Every problem in the chapter beside the book’s answer, a chapter at a time as you scroll.

Chapter 12: Static Equilibrium and Elasticity

51 problems · 20 figures

Check Your Understanding 12.1 §12.1 source ↗

Solve Example 12.1 by choosing the pivot at the location of the rear axle.

Answer

x = 1.3 m

Check Your Understanding 12.2 §12.1 source ↗

Explain which one of the following situations satisfies both equilibrium conditions: (a) a tennis ball that does not spin as it travels in the air; (b) a pelican that is gliding in the air at a constant velocity at one altitude; or (c) a crankshaft in the engine of a parked car.

Answer

(b), (c)

Check Your Understanding 12.3 §12.2 source ↗

Repeat Example 12.3 using the left end of the meter stick to calculate the torques; that is, by placing the pivot at the left end of the meter stick.

Answer

316.7 g; 5.8 N

Check Your Understanding 12.4 §12.2 source ↗

Repeat Example 12.4 assuming that the forearm is an object of uniform density that weighs 8.896 N.

Answer

T= 1963 N; F= 1732N

Check Your Understanding 12.5 §12.2 source ↗

For the situation described in Example 12.5, determine the values of the coefficient μs of static friction for which the ladder starts slipping, given that β is the angle that the ladder makes with the floor.

Answer

μ s < 0.5cotβ

Check Your Understanding 12.6 §12.2 source ↗

Solve the problem in Example 12.6 by taking the pivot position at the center of mass.

Answer

F → door on A = 100.0N i ^ − 200.0N j ^ ; F → door on B = −100.0N i ^ − 200.0N j ^

Check Your Understanding 12.7 §12.2 source ↗

A 50-kg person stands 1.5 m away from one end of a uniform 6.0-m-long scaffold of mass 70.0 kg. Find the tensions in the two vertical ropes supporting the scaffold.

Figure is a schematic drawing of a woman standing 1.5 m away from one end and 4.5 m away from another end of a scaffold.

Answer

711.0 N; 466.0 N

Check Your Understanding 12.8 §12.2 source ↗

A 400.0-N sign hangs from the end of a uniform strut. The strut is 4.0 m long and weighs 600.0 N. The strut is supported by a hinge at the wall and by a cable whose other end is tied to the wall at a point 3.0 m above the left end of the strut. Find the tension in the supporting cable and the force of the hinge on the strut.

Figure is a schematic drawing of a sign which hangs from the end of a uniform strut. The strut is 4.0 m long and is supported by a 5.0 m long cable tied to the wall at a point 3.0 m above the left end of the strut.

Answer

1167 N; 980 N directed upward at 18° above the horizontal

Check Your Understanding 12.9 §12.3 source ↗

Find the compressive stress and strain at the base of Nelson’s column.

Answer

206.8kPa; 4.6× 10 −5

Check Your Understanding 12.10 §12.3 source ↗

A 2.0-m-long wire stretches 1.0 mm when subjected to a load. What is the tensile strain in the wire?

Answer

5.0 × 10 −4

Check Your Understanding 12.11 §12.3 source ↗

If the normal force acting on each face of a cubical 1.0-m3 piece of steel is changed by 1.0×107N, find the resulting change in the volume of the piece of steel.

Answer

63 mL

Check Your Understanding 12.12 §12.3 source ↗

Explain why the concepts of Young’s modulus and shear modulus do not apply to fluids.

Answer

Fluids have different mechanical properties than those of solids; fluids flow.

12-1 §12.1 source ↗

What can you say about the velocity of a moving body that is in dynamic equilibrium?

Answer

constant

12-3 §12.1 source ↗

What three factors affect the torque created by a force relative to a specific pivot point?

Answer

magnitude and direction of the force, and its lever arm

12-5 §12.1 source ↗

For the next four problems, evaluate the statement as either true or false and explain your answer.

If there is only one external force (or torque) acting on an object, it cannot be in equilibrium.

Answer

True, as the sum of forces cannot be zero in this case unless the force itself is zero.

12-7 §12.1 source ↗

For the next four problems, evaluate the statement as either true or false and explain your answer.

If an odd number of forces act on an object, the object cannot be in equilibrium.

Answer

False, provided forces add to zero as vectors then equilibrium can be achieved.

