
(a) What is the average power output of a heart defibrillator that dissipates 400 J of energy in 10.0 ms? (b) Considering the high-power output, why doesn’t the defibrillator produce serious burns?
Answer
(a)
(b) A defibrillator does not cause serious burns because the skin conducts electricity well at high voltages, like those used in defibrillators. The gel used aids in the transfer of energy to the body, and the skin doesn’t absorb the energy, but rather lets it pass through to the heart.
19-8 §19.1 source ↗
Integrated Concepts
A 12.0 V battery-operated bottle warmer heats 50.0 g of glass, of baby formula, and of aluminum from to . (a) How much charge is moved by the battery? (b) How many electrons per second flow if it takes 5.00 min to warm the formula? (Hint: Assume that the specific heat of baby formula is about the same as the specific heat of water.)
Answer
(a)
(b)
19-9 §19.1 source ↗
Integrated Concepts
A battery-operated car utilizes a 12.0 V system. Find the charge the batteries must be able to move in order to accelerate the 750 kg car from rest to 25.0 m/s, make it climb a high hill, and then cause it to travel at a constant 25.0 m/s by exerting a force for an hour.
Answer
19-11 §19.1 source ↗
Unreasonable Results
(a) Find the voltage near a 10.0 cm diameter metal sphere that has 8.00 C of excess positive charge on it. (b) What is unreasonable about this result? (c) Which assumptions are responsible?
Answer
(a)
(b) This voltage is very high. A 10.0 cm diameter sphere could never maintain this voltage; it would discharge.
(c) An 8.00 C charge is more charge than can reasonably be accumulated on a sphere of that size.
19-15 §19.2 source ↗
Answer
(a)
(b)
19-17 §19.2 source ↗
Answer
(a) No. The electric field strength between the plates is which is lower than the breakdown strength for air ().
(b) 1.7 mm
19-19 §19.2 source ↗
Answer
19-21 §19.2 source ↗
Answer
19-23 §19.2 source ↗
Answer
(a)
(b)
19-24 §19.3 source ↗
Answer
19-26 §19.3 source ↗
Answer
(a) 1.80 km
(b) A charge of 1 C is a very large amount of charge; a sphere of radius 1.80 km is not practical.
19-28 §19.3 source ↗
Answer
19-30 §19.3 source ↗
Answer
(a)
(b) 152 MeV
19-32 §19.3 source ↗
Answer
(a)
(b)
19-35 §19.3 source ↗
Unreasonable Results
(a) What is the final speed of an electron accelerated from rest through a voltage of 25.0 MV by a negatively charged Van de Graaff terminal?
(b) What is unreasonable about this result?
(c) Which assumptions are responsible?
Answer
(a)
(b) This velocity is far too great. It is faster than the speed of light.
(c) The assumption that the speed of the electron is far less than that of light and that the problem does not require a relativistic treatment produces an answer greater than the speed of light.
19-46 §19.5 source ↗
Answer
19-48 §19.5 source ↗
Answer
19-50 §19.5 source ↗
Answer
19-52 §19.5 source ↗
Answer
19-54 §19.5 source ↗
Answer
(a)
(b)
19-56 §19.5 source ↗
Unreasonable Results
(a) A certain parallel plate capacitor has plates of area , separated by 0.0100 mm of nylon, and stores 0.170 C of charge. What is the applied voltage? (b) What is unreasonable about this result? (c) Which assumptions are responsible or inconsistent?
Answer
(a) 14.2 kV
(b) The voltage is unreasonably large, more than 100 times the breakdown voltage of nylon.
(c) The assumed charge is unreasonably large and cannot be stored in a capacitor of these dimensions.
19-57 §19.6 source ↗
Answer
19-59 §19.6 source ↗
Answer
19-60 §19.6 source ↗
Answer
19-62 §19.6 source ↗
Unreasonable Results
(a) An capacitor is connected in parallel to another capacitor, producing a total capacitance of . What is the capacitance of the second capacitor? (b) What is unreasonable about this result? (c) Which assumptions are unreasonable or inconsistent?
Answer
(a)
(b) You cannot have a negative value of capacitance.
(c) The assumption that the capacitors were hooked up in parallel, rather than in series, was incorrect. A parallel connection always produces a greater capacitance, while here a smaller capacitance was assumed. This could happen only if the capacitors are connected in series.
19-63 §19.7 source ↗
Answer
(a)
(b)
19-64 §19.7 source ↗
Answer
(a) 3.16 kV
(b) 25.3 mC
19-66 §19.7 source ↗
Answer
(a) ,
(b) ,
19-67 §19.7 source ↗
Answer
(a)
(b)
(c)
19-70 §19.7 source ↗
Unreasonable Results
(a) On a particular day, it takes of electric energy to start a truck’s engine. Calculate the capacitance of a capacitor that could store that amount of energy at 12.0 V. (b) What is unreasonable about this result? (c) Which assumptions are responsible?
Answer
(a)
(b) Such a capacitor would be too large to carry with a truck. The size of the capacitor would be enormous.