12-9 §12.1 source ↗

For the next four problems, evaluate the statement as either true or false and explain your answer.

What purpose is served by a long and flexible pole carried by wire-walkers?

Answer

It helps a wire-walker to maintain equilibrium.

12-11 §12.2 source ↗

Show how a spring scale and a simple fulcrum can be used to weigh an object whose weight is larger than the maximum reading on the scale.

Answer

(Proof)

12-13 §12.3 source ↗

Note: Unless stated otherwise, the weights of the wires, rods, and other elements are assumed to be negligible. Elastic moduli of selected materials are given in Table 12.1.

Why can a squirrel jump from a tree branch to the ground and run away undamaged, while a human could break a bone in such a fall?

Table 12.1 Approximate Elastic Moduli for Selected Materials in the book ↗
Material Young’s modulus
×1010Pa
Bulk modulus
×1010Pa
Shear modulus
×1010Pa
Aluminum 7.0 7.5 2.5
Bone (tension) 1.6 0.8 8.0
Bone (compression) 0.9
Brass 9.0 6.0 3.5
Brick 1.5
Concrete 2.0
Copper 11.0 14.0 4.4
Crown glass 6.0 5.0 2.5
Granite 4.5 4.5 2.0
Hair (human) 1.0
Hardwood 1.5 1.0
Iron 21.0 16.0 7.7
Lead 1.6 4.1 0.6
Marble 6.0 7.0 2.0
Nickel 21.0 17.0 7.8
Polystyrene 3.0
Silk 6.0
Spider thread 3.0
Steel 20.0 16.0 7.5
Acetone 0.07
Ethanol 0.09
Glycerin 0.45
Mercury 2.5
Water 0.22

Answer

In contact with the ground, stress in squirrel’s limbs is smaller than stress in human’s limbs.

12-15 §12.3 source ↗

Note: Unless stated otherwise, the weights of the wires, rods, and other elements are assumed to be negligible. Elastic moduli of selected materials are given in Table 12.1.

A thin wire strung between two nails in the wall is used to support a large picture. Is the wire likely to snap if it is strung tightly or if it is strung so that it sags considerably?

Table 12.1 Approximate Elastic Moduli for Selected Materials in the book ↗
Material Young’s modulus
×1010Pa
Bulk modulus
×1010Pa
Shear modulus
×1010Pa
Aluminum 7.0 7.5 2.5
Bone (tension) 1.6 0.8 8.0
Bone (compression) 0.9
Brass 9.0 6.0 3.5
Brick 1.5
Concrete 2.0
Copper 11.0 14.0 4.4
Crown glass 6.0 5.0 2.5
Granite 4.5 4.5 2.0
Hair (human) 1.0
Hardwood 1.5 1.0
Iron 21.0 16.0 7.7
Lead 1.6 4.1 0.6
Marble 6.0 7.0 2.0
Nickel 21.0 17.0 7.8
Polystyrene 3.0
Silk 6.0
Spider thread 3.0
Steel 20.0 16.0 7.5
Acetone 0.07
Ethanol 0.09
Glycerin 0.45
Mercury 2.5
Water 0.22

Answer

tightly

12-17 §12.3 source ↗

Note: Unless stated otherwise, the weights of the wires, rods, and other elements are assumed to be negligible. Elastic moduli of selected materials are given in Table 12.1.

What type of stress are you applying when you press on the ends of a wooden rod? When you pull on its ends?

Table 12.1 Approximate Elastic Moduli for Selected Materials in the book ↗
Material Young’s modulus
×1010Pa
Bulk modulus
×1010Pa
Shear modulus
×1010Pa
Aluminum 7.0 7.5 2.5
Bone (tension) 1.6 0.8 8.0
Bone (compression) 0.9
Brass 9.0 6.0 3.5
Brick 1.5
Concrete 2.0
Copper 11.0 14.0 4.4
Crown glass 6.0 5.0 2.5
Granite 4.5 4.5 2.0
Hair (human) 1.0
Hardwood 1.5 1.0
Iron 21.0 16.0 7.7
Lead 1.6 4.1 0.6
Marble 6.0 7.0 2.0
Nickel 21.0 17.0 7.8
Polystyrene 3.0
Silk 6.0
Spider thread 3.0
Steel 20.0 16.0 7.5
Acetone 0.07
Ethanol 0.09
Glycerin 0.45
Mercury 2.5
Water 0.22

Answer

compressive; tensile

12-19 §12.3 source ↗

Note: Unless stated otherwise, the weights of the wires, rods, and other elements are assumed to be negligible. Elastic moduli of selected materials are given in Table 12.1.

Can Young’s modulus have a negative value? What about the bulk modulus?

Table 12.1 Approximate Elastic Moduli for Selected Materials in the book ↗
Material Young’s modulus
×1010Pa
Bulk modulus
×1010Pa
Shear modulus
×1010Pa
Aluminum 7.0 7.5 2.5
Bone (tension) 1.6 0.8 8.0
Bone (compression) 0.9
Brass 9.0 6.0 3.5
Brick 1.5
Concrete 2.0
Copper 11.0 14.0 4.4
Crown glass 6.0 5.0 2.5
Granite 4.5 4.5 2.0
Hair (human) 1.0
Hardwood 1.5 1.0
Iron 21.0 16.0 7.7
Lead 1.6 4.1 0.6
Marble 6.0 7.0 2.0
Nickel 21.0 17.0 7.8
Polystyrene 3.0
Silk 6.0
Spider thread 3.0
Steel 20.0 16.0 7.5
Acetone 0.07
Ethanol 0.09
Glycerin 0.45
Mercury 2.5
Water 0.22

Answer

no

12-23 §12.4 source ↗

Note: Unless stated otherwise, the weights of the wires, rods, and other elements are assumed to be negligible. Elastic moduli of selected materials are given in Table 12.1.

Steel rods are commonly placed in concrete before it sets. What is the purpose of these rods?

Table 12.1 Approximate Elastic Moduli for Selected Materials in the book ↗
Material Young’s modulus
×1010Pa
Bulk modulus
×1010Pa
Shear modulus
×1010Pa
Aluminum 7.0 7.5 2.5
Bone (tension) 1.6 0.8 8.0
Bone (compression) 0.9
Brass 9.0 6.0 3.5
Brick 1.5
Concrete 2.0
Copper 11.0 14.0 4.4
Crown glass 6.0 5.0 2.5
Granite 4.5 4.5 2.0
Hair (human) 1.0
Hardwood 1.5 1.0
Iron 21.0 16.0 7.7
Lead 1.6 4.1 0.6
Marble 6.0 7.0 2.0
Nickel 21.0 17.0 7.8
Polystyrene 3.0
Silk 6.0
Spider thread 3.0
Steel 20.0 16.0 7.5
Acetone 0.07
Ethanol 0.09
Glycerin 0.45
Mercury 2.5
Water 0.22

Answer

It acts as “reinforcement,” increasing a range of strain values before the structure reaches its breaking point.

12-25 §12.1 source ↗

When opening a door, you push on it perpendicularly with a force of 55.0 N at a distance of 0.850 m from the hinges. What torque are you exerting relative to the hinges?

Answer

46.8 N · m

12-27 §12.1 source ↗

What force must be applied at point P to keep the structure shown in equilibrium? The weight of the structure is negligible.

Figure shows the distribution of forces applied to point P. Force of 2000 N, two meters to the left of the point P, moves it downwards. Force of 4000 N, two meters to the right and one meter above of the point P, moves it to the right.

Answer

4,472 N, 153.4°

12-29 §12.1 source ↗

Two children push on opposite sides of a door during play. Both push horizontally and perpendicular to the door. One child pushes with a force of 17.5 N at a distance of 0.600 m from the hinges, and the second child pushes at a distance of 0.450 m. What force must the second child exert to keep the door from moving? Assume friction is negligible.

Answer

23.3 N

12-31 §12.1 source ↗

The uniform seesaw is balanced at its center of mass, as seen below. The smaller boy on the right has a mass of 40.0 kg. What is the mass of his friend?

Figure is a schematic drawing of two boys on the seesaw. One boy sits two meters from the edge of the seesaw and two meters from the center. Another boys sits at the opposite edge of the seesaw, four meters from the center.

Answer

80.0 kg

12-33 §12.2 source ↗

The uniform seesaw shown below is balanced on a fulcrum located 3.0 m from the left end. The smaller boy on the right has a mass of 40 kg and the bigger boy on the left has a mass 80 kg. What is the mass of the board?