(c) It is unreasonable to assume that a capacitor can store the amount of energy needed.
AP Test Prep 19.1 §19.1 source ↗
- a.1.33×10-20 N right
- b.1.33×10-20 N left
- c.1.92×10-18 N right
- d.1.92×10-18 N left
Answer
AP Test Prep 19.3 §19.1 source ↗
- a.12 N/C south
- b.12 N/C north
- c.300 N/C south
- d.300 N/C north
Answer
AP Test Prep 19.5 §19.1 source ↗
- a.4.80×1027
- b.4.00×1026
- c.3.75×1021
- d.3.13×1020
Answer
AP Test Prep 19.7 §19.1 source ↗
- a.1000 minutes
- b.120,000 seconds
- c.15 hours
- d.250 minutes
Answer
AP Test Prep 19.9 §19.1 source ↗
- a.−3.8×10-2 J
- b.−4.5×10-2 J
- c.4.5×10-2 J
- d.3.8×10-2 J
Answer
AP Test Prep 19.11 §19.1 source ↗
- a.increases, increases
- b.increases, decreases
- c.decreases, increases
- d.decreases, decreases
Answer
AP Test Prep 19.13 §19.1 source ↗
- a.increase
- b.decrease
- c.no change
- d.not enough information
Answer
AP Test Prep 19.15 §19.1 source ↗
- a.maximum, maximum
- b.maximum, minimum
- c.minimum, maximum
- d.minimum, minimum
Answer
AP Test Prep 19.17 §19.2 source ↗
- a.A rightward-curving parabola
- b.A leftward-curving parabola
- c.A rightward-curving section of a circle
- d.A leftward-curving section of a circle
Answer
AP Test Prep 19.19 §19.2 source ↗
- a.500 V/m, 1500 V/m, down
- b.500 V/m, 1500 V/m, up
- c.1500 V/m, 500 V/m, down
- d.1500 V/m, 500 V/m, up
Answer
AP Test Prep 19.21 §19.2 source ↗
- a.1500 V/m
- b.2500 V/m
- c.4000 V/m
- d.2000 V/m
Answer
AP Test Prep 19.23 §19.2 source ↗
- a.750 V/m
- b.150 V/m
- c.38 V/m
- d.75 V/m
Answer
AP Test Prep 19.25 §19.4 source ↗
- a.The equipotential lines would have positive values.
- b.It would actually resemble Figure 19.9.
- c.no change
- d.not enough information
Answer
AP Test Prep 19.27 §19.4 source ↗
- a.constant slope
- b.steeper slope
- c.shallower slope
- d.a U-shape
Answer
AP Test Prep 19.29 §19.4 source ↗
- a.A lot; this system is unstable.
- b.Just a little; the isolines are far enough apart that crossing them doesn’t take much work.
- c.None; we’re traveling along an isoline, which requires no work.
- d.There’s not enough information to tell.
Answer
AP Test Prep 19.31 §19.5 source ↗
- a.four times as much
- b.twice as much
- c.the same
- d.half as much
Answer
AP Test Prep 19.33 §19.5 source ↗
- a.it grows proportional to length2
- b.it grows proportional to length
- c.it shrinks proportional to length
- d.it shrinks proportional to length2
Answer
AP Test Prep 19.35 §19.5 source ↗
- a.The distance between the plates
- b.The area
- c.The length of a side
- d.Both the area and the length of a side
| Dimension | Charge(µC) |
| 1.00 | 0.50 |
| 1.10 | 0.61 |
| 1.20 | 0.71 |
| 1.30 | 0.86 |
Answer
AP Test Prep 19.37 §19.7 source ↗
- a.Nothing changes, except now there is a dielectric in the capacitor.
- b.The energy in the system decreases, making it very easy to move the dielectric in.
- c.You have to do work to move the dielectric, increasing the energy in the system.
- d.The reversed polarity destroys the battery.
Answer
AP Test Prep 19.39 §19.7 source ↗
- a.increases, increases
- b.increases, decreases
- c.decreases, increases
- d.decreases, decreases
Answer
AP Test Prep 19.41 §19.7 source ↗
- a.3.98×10-2 J
- b.5.08×1014 J
- c.1.33×10-5 J
- d.1.69×1011 J
Answer
AP Test Prep 19.43 §19.7 source ↗
- a.decreases, decreases
- b.decreases, increases
- c.increases, decreases
- d.increases, increases
Answer
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Problems and answers are adapted from College Physics for AP® Courses 2e by Gregg Wolfe, Erika Gasper, John Stoke, Julie Kretchman, David Anderson and others, OpenStax, and are used under the CC BY-NC-SA 4.0 licence. Access for free at https://openstax.org/books/college-physics-ap-courses-2e/pages/1-connection-for-ap-r-courses. Illustrations: Copyright Rice University, OpenStax, under CC BY-NC-SA 4.0 license. This adaptation is released under the same licence, is non-commercial, and is neither affiliated with nor endorsed by OpenStax or Rice University.