Figure is a schematic drawing of two boys on the seesaw. One boy sits on the edge of the seesaw three meters from the center. Another boys sits at the opposite edge of the seesaw, five meters from the center.

Answer

40 kg

12-35 §12.2 source ↗

A uniform 40.0-kg scaffold of length 6.0 m is supported by two light cables, as shown below. An 80.0-kg painter stands 1.0 m from the left end of the scaffold, and his painting equipment is 1.5 m from the right end. If the tension in the left cable is twice that in the right cable, find the tensions in the cables and the mass of the equipment.

Figure is a schematic drawing of a man standing at the left side and the bucket placed at the right side of a scaffold.

Answer

right cable, 444.3 N; left cable, 888.5 N; weight of equipment 156.8 N; 16.0 kg

12-37 §12.2 source ↗

To get up on the roof, a person (mass 70.0 kg) places a 6.00-m aluminum ladder (mass 10.0 kg) against the house on a concrete pad with the base of the ladder 2.00 m from the house. The ladder rests against a plastic rain gutter, which we can assume to be frictionless. The center of mass of the ladder is 2.00 m from the bottom. The person is standing 3.00 m from the bottom. Find the normal reaction and friction forces on the ladder at its base.

Answer

784 N, 132.8 N

12-39 §12.2 source ↗

The forearm shown below is positioned at an angle θ with respect to the upper arm, and a 5.0-kg mass is held in the hand. The total mass of the forearm and hand is 3.0 kg, and their center of mass is 15.0 cm from the elbow. (a) What is the magnitude of the force that the biceps muscle exerts on the forearm for θ=60°? (b) What is the magnitude of the force on the elbow joint for the same angle? (c) How do these forces depend on the angle θ?

Figure is a schematic drawing of a forearm rotated around the elbow. A 5 kilogram ball is held in the palm. The distance between the elbow and the ball is 35 centimeters. The distance between the elbow and the biceps muscle, which causes a torque around the elbow, is 4 centimeters. Forearm forms a theta angle with the upper arm.Figure is a schematic drawing of a forearm rotated around the elbow. A 5 kilogram ball is held in the palm. The distance between the elbow and the ball is 35 centimeters. The distance between the elbow and the biceps muscle, which causes a torque around the elbow, is 4 centimeters. Forearm forms a theta angle with the upper arm.

Answer

a. 539 N; b. 461 N; c. do not depend on the angle

12-41 §12.2 source ↗

The uniform boom shown below weighs 700 N, and the object hanging from its right end weighs 400 N. The boom is supported by a light cable and by a hinge at the wall. Calculate the tension in the cable and the force on the hinge on the boom. Does the force on the hinge act along the boom?

Figure is a schematic drawing of a 400 N weight that is by a cable and by a hinge at the wall. Hinge forms a 20 degree angle with the line perpendicular to the wall. Cable forms a 45 degree angle with the line perpendicular to the wall.

Answer

tension 778 N; at hinge 778 N at 45° above the horizontal; no

12-43 §12.2 source ↗

A uniform trapdoor shown below is 1.0 m by 1.5 m and weighs 300 N. It is supported by a single hinge (H), and by a light rope tied between the middle of the door and the floor. The door is held at the position shown, where its slab makes a 30° angle with the horizontal floor and the rope makes a 20° angle with the floor. Find the tension in the rope and the force at the hinge.

Figure is a schematic drawing of a trapdoor that is 1.0 m by 1.5 m. Door is supported by a single hinge labeled H, and by a light rope tied between the middle of the door and the floor. The door makes a 30 degree angle with the floor and the rope makes a 20 degree angle with the floor.Figure is a schematic drawing of a trapdoor that is 1.0 m by 1.5 m. Door is supported by a single hinge labeled H, and by a light rope tied between the middle of the door and the floor. The door makes a 30 degree angle with the floor and the rope makes a 20 degree angle with the floor.

Answer

1500 N; 1620 N at 30°

12-45 §12.3 source ↗

The “lead” in pencils is a graphite composition with a Young’s modulus of approximately 1.0×109N/m2. Calculate the change in length of the lead in an automatic pencil if you tap it straight into the pencil with a force of 4.0 N. The lead is 0.50 mm in diameter and 60 mm long.

Answer

1.2 mm

12-47 §12.3 source ↗

By how much does a 65.0-kg mountain climber stretch her 0.800-cm diameter nylon rope when she hangs 35.0 m below a rock outcropping? (For nylon, Y= 1.35×109Pa.)

Answer

32.9 cm

12-49 §12.3 source ↗

A farmer making grape juice fills a glass bottle to the brim and caps it tightly. The juice expands more than the glass when it warms up, in such a way that the volume increases by 0.20%. Calculate the force exerted by the juice per square centimeter if its bulk modulus is 1.8×109N/m2, assuming the bottle does not break.

Answer

3.6×102N/cm2

12-51 §12.3 source ↗

A vertebra is subjected to a shearing force of 500.0 N. Find the shear deformation, taking the vertebra to be a cylinder 3.00 cm high and 4.00 cm in diameter.

Answer

11.9 μm

12-53 §12.3 source ↗

A 20.0-m-tall hollow aluminum flagpole is equivalent in strength to a solid cylinder 4.00 cm in diameter. A strong wind bends the pole as much as a horizontal 900.0-N force on the top would do. How far to the side does the top of the pole flex?

Answer

0.57 mm

12-55 §12.3 source ↗

As an oil well is drilled, each new section of drill pipe supports its own weight and the weight of the pipe and the drill bit beneath it. Calculate the stretch in a new 6.00-m-long steel pipe that supports a 100-kg drill bit and a 3.00-km length of pipe with a linear mass density of 20.0 kg/m. Treat the pipe as a solid cylinder with a 5.00-cm diameter.

Answer

8.59 mm

12-57 §12.3 source ↗

A 90-kg mountain climber hangs from a nylon rope and stretches it by 25.0 cm. If the rope was originally 30.0 m long and its diameter is 1.0 cm, what is Young’s modulus for the nylon?

Answer

1.35 × 10 9 Pa

12-59 §12.3 source ↗

A copper wire is 1.0 m long and its diameter is 1.0 mm. If the wire hangs vertically, how much weight must be added to its free end in order to stretch it 3.0 mm?

Answer

259.0 N

12-61 §12.3 source ↗

The bulk modulus of a material is 1.0×1011N/m2. What fractional change in volume does a piece of this material undergo when it is subjected to a bulk stress increase of 107N/m2? Assume that the force is applied uniformly over the surface.

Answer

0.01%

12-63 §12.3 source ↗

During a walk on a rope, a tightrope walker creates a tension of 3.94×103N in a wire that is stretched between two supporting poles that are 15.0 m apart. The wire has a diameter of 0.50 cm when it is not stretched. When the walker is on the wire in the middle between the poles the wire makes an angle of 5.0° below the horizontal. How much does this tension stretch the steel wire when the walker is this position?

Answer

1.44 cm

12-65 §12.3 source ↗

Normal forces are applied uniformly over the surface of a spherical volume of water whose radius is 20.0 cm. If the pressure on the surface is increased by 200 MPa, by how much does the radius of the sphere decrease?

Answer

0.63 cm

12-69 §12.AP source ↗

The coefficient of static friction between the rubber eraser of the pencil and the tabletop is μs=0.80. If the force F→ is applied along the axis of the pencil, as shown below, what is the minimum angle at which the pencil can stand without slipping? Ignore the weight of the pencil.

Figure shows a pencil that rests against a corner. The eraser end touches a rough horizontal floor. Angle between pencil and ground is Theta.

Answer

tan −1 (1/ μ s )= 51.3°

12-71 §12.AP source ↗

A uniform 4.0-m plank weighing 200.0 N rests against the corner of a wall, as shown below. There is no friction at the point where the plank meets the corner. (a) Find the forces that the corner and the floor exert on the plank. (b) What is the minimum coefficient of static friction between the floor and the plank to prevent the plank from slipping?

Figure shows a uniform plank that rests against a corner the corner of a wall. Part of the plank from the floor to the corner of the wall is 3.0 m long, 1.0 m long part of plank is above the wall. Distance between the part of the plank that touches the ground and the corner of the wall is 1.5 m.

Answer

a. at corner 66.7 N at 30° with the horizontal; at floor 177 N at 109° with the horizontal; b. μs=0.346

12-73 §12.AP source ↗

Two thin rods, one made of steel and the other of aluminum, are joined end to end. Each rod is 2.0 m long and has cross-sectional area 9.1mm2. If a 10,000-N tensile force is applied at each end of the combination, find: (a) stress in each rod; (b) strain in each rod; and, (c) elongation of each rod.

Answer

a. 1.10×109N/m2; b. 5.5×10−3; c. 11.0 mm, 31.4 mm

12-75 §12.CP source ↗

A horizontal force F→ is applied to a uniform sphere in direction exact toward the center of the sphere, as shown below. Find the magnitude of this force so that the sphere remains in static equilibrium. What is the frictional force of the incline on the sphere?

Figure shows a sphere of radius R and mass M that placed at the side of the triangle forming angle Theta with the ground. Force F is applied to the sphere.Figure shows a sphere of radius R and mass M that placed at the side of the triangle forming angle Theta with the ground. Force F is applied to the sphere.

Answer

F= Mgtanθ; f= 0

12-77 §12.CP source ↗

Two wheels A and B with weights w and 2w, respectively, are connected by a uniform rod with weight w/2, as shown below. The wheels are free to roll on the sloped surfaces. Determine the angle that the rod forms with the horizontal when the system is in equilibrium. Hint: There are five forces acting on the rod, which is two weights of the wheels, two normal reaction forces at points where the wheels make contacts with the wedge, and the weight of the rod.

Figure shows the wheels A and B connected by the rod and located at the opposite side of the right angle triangle. Side at which wheel A is located forms a 60 degree angle with the line parallel to the ground. Side at which wheel B is located forms a 30 degree angle with the line parallel to the ground.Figure shows the wheels A and B connected by the rod and located at the opposite side of the right angle triangle. Side at which wheel A is located forms a 60 degree angle with the line parallel to the ground. Side at which wheel B is located forms a 30 degree angle with the line parallel to the ground.

Answer

with the horizontal, θ=42.2°; α=17.8° with the steeper side of the wedge

12-79 §12.CP source ↗

In order to lift a shovelful of dirt, a gardener pushes downward on the end of the shovel and pulls upward at distance l2 from the end, as shown below. The weight of the shovel is mg→ and acts at the point of application of F→2. Calculate the magnitudes of the forces F→1 and F→2 as functions of l1, l2, mg, and the weight W of the load. Why do your answers not depend on the angle θ that the shovel makes with the horizontal?

Figure shows a gardener lifting a shovel full of ground with both hands. Force F1 is applied to the back hand. Force F2 is applied to front hand. Force w is applied to the front of shovel with ground. Distance between the back hand and front of shovel is l1. Distance between the back and front hands is l2. Angle between the shovel and line parallel to the ground is theta.

Answer

W( l 1 / l 2 −1); W l 1 / l 2 + mg

12-81 §12.CP source ↗

The pole shown below is at a 90.0° bend in a power line and is therefore subjected to more shear force than poles in straight parts of the line. The tension in each line is 4.00×104N, at the angles shown. The pole is 15.0 m tall, has an 18.0 cm diameter, and can be considered to have half the strength of hardwood. (a) Calculate the compression of the pole. (b) Find how much it bends and in what direction. (c) Find the tension in a guy wire used to keep the pole straight if it is attached to the top of the pole at an angle of 30.0° with the vertical. The guy wire is in the opposite direction of the bend.

Figure shows a pole to which two forces T and force Tgw are applied. There is a 90 degree angle between two T forces. There is an 80 degree angle between the plane T forces are applied anf the pole. There is a 30 degree angle between Tgw and the pole.Figure shows a pole to which two forces T and force Tgw are applied. There is a 90 degree angle between two T forces. There is an 80 degree angle between the plane T forces are applied anf the pole. There is a 30 degree angle between Tgw and the pole.

Answer

a. 1.1 mm; b. 6.6 mm to the right; c. 1.11×105N

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Problems and answers are adapted from University Physics Volume 1 by Samuel J. Ling, Jeff Sanny and William Moebs, OpenStax, and are used under the CC BY-NC-SA 4.0 licence. Access for free at https://openstax.org/books/university-physics-volume-1/pages/1-introduction. Illustrations: Copyright Rice University, OpenStax, under CC BY-NC-SA 4.0 license. This adaptation is released under the same licence, is non-commercial, and is neither affiliated with nor endorsed by OpenStax or Rice University.